A 2 kg brick is moving at a speed of 3 m/s. What is the kinetic energy of the brick?

Answers

Answer 1

Explanation:

it's generally proven that the formula for kinetic energy is k. e = ½mv²

= ½×2×3

=3


Related Questions

scholastic science world
CHECK FOR UNDERSTANDING: VIDEO GAME TYCOONS

Answers

I dont see it ;-; REEEEEEEE

a bag of sugar has a mass of 2.26 kg. what is its weight

Answers

Answer:

2260

gimme brainliest rn

Two vectors are given as A⃗ = 2i^ + 3j^ − 3k^ and B⃗ = -1i^ + 5j^ + 3k^. Find A⃗ ⋅ B⃗

Answers

Answer:

A·B = 4

Explanation:

Given that,

Vector A = 2i+3j-3k

Vector B = -i+5j+3k

We need to find the value of A·B.

We know that,

i·i=j·j=k·k = 1 and i·j=j·k=k·i=0

So,

[tex]A\cdot B=(2i+3j-3k)\cdot (-i+5j+3k)\\\\=-2+5(3)+(-3)(3)\\\\=-3+15-9\\\\=4[/tex]

So, the value of A·B is equal to 4.

Which statement is true?
A)
All waves travel at the same speed through any medium.
B)
All waves travel at the same speed if no medium is present.
Electromagnetic waves require a medium, but mechanical waves do not.
D)
Mechanical waves require a medium, but electromagnetic waves do not

Answers

Answer:

B.

Explanation:

B)all waves travel at the same speed if no medium is present


Hope I helped :))

HELP 30 POINTS
The picture above shows a cross section of the Earth’s interior including both oceanic crust and continental crust. Along the seafloor, there are mid–ocean ridges where magma rises to the surface and creates new crust. There are also areas where crust is recycled as oceanic crust goes below continental crust. What type of boundary would occur at a mid-ocean ridge?

Answers

Mid-ocean ridges happen along divergent plate boundaries, where new ocean floor is created as the Earth’s tectonic plates spread apart. As the plates separate, molten rock rises to the seafloor, producing large volcanic eruptions of basalt.

The unit J/Pa is equivalent to

(a) m³

(b) cm³

(c) dm³

(d) None of these​

Answers

Answer:

(a) m³

Explanation:

Joule is the unit of work and Pascal is unit of pressure.

J/Pa = work/pressure = Nm/Nm⁻² =

Thus, The unit J/Pa is equivalent to

-TheUnknownScientist

You need to load a crate of mass m onto the bed of a truckon earth. One possibility is just to lift the crate straight up over a height h, equal to height of the truck's bed. Theforce exert in this case is F1 and the work done in this case is W1. The other possibility is to slide the crate up the frictionless ramp of length L.. In this case you exert force F2 and perform work W2. Which statement is true?

a. F1 > F2 and W1 > W2
b. F1 = F2 and W1 > W2
c. F1 = F2 and W1 = W2
d. F1 > F2 and W1< W2
e. F1 > F2 and W1 = W2

Answers

Answer:

The correct answer is - option E. e. F1 > F2 and W1 = W2

Explanation:

Case 1 - F1 = mg, m= mass and g = gravitational force

Work done W1 = F1h= mgh (h - height of bed of truck)

Case 2 - F2 = mgsinθ

work done W2 = mgsinθ×L (L=length of ramp ans sin θ angle of ramp)

sinθ = h/l, then W2 = mg(h/L)L

W2 = mgh

By comparing both,

F2 = mgsinθ and F1 = mg therefore,

F2>F1

now, W2 = mgh, and W1 = mgh

therefore, W2 = W1.

