Answer:
c. 80%
Explanation:
Given;
load raised by the machine, L = 360 N
distance through which the load was raised, d = 0.2 m
effort applied, E = 50 N
distance moved by the effort, e = 1.8 m
The efficiency of the machine is calculated as follows;
[tex]Efficiency = \frac{ 0utput \ work }{1nput \ work} \times 100\% \\\\Efficiency = \frac{Load \ \times \ distance \ moved \ by \ load }{Efort \ \times \ distance \ moved \ by \ effort} \times 100\%\\\\Efficiency = \frac{360 \times 0.2}{50 \times 1.8} \times 100\%\\\\Efficiency =80\%[/tex]
Therefore, the efficiency of the machine is 80%
a truck with 0.363-m-radius tires travels at 23.9 m/s. what is the angular velocity of the rotating tires in radians per second?
Answer:
Below
Explanation:
Circumference of tires = 2 pi * r=2.28079 m
rpm * 2pi = (23.9 m/s )/ (2.28079 m) * 2pi = 65.8 R/s
A 200 ω resistor, a 0.850 h inductor, and a 5.75 μf capacitor are connected in series across a voltage source that has voltage amplitude 29.0 v and an angular frequency of 260 rad/s.
a. What is v at t= 22.0 ms ?
b. What is vR at t= 22.0 ms ?
c. What is vL at t= 22.0 ms ?
d. What is vC at t= 22.0 ms ?
The root mean square voltage Vrms of the circuit is 15.49 V.
The voltage of the resistor vR is 10.4 V.
The voltage of the inductor vL is 11.49 V.
The voltage of the capacitor vC is 0.035 V.
RMS voltage of the circuit is calculated as follows:
Vrms = -V₀ sin ωt = -29 * sin (260* 22* 10⁻³) = 29 * 0.534 = 15.49 V
XI = ωL = 260* 0.85 = 221 ohms
Xc = 1/ωc = 1/(260 * 5.75* 10⁻³) = 10³/1495 = 0.67 ohm
Z = √[R² +(XI - Xc)²] = √[200² + (221 - 0.67)²] = √[200² + 220.33²]
= √[ 40000 + 48545.30] = 297.56 ohm
Current flowing in the circuit is
Irms = Vrms/Z = 15.49 / 297.56 = 0.052 A
vR = Irms * R = 0.052 * 200 = 10.4 V
vL = Irms * L = 0.052 * 221 = 11.49 V
vC = Irms * C = 0.052 * 0.67 = 0.035 V
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A student swings ball of mass M on the end of a string in vertical circle of radius R,as shown in the figure below. Also shown is diagram representing all the forces exerted on the ball at the bottom of the circle where its speed is What is the magnitude of the acceleration of the ball at the bottom of the circle? FTension FGravity
A)Fi /M
B)Fc /M
C)Fr+Fg/M
D) Ft- Fg/M
The magnitude of the acceleration of the ball applied at the bottom of the circle is expressed as FTension-FGravity/M.
When making a vertical circle with a ball on a string?The string's tension varies along its vertical as well as circular course. The ball's speed varies as long as the total amount of kinetic and potential energy is constant through out. Centripetal force fluctuates when speed changes accordingly.How can I determine the tension of a string moving in a vertical circle?You can write it down as FC = mv2 /r.
The centripetal force in a moving object attached to a string is equal to the product of the object's mass (mg) and the string tension (T).
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A high school physics student with a mass of 75 kg is sitting in a seat reading this question. The magnitude of the force with which the seat is pushing up on the student is:.
Answer:
736 N
Explanation:
F = 75 kg * 9.81 m/s^2 = 736 Newtons
Michael’s mom is driving the soccer carpool. They leave the field at 7 pm, with an odometer reading of 78,753 km. Combined the minivan and players have a mass of 2900 kg. After all the players are dropped off, it is 7:56 pm and the odometer reads 78,802 km. What was the average velocity of the minivan while traveling?
Answer:
0.875 miles/minute
Explanation:
The formula for velocity if final position - initial position divided by final time - initial time. Here, the final position
of the van was 49 km away from house, and its initial was 0, because you didn't travel anywhere initially. The final time was 56 minutes because that was how long it took to get home, and the initial was 0, because you were 0 minutes into travel at the beginning.
What measuring instrument should be used to determine if there was presence of electricity running in her extension cord?
Electrical voltage can be found in cable, cables, circuit breakers, light fixtures, outlets, and switches using voltage testers and receptacle analyzers.
How do you determine whether there is electricity present?
Simply place one tester probe against a hot wire, screw terminal, or outlet slot to utilise a neon voltage tester. Connect the second probe to a ground or neutral contact. If there is current, the small neon bulb at the tool's tip will light up.
