Answers
B = 36%
C = 16/25
D = 80%
M = 11/50
R = 45%
T = 14/25
X = 7/10
Those are all the answers that I got, I’m NOT saying all of them are correct! I hope this helps tho- :)
Related Questions
Which graph is a histogram?
Answers
Answer: The second one.
Edge. 22
How many 5 digit numbers can be formed using all the digits with repetition the digits being 0,1,2,3,4?
Answers
The number of 5 digit numbers that can be formed is 3125
How to determine the number of 5 digit numbers that can be formed?From the question, we have the following parameters that can be used in our computation:
Digits = 0, 1, 2, 3, 4
These digits can be repeated
So, we have
n = 5 i.e. the count of digits in 0, 1, 2, 3, 4
The number of 5 digit numbers is then calculated as
Count = n⁵
So, we have
Count = 5⁵
Evaluate
Count = 3125
Hence, the count is 3125
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The function f(x) = -√x is shown on the graph.
714
6
16
5
4
3-
2+
1-
7-6-5-4-3-2-1₁ 1 2 3 4
-2+
2 3 4
-3-
4-
-5
5
-6
5 6 7x
Which statement is correct?
O The domain of the function is all real numbers less
than or equal to -1.
O The range of the function is all real numbers greater
than or equal to 0.
O The range of the function is all real numbers less
than or equal to 0.
O The domain of the function is all real numbers less
than or equal to 0.
Answers
Answer:
(c) The range of the function is all real numbers less than or equal to 0
Step-by-step explanation:
You want the true statement describing the domain or range of f(x) = -√x.
DomainThe domain of the function is the set of values x for which the function is defined. The square root is only defined for non-negative arguments:
x ≥ 0 . . . . . . not an answer choice
RangeThe range is of the function is the set of values f(x) that the function can produce. The square root function can produce any non-negative value, so the opposite of the square root function will produce any non-positive value:
f(x) ≤ 0 . . . . . the range is real numbers less than or equal to zero
7. Which is the following formula solved for a?
x = b + vt + ¹⁄2at²
a. x − b - vt = at²
2
b. a = x − b + vt + ½t²
-
c. a =
d. a =
2(x-b-vt)
2
t
2
b+vt+t²
1/2
Please help meeeee!!!!
Answers
Answer:
c.) a = (2(x-b-vy))/t^2
Step-by-step explanation:
Manipulate the given equation to isolate a on the left side:
x=b+vy+(1/2)at^2
x=b+vy+(1/2)at^2
(1/2)at^2 = x-b-vy
at^2 = 2(x-b-vy)
a = (2(x-b-vy))/t^2
What is the graph of y² 4x?
Answers
The graph of y² 4x is a parabola with vertex (0,0) and x- and y-intercepts (0,0). The graph opens downward and can be written as y=4x².
The graph of y² 4x is a parabola in the shape of a "U" that opens downward. This parabola can be written in the standard form of y=a(x-h)²+k. In this case, a=4, h=0, and k=0. This means that the equation for the graph of y² 4x is y=4x².
To calculate the graph, we must first determine the vertex, which is the point of the parabola that has the maximum or minimum value. To do this, we use the formula for the vertex of a parabola, which is (h,k)=(-b/2a,f(h)). With a=4 and b=0, the vertex of the parabola is (0,0).
We can then calculate the x-intercepts, which are the points at which the graph of y² 4x crosses the x-axis. To do this, we set y=0 in the equation y=4x² and solve for x. This gives us x=±√(0/4) or x=0. This means that the x-intercepts of the graph of y² 4x are (0,0).
Finally, we can calculate the y-intercept, which is the point at which the graph of y² 4x crosses the y-axis. To do this, we set x=0 in the equation y=4x² and solve for y. This gives us y=0. This means that the y-intercept of the graph of y² 4x is (0,0).
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a spring with spring constant 2.5×104 n/m has a 1.4-kg cart at its end.
Answers
The frequency of oscillation for the spring with the constant value of 2.5×10⁴ is 0.0012
The term frequency is defined as the number of waves that pass a fixed point in unit time and it is also known as the number of cycles or vibrations undergone during one unit of time by a body in periodic motion.