A toy car of mass 2.0kg is made to move in a circular track of radius 10.0m. If the centripetal force is 800.0N, calculate the angular velocity of the car​

Answers

Answer:

w = 6.325 rad/s

Explanation:

Given the following data;

Mass = 2kg

Radius, r = 10m

Centripetal force = 800N

To find the angular velocity of the car;

First of all, we would use the following formula to solve for the speed of the car;

Centripetal force = mv²/r

800 = 2*v²/10

Cross-multiplying, we have;

8000 = 2v²

4000 = v²

Taking the square root of both sides, we have;

v = √4000

v = 63.25 m/s

Next, we find the angular velocity, w using the formula below;

w = v/r

w = 63.25/10

w = 6.325 rad/s

A wheel has an angular speed of 32 rev/s when it experiences a constant angular acceleration of 65 rev/s2 which causes it to spin FASTER. During this time the wheel completes 92 rev. Determine how long the wheel was experiencing this angular acceleration and how fast the wheel was spinning at the end of this period. Assume that the wheel doesn't change the direction of its spin.

Answers

Answer:

ωf = 113.95 rev/s

t = 1.26 s

Explanation:

We can use the third equation of motion to find out the final spinning speed of the wheel:

[tex]2\alpha \theta = \omega_f^2 -\omega_i^2\\[/tex]

where,

α = angular acceleration = 65 rev/s²

θ = No. of revolutions completed = 92 rev

ωf = final angular speed = ?

ωi = initial angular speed = 32 rev/s

Therefore,

[tex](2)(65\ rev/s^2)(92\ rev) = \omega_f^2 - (32\ rev/s)^2\\\omega_f^2 = 11960\ rev^2/s^2 + 1024\ rev^2/s^2\\\omega_f = \sqrt{12984\ rev^2/s^2}[/tex]

ωf = 113.95 rev/s

Now, for the time we can use the first equation of motion:

[tex]\omega_f = \omega_i +\alpha t\\113.95\ rev/s - 32\ rev/s = (65\ rev/s^2)t\\t = \frac{81.95\ rev/s}{65\ rev/s^2}\\\\[/tex]

t = 1.26 s

Brian Lara is a cricketer playing in the field on the second day of a cricket test-match. He exerts a forward force on the 0.145kg cricket ball, as he catches it, to bring it to rest from a speed of 38.2m/s. During the process, his hand recoils a distance of 0.135m. Determine the acceleration of the ball and the force which is applied to it by Brian Lara.

Answers

Answer:

a = -3984.6 m/s²

F = 577.76 N

Explanation:

The acceleration of the ball can be calculated by using the third equation of motion:

[tex]2as = v_f^2 - v_i^2\\[/tex]

where,

a = acceleration of ball = ?

s = distance covered = recoil distance = 0.135 m

vf = final speed = 0 m/s

vi = initial speed = 38.2 m/s

Therefore,

[tex]2(0.135\ m)a = (0\ m/s)^2-(38.2\ m/s)^2\\[/tex]

a = -3984.6 m/s²

here negative sign shows deceleration.

Now, for the force applied by Brian Lara will be equal in magnitude but opposite in direction of the force required to stop the ball:

[tex]F = -ma\\F = -(0.145\ kg)(-3984.6\ m/s^2)\\[/tex]

F = 577.76 N


Chemical energy may be released during a chemical reaction in the form of heat ..... True or false?

Answers

Answer:

heat and gas sometimes so true

Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. Suppose the mass of a certain spherical neutron star is twice the mass of the Sun and its radius is 13.0 km. Determine the greatest possible angular speed the neutron star can have so that the matter at its surface on the equator is just held in orbit by the gravitational force. (The mass of the Sun is 1.99 1030 kg.)

Answers

Answer:

The required angular speed the neutron star is 10992.32 rad/s

Explanation:

Given the data in the question;

mass of the sun M[tex]_S[/tex] = 1.99 × 10³⁰ kg

Mass of the neutron star

M[tex]_N[/tex] = 2( M[tex]_S[/tex] )

M[tex]_N[/tex] = 2( 1.99 × 10³⁰ kg )

M[tex]_N[/tex] = ( 3.98 × 10³⁰ kg )

Radius of neutron star R[tex]_N[/tex] = 13.0 km = 13 × 10³ m

Now, let mass of a small object on the neutron star be m

angular speed be ω[tex]_N[/tex].

During rotational motion, the gravitational force on the object supplies the necessary centripetal force.