Which test is performed to detect whether a piece of equipment contains electricity?
test bulbA piece of electrical test equipment called a test light, test lamp, voltage tester, or mains tester is used to determine whether electricity is present in a piece of equipment that is being tested
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In order to determine causal effects between variables, researchers must use. a. Correlational designs b. Case studies O c Experimental designs O d. All of the above
To identify the factors influencing the associations between the variables, researchers must adopt a correlational design.
An investigator who carries out research, that is, a planned and methodical examination of something, is referred to as a researcher. As researchers, scientists are frequently referred to.
Researchers are employed by authors of books that require extensive information collection, such as those by Michael Crichton who write about biology, to assist them in compiling and analyzing data. Some authors conduct their own research by consulting friends who are doctors to find intriguing methods for their characters to pass away.
Research and development (R&D) of methods and systems for the expansion of human knowledge are the main goals of fundamental research (as opposed to applied research). These goals include documentation, discovery, interpretation, and R&D. Research methodologies rely on epistemologies, which differ greatly within the humanities and sciences as well as within each discipline. Science, the humanities, the arts, business, marketing, and social and economic research are some of the several types of research.
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a cylinder with cross-section area a floats with its long axis vertical in a liquid of density rho.
a) The expression for force needed to push the cylinder distance deeper into the liquid by a distance x is F = ρ × A × x.
b) The work done to push the cylinder 10 cm deeper into the water is 12.315 N-m.
The force required to push the cylinder by a certain distance is nothing but the weight of the liquid displaced by the same distance.
So, F = ρ × A × x
where, p is density
x is distance
A is area
We know the expression for work as, W = F × z
where, z is the work required to move through distance z
From a) we can write F = A × z² × ρ
Given that, d = 4 cm
So, r = 2 cm = 0.2 m
z = 10 cm = 0.10 m
ρ = 1000 kg/m³ = 9800 N/m³
Substituting the values in the above equation, we have,
W = π × 0.2² × 0.1² × 9800 = 12.315 N-m
The question is incomplete. The complete question is 'a.) Pressing down on the cylinder pushes it deeper into the liquid. Find an expression for the force needed to push the cylinder distance deeper into the liquid and hold it there.
'b.) A 4.0 cm diameter cylinder floats in water. How much work must be done to push the cylinder 10 cm deeper into the water?'
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9. An astronaut weighs 500 Newtons on Earth and 25
newtons on asteroid X. The acceleration due to
gravity on asteroid X is approximately
A) 1 m/s²
C) 0.2 m/s²
B) 2 m/s²
D) 0.5 m/s²
The acceleration due to gravity on asteroid X is approximately 0.5 meter/secon^2. Hence, option (D) is correct.
What is acceleration due to gravity?The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. M/s^2 is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The letter g stands for gravitational acceleration.
Given that: An astronaut weighs 500 Newtons on Earth and 25 newtons on asteroid X.
Hence, The acceleration due to gravity on asteroid X is :
= acceleration due to gravity on Earth × (25 N/500N)
= 10 meter/secon^2 × (1/20)
= 0.5 meter/secon^2 ( approx.)
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(a) calculate the rotational kinetic energy of earth on its axis. (b) what is the rotational kinetic energy of earth in its orbit around the sun?
The rotational kinetic energy of the earth on its axis is 2.08 x 10^29 Joules and the rotational kinetic energy of the earth in its orbit around the sun is 2.17 x 10^33 Joules.
(a) To calculate the rotational kinetic energy of Earth on its axis, we can use the formula:
KE = 0.5 * I * ω^2where KE is the rotational kinetic energy, I is the moment of inertia of the object, and ω is the angular velocity.
The moment of inertia of Earth can be calculated using the formula:
I = (2/5) * m * r^2where m is the mass of Earth and r is the radius of Earth.
Using these formulas, we can calculate the rotational kinetic energy of Earth as follows:
KE = 0.5 * [(2/5) * m * r^2] * (ω^2)
= 0.5 * [(2/5) * 5.97 x 10^24 kg * 6371 km^2] * (7.29 x 10^-5 rad/s)^2
= 2.08 x 10^29 Joules
(b) To calculate the rotational kinetic energy of Earth in its orbit around the sun, we can use the formula:
KE = 0.5 * m * v^2where KE is the rotational kinetic energy, m is the mass of Earth, and v is the velocity of Earth in its orbit around the sun.
The velocity of Earth in its orbit around the sun can be calculated using the formula:
v = √[(G * M) / r]where G is the gravitational constant, M is the mass of the sun, and r is the distance of Earth from the sun (also known as the semimajor axis of Earth's orbit).