Here we have given the following values,
Spring constant = 2.5 × 10⁴
And the weight of the cart = 1.4 kg
Now, we have calculated the value of the frequency of oscillation as,
=> v = 1/T
Here T refers the time period.
Where it can be rewritten as,
=> 1/2π x √(k/m)
Now, we have to apply the values on it then we get
=> 1/2π x √(1.4/2.5 x 10⁴)
=> 0.1592 x 0.0074
=> 0.0012
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literally anybody help me please!! all you have to do is find the slope on the graph. PLEASE HELP ME ASAP!!
Answers
Answer:
m = 3
Step-by-step explanation:
rise over run
Answer:
Hope it helps you ...........
What are the 4 forms of quadratic equations?
Answers
The four methods of solving a quadratic equation are factoring, using the square roots, completing the square and the quadratic formula.
Use the formula to solve the problem. Area of a trapezoid = (1/2)(a + b)h, where a and b are the lengths of the two parallel sides and h is the altitude. The area of a trapezoid is 375 m2. If the two parallel sides are 20 m and 30 m, respectively, what is the altitude of the trapezoid? altitude, h = m.
Answers
Answer:
h = 1.25m
Step-by-step explanation:
a=20m, b= 30m
Area = (½) (a+b) (h)
375= ½ (20+30) h
375= 300h
300h = 375
h= 375÷300
= 1.25m
When a truckload of oranges arrives at a packing plant, a random sample of 125 is selected and examined. The whole truckload will be rejected if more than 8% of the sample is unsatisfactory. Suppose that in fact 10% of the oranges on the truck do not meet the desired standard. What is the probability that the shipment will be rejected?.
Answers
The probability that the shipment will be rejected is 0.724.
Given :
Since we have given that
n = 125
p' = 8 % = 0.08
p = 10 % = 0.10
Test statistic value :
z = p' - p / [tex]\sqrt{p(1-p)/n}[/tex]
= 0.08 - 0.10 / [tex]\sqrt{0.10 * 0.90 / 125}[/tex]
= -0.75
p value at z = -0.75
p = 0.226
What is probability ?
Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.
Probability of shipment will be rejected = 1 - 0.226
= 0.724
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What are the types of expression?
Answers
There is major 3 types of expression. Numerical expression, algebraic expression and fractional expression.
What is numerical expression?This expression contains only two or more numbers along with symbols or operator. There is no variable present.
such as 226÷113+2×22-11
or (44÷88) ×100%
the above sign is percentage sign we can determine a percent value
or∛ (64)
the above sign represents a cubic root
we get the value 4
What is fractional expression?The expression having two or more fractional terms along with symbols are called fractional expression. There are numerator and denominator from which we need to determine a common denominator to obtain a result.
such as, 4/5+3/4
we have 2 different denominators 5 and 4. we need to find a common denominator by multiplying both. 5x4
20
In the next, common denominator is divided by each denominator and the result is multiplied with each numerator.
(4×4+3×5)/20
hence, the result is 31/20
What is algebraic expression?
The expression contains both variables and numbers along with symbols are called algebraic expression. The algebraic expression having equal sign are termed as equation. Tha main purpose of using equation is to determine unknown value.
Algebraic expression are different types such as linear expression
2x+3-4y
2 and 4 are coefficient, 3 is constant
Polynomial expression as example 2x²-3y+4
Besides, we have other algebraic expression such as 3y+4 or x/4+y/3
and so on.
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2)
Two triangles on the coordinate plane are shown below.
C
Part A. What transformation (s) could be applied to map
triangle EBD onto triangle CBA?
Part B. Once the transformation is completed, how can you
determine if the two triangles are congruent?
Answers
Two triangles are congruent because the sides of two triangles and angles are congruent and the transformation applied to map triangle EBD onto triangle CBA is rotation of 90 degrees.
What is Graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points.
There are two triangles in the coordinate plane.
Triangle ABC and triangle EBD are in plane.
We need to find the transformation applied to EBD onto triangle CBA.