GmM[tex]_N[/tex] = / R[tex]_N[/tex]² = mR[tex]_N[/tex]ω[tex]_N[/tex]²

ω[tex]_N[/tex]² = GM[tex]_N[/tex] = / R[tex]_N[/tex]³

ω[tex]_N[/tex] = √(GM[tex]_N[/tex] = / R[tex]_N[/tex]³)

we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²

we substitute

ω[tex]_N[/tex] = √( (  6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)

ω[tex]_N[/tex] = √( 2.65466 × 10²⁰ / 2.197 × 10¹²

ω[tex]_N[/tex] = √ 120831133.3636777

ω[tex]_N[/tex] = 10992.32 rad/s

Therefore, The required angular speed the neutron star is 10992.32 rad/s

PLEASE HELP! I'LL GIVE BRAINLEST​

Answers

Answer:

8.162

Explanation:

W=mg

  = 2.2 x 3.71

  = 8.162 N

PHYSICS HELP
PLEASE HELP ITS ABOUT ATWOOD MACHINES

Answers

Answer:

7.23407 [tex]\frac{m}{s^2}[/tex]

Explanation:

(I will not include units in calculations)

I'm assuming FBD's are already drawn, so I will work from there.

Let the 2.2kg block equal [tex]m_2[/tex], and the 20kg block equal [tex]m_1[/tex].

Summation equation for [tex]m_2[/tex]: [tex]\sum F_x=F_t_2-(F_f+F_g_x)=m_2a[/tex], [tex]\sum F_y=F_n-F_g_y=0[/tex]

Summation equation for [tex]m_1[/tex]: [tex]\sum F_y=F_g-F_t_1=m_1a[/tex]

Torque Summation Equation: [tex]\sum\tau=F_t_1*r-F_t_2*r=I\alpha[/tex]

Do some plugging in with the values given: [tex]\sum\tau=F_t_1*r-F_t_2*r=.5Mr^2\alpha[/tex]

Replace [tex]\alpha[/tex] with [tex]\frac{a}{r}[/tex], and cancel out the r's.

[tex]\sum\tau=F_t_1-F_t_2=.5Ma[/tex]

This step is important: Rearrange the force summation equation to solve for each tension force.

[tex]F_t_2=m_2a+F_f+F_g_x\\F_t_1=m_1g=m_1a[/tex]

Perform Substitution: [tex]\sum\tau=m_1g-m_1a-(m_2a+F_f+F_g_x)=.5Ma[/tex]

Now, we need to find the friction force and the horizontal component of the force of gravity.

Note that [tex]F_f=[/tex]μ[tex]F_n[/tex]

And based on our earlier summation equation: [tex]F_n=F_g_y[/tex]

First, break [tex]F_g[/tex] into x and y components. [tex]F_g_y=F_g\cos(\theta)[/tex], [tex]F_g_x=F_g\sin(\theta)[/tex]

Perform substitution with this and the fact that [tex]F_g=mg[/tex].

[tex]\sum\tau=m_1g-m_1a-(m_2a+\mu*m_2g\cos(\theta)+m_2g\sin(\theta))=.5Ma[/tex]

Solving for a, plugging in numbers yields an answer of 7.23407 [tex]\frac{m}{s^2}[/tex]

Answer:

7.23407

Explanation:

easy

does altitude has an effect on weight? HELP​

Answers

Answer:  lose weight at high altitudes.

Explanation:

Answer:

Just a week at high altitudes can cause sustained weight loss, suggesting that a mountain retreat could be a viable strategy for slimming down. Overweight, sedentary people who spent a week at an elevation of 8,700 feet lost weight while eating as much as they wanted and doing no exercise

what is an axis in social​

Answers

Answer:

An axis is an invisible line around which an object rotates, or spins. The points where an axis intersects with an object's surface are the object's North and South Poles.

Which diagram best represents the gravitational forces, F, be-
tween a satellite, S, and Earth?

Answers

Answer:

Diagram (3).

Explanation:

N3L states that if object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A ([tex]F_{A} = -F_{B}[/tex]).

The diagram which best represents the gravitational forces, F, between a satellite, S, and Earth is; Choice (3).