Using these formulas, we can calculate the rotational kinetic energy of Earth in its orbit around the sun as follows:
KE = 0.5 * m * [√[(G * M) / r]]^2
= 0.5 * m * [(G * M) / r]
= 0.5 * 5.97 x 10^24 kg * [(6.67 x 10^-11 N * m^2 / kg^2) * (1.989 x 10^30
kg) / (1.496 x 10^11 m)]
= 2.17 x 10^33 Joules
Note that the rotational kinetic energy of Earth in its orbit around the sun is much greater than the rotational kinetic energy of Earth on its axis, due to the much larger velocity and mass involved in Earth's orbit around the sun.
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Which of the following can result in deviations from Beer's law when the path length is constant? Explain your answer.
1. All radiation not absorbed by the sample is transmitted to the detector.
2. Stray light reaching the detecter.
3. Solute conc. exceeding 0.01 M.
4. The use of polychromatic radiation.
5. The sample is heterogenous Just need the ones that are correct.
There are several conditions that can result in deviations from Beer's Law when the pathlength is constant. This can cause the Beer's Law plot to become non-linear.
When the solute concentrations exceed 0.01 m. This can cause the Beer's Law plot to become flat or even inverted. The use of polychromatic radiation can also cause deviations from Beer's Law. This is because different wavelengths of light will be absorbed to different degrees by the sample.
When the pathlength is constant, the conditions that can result in deviations from Beer's law are:
1) All radiation not absorbed by the sample is transmitted to the detector.
2) The absorbing species undergoes dissociation or association.
3) The sample is homogeneous.
4) Solute concentrations exceeding 0.01 M.
5) The use of polychromatic radiation.
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What acceleration does a net force of 32 N impart to a mass of; *
30 kg
45 kg
14 kg
32 kg
3 kg
0.094 m/s^2 0.94 m/s^2
O
O
O
O
1.00 m/s^2 0.44 m/s^2
O
O
O
O
O
O
O
10 points
1.41 m/s^2
O
O
This query calls for the use of Newton's second law of motion. Mass is equal to the product of acceleration and net force. Mass = 32 N / 4 m/s2 = 8 kg when the values are entered into the formula.
If an object has a mass of 10 kg and a force of 30n, what is its acceleration?We can obtain a=F/m by adopting the formula F=m*a and rearranging the subject. Then, using the provided numbers as substitutes, we can determine that a=30/10=3. The item will accelerate at 3ms-2 because acceleration is measured in ms-2.
How is force calculated?Newton's second law of motion provides the definition of the force formula: An object's force is equal to its mass times its acceleration. F = m ⨉ a. To apply this formula, you must use SI units for force (newtons), mass (kilograms), and acceleration (meters per second squared).
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What is the relation between the wavelength λ and the frequency f of a signal?
The frequency and wavelength are indirectly proportional to each other. More is the wavelength, lesser is the frequency and vice-versa.
What is a wavelength?
Wavelength is the distance between identical points( conterminous peaks) in conterminous cycles of a waveform signal propagated in space or along a line. In wireless systems, this length is generally given in measures( m), centimeters( cm), or millimeters( mm). In the case of infrared( IR), visible light, ultraviolet( UV), and gamma shafts( γ)The wavelength is more frequently given in nanometers( nm), which are units of 10- 9 m, or angstroms( Å)., which are units of 10- 10m. Wavelength is equally commensurable with frequency, which refers to the number of surge cycles per second. The advanced is the frequence of the signal, the shorter the wavelength.To know more about Wavelength, click the link given below:
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Wy is it necessary to reduce the voltage to a motor when the frequency is reduced?
To reduce magnetic flux density, it is necessary to reduce the voltage to a motor when the frequency is reduced. This will resist lowering of inductive reactance and increase of rotor current
When we decrease voltage applied to the motor. The current in stator is winding as well as the magnetic flux density will decrease along with decrease in induced voltage.
The voltage induced over rotor's conductor is defined here
,[tex]V_{R[/tex] = B.l.u
We can see things in other way also. Changing frequency has effect on both the motor speed and the strength of the magnetic field. With the lowering of frequency motor speed becomes slow.
With reduction in voltage, magnetic field decreases and magnetic flux becomes constant. This keeps torque production stable, regardless of frequency.
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On the screenshot linked below, the answer to part one is .237141. How would I solve part two?
(a) The fraction of neutron's kinetic energy transferred to the atomic nucleus is 0.068.
(b) The final kinetic energy of the neutron is 2.48 x 10⁻¹³ J.