Graph transformation is the process by which an existing graph, or graphed equation, is modified to produce a variation of the proceeding graph.
The triangle EBD undergoes a rotation of 90 degrees in clockwise direction to get triangle CBA.
The two triangles are congruent because the sides of two triangles and angles are congruent. So we conclude that the two triangles are congruent.
Hence, rotation of 90 degrees is the transformation (s) could be applied to map triangle EBD onto triangle CBA.
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What is not a valid triangle congruence theorem?
Answers
The theorem that is a valid triangle congruence theorem is the: ASA
What is a Triangle Congruence Theorem?A triangle congruence theorem is a set of conditions that must be met by a set of triangles before both triangles can be said to be congruent to each other.
Some of the valid triangle congruence theorem are:
SAS: which means the triangles must have two set of congruent sides and a pair of congruent included angles.ASA: which means the triangles must have two set of congruent angles and a pair of congruent included sides.SSS: which means the triangles must have three set of corresponding congruent sides.Therefore, from the option given, the only valid triangle congruence theorem is: ASA.
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Complete Question:
Which of the following is a valid triangle congruence theorem?
AAA
SSA
ASA
none of the above
joe gets a new pair of running shoes. if he runs 1 mile each day in week 1 and adds 1 10 mile to his daily routine each week, what is the total mileage on joe's shoes after week 21?
Answers
The total mileage on Joe's shoes after the 21 weeks is 2,457 miles.
What is the total mileage of joe's shoes?The total mileage of Joe's shoes is the sum of all the distance travelled by Joe within the given time of period of 21 weeks.
The distance travelled by Joe in 1 week is calculated as follows;
1 week = 7 daysnumber of miles in a day = 1 miledistance travelled by Joe in 1 week = 1 mile/day x 7 days = 7 miles
The distance travelled by Joe in 21 weeks is calculated as follows;
distance travelled in 21 weeks = ( 7 miles / week ) x ( 21 weeks )
distance travelled in 21 weeks = 147 miles
the number of additional mile added each week = 110 mile
for 21 weeks = 21 x 110 mile = 2,310 miles
The total mileage on Joe's shoes after the 21 weeks is calculated as follows;
total mileage = 2,310 miles + 147 miles
total mileage = 2,457 miles
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Write an equation in slope-intercept form of the line that passes through the given points. $x$ $y$ $-4$ $9$ $-2$ $4$ $0$ $-1$ $2$ $-6$ $y=$
Answers
The equation of the line that passes through the given points in the slope-intercept form is y = (-5/2)x - 1
Writing equation of a lineFrom the question, we are to determine the equation of the line that passes through the given points
We will pick two value pairs from the table
Picking (-4, 9) and (-2, 4)
Using the formula,
(y - y₁) / (x - x₁) = (y₂ - y₁) / (x₂ - x₁)
Then,
(y - 9) / (x - (-4)) = (4 - 9) / (-2 - (-4))
Simplify
(y - 9)/(x + 4) = -5/(-2 + 4)
(y - 9)/(x + 4) = -5/2
Cross multiply
2(y - 9) = -5(x + 4)
2y - 18 = -5x - 20
2y = -5x -20 + 18
2y = -5x - 2
Divide through by 2
y = (-5/2)x - 1
Hence, the equation is y = (-5/2)x - 1
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How many cans of paint are needed to cover an area?
Answers
We need 6 cans of paint are needed to cover an area of 2 200 square units.
In this question we need to find the number of cans of paint needed to cover an area of 2 200 square units.
We have been given one can of paint covers an area of 400 square units.
Let x cans of paint are needed to cover an area of 2200 square units..
1 can = 400 square units
x cans = 2200 square units
Bu Unitary method,
x = 2200/400
x = 22/4
x = 11/2
x = 5.5
x ≈ 6
Therefore, six cans of paint are needed to cover an area of 2 200 square units.
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A complete question is:
How many cans of paint are needed to cover an area of 2 200 square units if one can of paint covers an area of 400 square units?