The Newton's law of gravitation states that the Force of attraction between two objects is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

The law clearly states a Force of attraction; the two objects come towards each other.

Consequently, Choice (3) best represents the gravitational forces, F, between a satellite, S, and Earth.

Read more:

https://brainly.com/question/11460810

Niobium metal becomes a superconductor when cooled below 9K. Itssuperconductivity is destroyed when the surface magnetic fieldexceeds 0.100 T. Determine the maximum current a 2.00-mm-diameterniobium wire can carry and remain superconducting, in the absenceof any external magnetic field.

Answers

Answer:

the maximum current is 500 A

Explanation:

Given the data in the question;

the B field magnitude on the surface of the wire is;

B = μ₀i / 2πr

we are to determine the maximum current so we rearrange to find i

B2πr = μ₀i

i = B2πr / μ₀

given that;

diameter d = 2 mm = 0.002 m

radius = 0.002 / 2 = 0.001 m

B = 0.100 T

we know that permeability; μ₀ = 4π × 10⁻⁷ Tm/A

so we substitute

i = (0.100)(2π×0.001 ) / 4π × 10⁻⁷

i = 500 A

Therefore, the maximum current is 500 A

I need help please only way to put my grade up !!!!!! Would appreciate it !!! Someone who’s good at this

Answers

Answer:

Total energy = 1000J

KE = 500J

PE = 500J

Explanation:

As you may know, the equation for gravitational potential energy is mgh (weight x height)

If the skateboard is halfway down, that means it is at half the height. As the skateboard speeds up (as it goes downward), the potential energy becomes kinetic energy. Since it has 500J of kinetic energy at half way down, it means it had double that amount of Potential energy at the top (1000J). Since half of that became kinetic energy, there is only 500J of PE left.

Total energy = KE + PE = 1000J

KE = 500J

PE = 500J

A student is investigating the differences between light waves and sound waves. The student does this by using a capsule filled with solid glass at one end and a vacuum at the other end. The student will transmit waves into the capsule at a 30° angle to the (normal) centerline.

alert your teacher if the image is missing

Which >>TWO<< questions should the student ask, and which predictions are MOST LIKELY correct based on this investigation?

Group of answer choices

question: Can electromagnetic waves and mechanical waves travel from a solid glass medium into a liquid medium?

prediction: The electromagnetic waves will continue through the liquid medium, while the mechanical waves will go no farther.


question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?

prediction: The electromagnetic waves will continue through the vacuum, while the mechanical waves will go no farther.


question: Can electromagnetic waves and mechanical waves travel from a solid glass medium into a liquid medium?

prediction: Both electromagnetic waves and mechanical waves will bend, showing that they have passed through each medium.


question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?

prediction: The electromagnetic waves and mechanical waves will continue through the vacuum at a lower speed.


question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?

prediction: The electromagnetic waves will travel in a straight line, showing that they have maintained a constant speed.


question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?

prediction: The electromagnetic waves will bend downward, showing that they have sped up slightly

Answers

Answer:

Explanation:

The investigation is on differences between light waves and sound waves. Because the light and sound are transmitted at a 30° angle at a capsule with glass and vacuum, questions asked should show difference answers for light and sound.

First and third question talk about liquid which is not related here.

Fouth and sixth prediction are wrong as electromagnetic wave will not slow down or speed up in vacuum.

That leaves the second and fifth set as correct answers:

question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?

prediction: The electromagnetic waves will continue through the vacuum, while the mechanical waves will go no farther.

question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?

prediction: The electromagnetic waves will travel in a straight line, showing that they have maintained a constant speed.

Answer:

The two questions and predictions are:

question: How are electromagnetic waves and mechanical waves affected when traveling from a solid glass medium to a vacuum?

prediction: The electromagnetic waves will continue through the vacuum, while the mechanical waves will go no farther.

question: How is the speed of electromagnetic waves affected when traveling from a solid glass medium to a vacuum at a 30° angle?

prediction: The electromagnetic waves will travel in a straight line, showing that they have maintained a constant speed.

Explanation:

light is EM wave which is transverse while sound is longitudinal. speed changes for long wave but not EM.

A moving man is lifting a box up an inclined plane. Halfway up he sets the box down and rests. Which of the following explains why the box does not slide back down the inclined plane?
a. The force of friction balances the force of gravity.
b. The force of gravity does not affect inclined planes.
c. The force of friction does not affect inclined planes.
d. The force of friction is less than the force of gravity.

Answers

Answer: A or B

Explanation: I’m guessing that they even each other out depending on the incline, gravity will help keeping it in place

HELP HELP HELP HELP HELP PLEASEEE HELP ME WITH MY OTHER QUESTIONS TOO!! PLEASE

Answers

That person is a scam up top

A sphere with the same mass and radius as the original cylinder, but a smaller rotational inertia, is released from rest from the top of the ramp. KS and KC are the sphere's and cylinder's total kinetic energy at the bottom of the ramp, respectively. How do KS and KC compare, and why

Answers

Answer:

The Kinetic energy of Sphere is higher than the cylinder.

( KS > KC )

Explanation:

Given - A sphere with the same mass and radius as the original cylinder, but a smaller rotational inertia, is released from rest from the top of the ramp. KS and KC are the sphere's and cylinder's total kinetic energy at the bottom of the ramp, respectively.

To find - How do KS and KC compare, and why ?

Proof -

We know that,

The total energy of an object =  Potential energy +  linear kinetic energy + rotational kinetic energy.

⇒E = mgh + [tex]\frac{1}{2} mv^{2}[/tex] + [tex]\frac{1}{2} l\omega^{2}[/tex]  

Now,

Mass of sphere = m

Radius of sphere = r

So,

The moment of inertia of a uniform solid sphere = [tex]\frac{2}{5} mr^{2}[/tex]

Also,

Mass of cylinder = m

Radius of cylinder = r

So,

The moment of inertia of a uniform solid cylinder = [tex]\frac{1}{2} mr^{2}[/tex]

Now,

Total energy for the sphere , Es = mgh + [tex]\frac{7}{10} mv^{2}[/tex]

Total energy for the cylinder, Ec =  mgh + [tex]\frac{3}{4} mv^{2}[/tex]

As they always have the same total energy,

So, for height h of the sphere's velocity has to be higher.

Therefore,

The Kinetic energy of Sphere is higher than the cylinder.

Answer:

KS < KC

Explanation:

the density of gold is 19g/m³ what is the volume of 38g​

Answers

let the volume be x

19 = 38/x

x=38/19

x=2

volume is 2 cm^3

CORRECT ANSWER GETS BRAINLIEST

Answers

Answer:

Wax melts as it absorb heat from flame

Explanation:

To know which option is correct, it is important that we know what chemical changes and physical changes are all about.

Chemical change is a change in which the process is not easily reversed and it produces new substance.

Physical change is more like the opposite of chemical change. In this change, the process is easily reversed and no new substance is produced.

Considering the options given above,

1. Iron combines with oxygen to produce rust is a chemical change since a new substance (rust) is formed and we can not reverse the process to get back iron and oxygen.

2. Wax melts as it absorb heat from flame is a physical change since no new substance is formed and we obtained the wax by allowing it to solidified.

3. Pure sodium explodes when dropped in water is a chemical change because we can not reverse the process to get back the sodium.

4. Glucose molecules are produced in plant leaf is also a chemical change.

From the illustrations above, it is evident that: 'Wax melts as it absorb heat from flame' is not a chemical

What my fav food for 20 points if you know it!?

Answers

Answer:

pizza

Explanation:

Answer:

sea food???

Explanation:

Instead of changing the focal length of the lens, the eyes of amphibians work in a different manner: a set of muscles changes the shape of the eye which increases the distance between the front of the eye and the retina. The world's largest frog, the Goliath frog of west Africa, has an eye with a maximum size similar to a human's: 2.5cm. However, unlike a human, where the focal length is also 2.5cm, the focal length of the Goliath frog's eye is 2.146 cm. What is the maximum distance this frog can see

Answers

Answer:

The answer is "15.56 cm".