Micah's gym is moving into a bigger space, where he can have more stationary bicycles and treadmills. Micah needs both stationary bicycles and treadmills in his gym. Let x be the number of bicycles and y be the number of treadmills. The number of new bicycles must be more than 13 times the number of new treadmills. Each bicycle costs $340 and each treadmill costs $670. He must spend less than $5,650. Select all of the constraints for this situation.
Answers
The constraints for this situation are x>0, y>0, 340x + 670y < 5650 and x>1/3y
Let the number of bicycles = x
and the number of treadmills = y
Since the number of new bicycles must be more than 1/3 times of the new treadmills.
Inequality representing the statement will be,
x>1/3y
Each bicycle costs $340 and each treadmill costs $670.He must spend less than $5650,
Inequality will be,
340x + 670y < 5650
And the number of bicycles and treadmills should be greater than 0.
x > 0
y > 0
Therefore, constraints for this situation are, x>0, y>0, 340x + 670y < 5650 and x>1/3y
(Refer to the image attached for the complete question)
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Let the number of bicycles = x
and the number of treadmills = y
Inequality representing the statement will be,
x>1/3y
Each bicycle costs $340 and each treadmill costs $670.He must spend less than $5650,
Inequality will be,
340x + 670y < 5650
And the number of bicycles and treadmills should be greater than 0.
x > 0
y > 0
Therefore, constraints for this situation are, x>0, y>0, 340x + 670y < 5650 and x>1/3y
What is the factor of x³ 2x² 5x 6?
Answers
The factors of x³ 2x² 5x 6 are two binomials. The first binomial is x² + 2, and the second binomial is x + 3. These two binomials can be multiplied together to get the original equation, x³ 2x² 5x 6.
To find the factors of x³ 2x² 5x 6, we need to use the factorization process. This involves breaking down the equation into its prime factors. First, we need to factor out the greatest common factor (GCF) from the equation. The greatest common factor of x³ 2x² 5x 6 is x, so we can factor out x to get x² 2x 5 6. Now, we can use the difference of squares formula to factor out the remaining terms. The difference of squares is (a + b)(a - b). We can use this formula with 2x and 5 to get (2x + 5)(2x - 5). This leaves us with the two binomials (x² + 2)(x + 3). These two binomials can be multiplied together to get the original equation, x³ 2x² 5x 6.
x³ 2x² 5x 6 = (x)(x² 2x 5 6)
= (x)(2x + 5)(2x - 5)
= (x)(x² + 2)(x + 3)
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Determine whether the pair of lines is parallel, perpendicular, or neither.
Answers
Answer:
Neither
Step-by-step explanation:
It is not opposite to each other (perpendicular) or the same slope (parallel)
A circular clock has a minute hand that rotates from the center of the clock. This distance from the point on the minute hand from where it rotates to its end is 12 centimeters. Find how far the end of the minute hand moves in 20 minutes.
Answers
The distance the 12 centimeters minute hand moves in 20 minutes obtained by converting the angular motion to translational motion is about 25.133 centimeters
What is an angular motion?Angular motion is the circular motion of an object around a point or location.
The complete 360° rotation of the minute hand = 60 minutes
Therefore;
60 minutes is equivalent to 360°
1 minute is equivalent to 360°/60 = 6°
20 minutes is equivalent to 20 × 6° = 120°
The circular path motion following an angular rotation of angle theta = Radius × Theta
Where, theta is in radians
The radius of the minute hand = 12 centimeters
360° = 2•π radians
120° = 360°/3 = (2•π/3) radians
The distance moved by the the minute hand = 12 cm × (2•π/3) radians = 8•π cm
8•π cm ≈ 25.133 cm
The distance the minute hand moves in 20 minutes is about 25.133 cm
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Write y=-5/8x+3 in standard form using integers.