Explanation:

[tex]v= 2.5 \ cm\\\\f= 2.154 \ cm[/tex]

Calculating object of length is x so:

[tex]u= -x[/tex]

Using formula:

[tex]\to \frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\\\to \frac{1}{2.5}-\frac{1}{-x}=\frac{1}{2.154}\\\\\to \frac{1}{x}=\frac{1}{2.154}-\frac{1}{2.5}\\\\\to \frac{1}{2.5}-\frac{1}{-x}=\frac{1}{2.154}\\\\\to x= 15.56 \ cm[/tex]

Which waves can travel through space?
a. Electromagnetic waves only
b. Mechanical waves only
c. Electromagnetic and mechanical waves
d. Longitudinal and electromagnetic waves

Answers

Answer:

electromagnetic waves only

Explanation:

I just took the test, Hope it helps!

Answer:

A: Electromagnetic waves only

Explanation:

Ilus
A bat bounces a sound wave off a
bird 19.4 m away, and hears the
echo after 0.117 s. What is the
speed of sound in the air?
(Hint: It is not necessarily 343 m/s.)
(Unit = m/s)

Answers

Answer:

332m/s

Explanation:

We know the formula for velocity is v=d/t, but this particular question is asking about an echo. The problem tells us the distance to the bird from the bat, which is 19.4. To find the echo, you need to find the distance from the bat to the bird and back.

So

19.4 x 2 = 38.8

And then plug into the equation

v = 38.8 / 0.117

= 332m/s

CAN YOU HELP MEEEEEEEEEE PLEASEEEE

Answers

Answer:

What are your options? also i believe the answer may be ecosystem.

Explanation:

There are both biotic and abiotic factors in an ecosystem. Be cause living organisms Are Biotic. While water and rocks are abiotic which are needed to form an ecosystem.

Other Questions
Provided below is the IR and 'H NMR for a compound having the molecular formula of C,H,O, Using this information, determine the degrees of unsaturation for this structure and solve and draw the structure responsible for these spectral data. To validate your answer, you need to assign the type of bond (ie, stretch) responsible for each peak highlighted by a box in the IR. You must also assign each 'H NMR peak (a)-(e) to the correct set of protons in your proposed structure. The integration for each peak has been provided for you. You must label the multiplicity observed for each peak. Is your structure consistent with all of this data? If not, chances are you do not have the correct structure, or the peaks have been assigned incorrectly. In your peer review, offer feedback concerning the accuracy of the submitted structures and spectral assignments. If you believe the answers are incorrect, then you need to provided explanation. In the end, you should all be getting the same correct structure. Please draw the final structure in the box provided underneath the NMR. TH NMR - for clarity, expansions have been provided for peaks that are not a singlets. Proposed Structure: Remember to assign it to the NMR per instructions. IR FREQUENCY TABLE (in wavenumber) Frequency Range (om ) Intensity Group A. Alky! C-H (stretching) Isopropy. -CH(CH), tert-Butyl, -C(CH) ( -5) and 2853-2002 1380-1385 1365-1370 1385-1395 - 1366 (m) and B. Alkenyl C-H(stretching) C- (stretching) R-CH-CH, m) (v) 3010-3095 1620-1600 085-1000 905-920 80-900 (6) (out of plane >C-H bondinga) and BCHCH cafe Esses se s8 s (8) 675-730 960-975 (6) (s) -3300 2100-2260 (8) () cle-RCH-CHR trans-RCH-CHR C. Alkyny! C H (stretching) C-C (stretching) D. Aromatic Ar-H(stretching) Aromatic substitution type (C-Hout-of-plane bendings) Monosubstituted o-Disubstituted m-Disubstituted -3030 and (very s) (very s) (s) 690-710 730-770 735-770 680-725 750-810 800-860 and (very s) (very s) 3590-3650 3200-3550 2500-3000 (sharp ) (broad, s) (broad, p-Disubstituted E. Alcohol, Phenols, and Carboxylic Acids O H (stretching) Alcohols, phenols (dilute solutions) Alcohols, phenols (hydrogen bonded) Carboxylic acids (hydrogen bonded) F. Aldehydes, Ketones, Esters, and Carboxylic Acids C-O (stretching) Aldehydes Ketones Esters Carboxylic acids Amides G. Amines N- H H. Nitriles CON 1630-1780 1690-1740 1680-1750 1735-1750 1710-1780 1630-1690 (s) (s) (s) (s) (s) (5) 3300-3500 (m) 2220-2260 (m) weak edium w - variatie p rowity Abbreviations strong m NMR CHEMICAL SHIFT TABLE (in ppm) CHARACTERISTIC PROTON CHEMICAL SHIFTS Type of Preton Structure Chemical Shin, ppm Cycopropane CHE Primary R-CH Secondary R-CH: Tertiary R; C-11 Vinylic C=C-H Acetylanic triple bond.CC-H Aromate Ar-H Benzyle Arc- Allylic CHCCH Fluorides H-C-F Chlorides H-C-a Bromides H-C-Br Iodides H-C- Alcohol H-C-OH Ethors H-C-OR 33-4 Esters RCOO-C- 3.7-4.1 Esters H-C-COOR 2-22 Acids H-C-COOH 2-26 Carbonyl Compounds H-C-C-0 2-27 Aldehydie R-CH-)C=0 9-10 Hydroxylic R-C-OH 1-55 Phenolie Ar-OH 4-12 Enolic C-C-OH 15-17 Carboxylic ROOOH 10.5-12 Amino RNH, 1-5 An investor deposited some money at 1.7% annual interest, and two equal but larger amounts at 2.3% and 2.4%. Thetotal amount invested was $25,000, and the total annual interest earned was $568. How much was invested at eachrate?At the rate 1.7%, $ was invested. what disadvantage will result from increased international trade, according to critics of globalization? a. prices of goods and services will decline. b. multinational corporations will increasingly shape the policies of governments. c. people will gain exposure to different cultures. d. more consumer goods will be produced. Question 18 of 24. Some dellverles require a signature and cannot be left unattended. True False Question 19 of 24. Which Personal Protective Equipment (PPE) and essential paperwork must be worn/carried at all times (select all that apply)? O GlovesO Safety visibility vest O Driver's license O Medical certificate (for DOT drivers) Question 20 of 24. Customer instructions are key to a perfect delivery. True False Question 21 of 24. To plan ahead using REPS & 10, what is the minimum space cushion needed to maintain following distance traveling at 30 MPH (for an Armada van)? O 5-second space cushion O 5-second space cushion O 7-second space cushionO You don't need a space cushion Which of the following operations are closed for whole numbers? I need help with these problems 1-11 a researcher wants to find out if people who kiss more than ten times a day wear brighter colors to work than those who do not. to test this, the researcher sends a survey to people to ask whether a participant normally kisses ten times per day or not and normally wears bright colors to work. the researcher assumes all assumptions are nonparametric. which test statistic would you use? What part of the plot concludes the falling action by revealing the outcome of the conflict? Solve for b.b-c+d/8 = a e. coli bacteria are placed into a medium containing both glucose and lactose. which of the gene products (i.e., enzymes) listed below do you predict will be fully transcribed? What one thing affects boiling point elevation and freezing point depression the most in a solution? balance the equation What means right to be let alone the right of a person to be free from any unwarranted interference? A mutual fund has breakpoints at $25,000, $50,000, $100,000, and $250,000. Which of the following transactions might be considered a breakpoint sale?O The client purchases $48,000 worth of sharesO The client redeems $24,000 worth of sharesO The client purchases $252,000 worth of sharesO The client purchases $96,000 worth of shares Which Gilgamesh new English version is best? What is the formula for root mean speed? ???????????????????? Your brother is arguing that popcorn kernels are nonliving things. You think they are living. List all the characteristics that you think make the popcorn kernels living. How could you prove it? Design an experiment to test if the popcorn is alive or not. __________is inventory that has been ordered but is in transit. triangle XYZ has vertices X(0,2), Y(4,4), and Z (3,-1). Triangle XYZ is rotated 180 counter clockwise about Z. in which quadrant is the image of point X