Answers
Answer:
5x + 8y = 24
Step-by-step explanation:
y = [tex]\frac{-5}{8}[/tex]x + 3 Add [tex]\frac{5}{8}[/tex]x to both sides
[tex]\frac{5}{8}[/tex]x + y = [tex]\frac{-5}{8}[/tex]x + [tex]\frac{5}{8}[/tex]x + 3
[tex]\frac{5}{8}[/tex]x + y = 3 Multiply all the way through by 8 to clear the fraction
[tex](\frac{8}{1})[/tex][tex](\frac{5}{8})[/tex]x + (8)y= (8)(3)
5x + 8y = 24
In 1990, the postal rate was 25 cents for the first ounce and 20 cents for each additional ounce or part of an ounce. What did it cost to mail a package that weighed 6.8 ounces?
Answers
Answer:
$1.41
Step-by-step explanation:
0.20 * 5.8 ounces = $1.16
0.25 * 1.16 = $1.41
The mail weighing 6.8 ounces cost 145 cents
What is the unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
Given here, the first ounce cost 25 cents and all subsequent ounces or parts of an ounce cost 20 cents each
therefore cost of the first ounce = 25
and cost of 5.8 ounces = 20× 6
= 120 cents
thus total cost is 120+25 =145 cents
Hence, the total cost to mail a package is 145 cents
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If lambda belong to R and the domain of f(x) = log lambda x-2/x i [1,2) union (2,3], then lambda belong to
Answers
the value of |x-2| lies between 0 and 1 then λ also lies between 0 and 1. Then λ belongs to (0,1).
In the given question, if λ∈R and the domain of f(x) = [tex]\sqrt{\frac{log_{\lambda}|x-2|}{|x|}}[/tex] is [1,2)∪(2,3], then λ belong to
The given function is
f(x) = [tex]\sqrt{\frac{log_{\lambda}|x-2|}{|x|}}[/tex]
The function is belong in between [1,2)∪(2,3]. So
|x-2| ≠ 0 and |x| > 0
x ≠ 2 and x > 0
Since the value of x can not be equal to 2 and x value is always greater than 0. So
[tex]log_{\lambda}|x-2|\geqslant 0[/tex]
The value of |x-2| should be lies between 0 and 1 because x cannot be equal to 2 and greater than 1.
So 0< |x-2| < 1
If the value of |x-2| lies between 0 and 1 then λ also lies between 0 and 1.
Hence, 0 < λ < 1.
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Does I 2 equal 1 or?
Answers
The value of "i" squared results in:
(-1) = i²
What are numeric sets?Numerical sets are groupings of numerical values that have a particularity in common, they can be integers, decimals, fractions, among others.
Complex NumbersAmong the numerical sets there is one that we call complex numbers, which include values that are not real, such as "i" a letter that denotes that it is an imaginary number.
In function to this type of numbers there is a particular value and it is the "i" which is the result of the square root of -1, then we have:
√(-1) = i[√(-1)]² = i²(-1) = i²
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Suppose that ΔFAR is similar to ΔSUN. : Identify the corresponding sides.
Answers
FA is the corresponding side to SU
AR is the corresponding side to UN
RF is the corresponding side to NS
What are Corresponding Sides ?
Corresponding sides are the sides that are in the same position in any different 2-dimensional shapes. For any two polygons to be congruent, they must have exactly the same shape and size. This means that all their interior angles and their corresponding sides must be the same measure. For any two polygons to be similar, the ratios of the lengths of each pair of corresponding sides must be equal.
In the below-given images, the two triangles are congruent and their corresponding sides are color-coded.
In the above two triangles ABC and XYZ,
AB is the corresponding side to XY
BC is the corresponding side to YZ
CA is the corresponding side to ZX
Similarly , if ΔFAR is similar to ΔSUN
then ,
FA is the corresponding side to SU
AR is the corresponding side to UN
RF is the corresponding side to NS
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How do you know if there is no solution or infinite solutions?
Answers
There are countless possible solutions to some equations. In these equations, the equation is true regardless of the value given to the variable. If we try to solve an equation and receive a variable or a number equal to itself, there are infinitely many solutions to the equation.
Single-solution equations:
Some equations only have one precise solution. The variable in these equations can only take on one value in order for the equation to be true. When you solve an equation and the result is a variable equal to a number, you know that the equation only has one solution.
Example: For x, find the solution to the equation 6x-3=21.
6x \s= 24
To both sides, add 3.
x \s= 4
Subtract 6 from both sides.
For a single value of the variable, x=4, the equation is true. Consequently, there is only one solution to the equation 6x-3=21
Non-solvable equations:
There are certain equations with no answers. These equations don't have a value for the variable that would make them true. If you attempt to solve an equation and the result is false, the problem has no solutions.
Example: Solve the equation 4x+12=2x+12+2x.
4x+12
= 2x+12+2x
4x+12
= 4x+12 Combine like terms 2x and 2x.
12
= 12 Subtract 4x from both sides.
Since the equation 12=12 is always true, you can change the value of x to make it true. Therefore, 4x+12=2x+12+2x has an endless number of solutions.
Equations that have infinitely many solutions:
The number of solutions to some equations is limitless. When a variable is used in these equations, any value makes the equation true. If you attempt to solve an equation and it yields a variable or value that is equal to itself, then the equation has an endless number of solutions.
Solve the equation 4x+12=2x+12+2x.
4x+12
= 2x+12+2x
4x+12
= 4x+12 Combine like terms 2x and 2x.
12
= 12 Subtract 4x from both sides
Since the equation 12=12 is always true, you can change the value of x to make it true. Therefore, 4x+12=2x+12+2x has an endless number of solutions.
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How old should a kid count to 10?
Answers
Children who are 4 years old frequently count up to 1,0and have mastered skip counting. There are many chances to deepen their comprehension at home using basic math games.
What is Counting?
In order to calculate the size of a set, or the number of items in a finite set, one must count. Calculating the amount or total number of items in a collection or group is what is meant when we say we are counting in arithmetic. To count, then, is to speak numbers in sequence while giving each item in a group a value based on a one-to-one correlation. Objects are counted using counting numbers.
Children who are eight years old frequently count up to 1,000 and have mastered skip counting. There are many chances to deepen their comprehension at home using basic math games.
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Help with this question
Answers
The theoretical and experimental probabilities are equal.
What is probability?Probability determines the likelihood of a random event occurring. The ratio of the number of favorable outcomes to the total number of possible outcomes is known as theoretical probability.
Theoretical probability = number of odd sides/ die sides
Here given that the numbers that are odd comes 6
So,
6/20 = 3/10 theoretical probability
The outcome of an experiment that has been repeated multiple times is used to calculate experimental probability.
Experimental probability = number of times Tani landed on a odd number divided by the number of times the experiment was performed
6/ 20= 3/10.
Therefore here , both experimental and theoretical probabilities are equal.
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What is the name of the relationship between ∠1 and ∠5 ?
Responses
alternate interior angles
alternate exterior angles
corresponding angles
adjacent angles
Answers
In the figure, the angles m∠ 1 and m∠ 2 are corresponding angles
Corresponding AngleCorresponding angles are the angles which are formed in matching corners or corresponding corners with the transversal when two parallel lines are intersected by any other line (i.e. the transversal).
In the question given, m∠ 1 and m∠ 2 are corresponding angles with each other.
This also implies that they are equal with one another using corresponding angle theorem.
Corresponding angle theorem states that : All corresponding angles are equal to one another.
Therefore, m∠ 1 and m∠ 5 are corresponding angles and are equal to one another.
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What is equidistant in coordinate geometry?
Answers
A point is said to be equidistant from two other points when it is at an equal distance away from both of them. For example, the perpendicular bisector of a line segment is equidistant from both endpoints.
A point is said to be equidistant from a set of objects if the distances between that point and each object in the set are equal.
In two-dimensional Euclidean geometry, the locus of points equidistant from two given (different) points is their perpendicular bisector. In three dimensions, the locus of points equidistant from two given points is a plane, and generalising further, in n-dimensional space the locus of points equidistant from two points in n-space is an (n−1)-space.
For a triangle the circumcentre is a point equidistant from each of the three vertices. Every non-degenerate triangle has such a point. This result can be generalised to cyclic polygons: the circumcentre is equidistant from each of the vertices. Likewise, the incentre of a triangle or any other tangential polygon is equidistant from the points of tangency of the polygon's sides with the circle.
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