What is the final velocity of the atom?The final velocity of the atom is calculated by applying the principle of conservation of linear momentum as follows;
initial momentum of the neutron = final momentum of the atom
m₁u₁ = m₂u₂
where;
m₁ is the mass of the neutronu₁ is the initial velocity of the neutronm₂ is the mass of the atomic nucleusu₂ is the final velocity of the atomic nucleusThe mass of the atom = 14.8m₁
u₂ = m₁u₁ / m₂
u₂ = m₁u₁ / (14.8m₁)
u₂ = 0.0676u₁
The initial kinetic energy of the neutron is calculated as;
K.Ei = ¹/₂m₁u₁²
The final kinetic energy of the atom is calculated as;
K.Ef = ¹/₂m₂u₂²
K.Ef = ¹/₂(14.8m₁)(0.0676u₁)²
K.Ef = 0.068 (¹/₂m₁u₁²)
K.Ef = 0.068 (K.Ei)
The fraction of neutron's kinetic energy transferred to the atomic nucleus is calculated as;
= 0.068 (K.Ei) / K.Ei
= 0.068
= 6.8 %
The final kinetic energy of the neutron is calculated as follows;
K.E.f (neutron) = (1 - 0.068) x (2.66 x 10⁻¹³ J)
K.E.f (neutron) = 2.48 x 10⁻¹³ J
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What happens when a magnet moves near or in a coil of wire?
Answer:
Below
Explanation:
A VOLTAGE is induced across the coil.... if the ends of the coil are connected together or to a circuit, a current will flow
2 points
A rocket accelerates from 50 m/s to 250 m/s in 10 seconds. What is the acceleration of the rocket?
0.04 m/s²
25 m/s²
2500 m/s²
O 20 m/s²
Answer:
The acceleration of the rocket is 20 m/s².
Explanation:
This can be calculated by dividing the change in velocity by the time it took to achieve that change in velocity. In this case, the change in velocity is 250 m/s - 50 m/s = 200 m/s, and it took 10 seconds, so the acceleration is 200 m/s / 10 s = 20 m/s².
an automobile horn emits a sound frequency of 800 hzas measured by a stationary observer. what frequency would be measured by an observer moving toward the source at 35:0 m
Answer:
The source emits sound at 800 / sec - f = 800 / s
The auto moves at 35 / 800 sec (the apparent wavelength is shortened)
f' = f + f vo / v where vo is the speed of the observer
f' = f (v + vo) / v rewriting the above equation
f' = 800 / sec (331 + 35) / 331 using 331 m/s as the speed of sound
f' = 885 / sec sound heard
Kumar rides his bicycle such that the back wheel rotates 10 times in 5 s. Determine the angular velocity of the wheel in a) degrees per second b) radians per second.
(a) Angular velocity in Degrees per second = [tex]720^0[/tex] per second
(b) Angular velocity in radians per second = 4[tex]\Pi[/tex] radians per second.
Number of rotations = 10
Total time = 5
So, the value of frequency will be =(Number of rotations)/Total time
That will be = (10/5) = 2
Angular velocity is defined as the speed at which an item rotates or revolves around an axis.
The Greek letter omega (occasionally ω, sometimes Ω) stands for angular velocity.
The SI unit for angular velocity is radians per second because it is expressed as an angle per unit of time.
(a) Angular velocity in Degrees per second
[tex]$=360^{\circ} \mathrm{f}=720^{\circ}$[/tex] degree per second.
(b) Angular velocity in radians per second
[tex]$\omega =2 \pi f=2 \pi(2)=4 \pi$[/tex] radians per second.
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What is the force of friction on a sliding object?
Sliding friction is the resistance that any two items produce as they slide against one another. Kinetic friction is another name for this friction.
What forces are at work on the moving object?The external force is the frictional motion. When the external factor is larger than the pressure of kinetic friction, acceleration happens. When the amount of kinetic friction exceeds the force of the external force, slowing (or stopping) takes place.
What kind of sliding friction is that?When an object slides across a surface, sliding friction is regarded as a resistance to that object's motion. Think of a box that is on the ground. This surface is in close proximity to the floor's surface.
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Three different forces are pulling on a heavy trapdoor (Figure 4.6). Which
force will have the biggest turning effect? Explain your answer.
A 175 g glider on a horizontal, frictionless air track is attached to a fixed ideal spring with force constant 155 n/m. At the instant you make measurements on the glider, it is moving at 0. 815 m/s and is 3. 00 cm from its equilibrium point. Use energy conservation to find (a) the amplitude of the motion and (b) the maximum speed of the glider. (c) what is the angular frequency of the oscillations?.
The maximum speed of the glider v = 4.75 m/s. the amplitude of the motion 2.12 cm. the angular frequency of the oscillations is approximately 2.86 rad/s.
To find the amplitude of the motion, we can use the equation for the potential energy of a spring:
Potential Energy = (1/2) * k * x^2
where k is the force constant of the spring, x is the displacement of the glider from its equilibrium point, and Potential Energy is the potential energy of the spring.
In this case, the force constant of the spring is 155 n/m, the displacement of the glider from its equilibrium point is 3.00 cm, and the potential energy of the spring is unknown. Plugging these values into the equation above, we get:
Potential Energy = (1/2) * 155 n/m * (3.00 cm)^2
This simplifies to:
Potential Energy = (1/2) * 155 n/m * 9.00 cm^2
This further simplifies to:
Potential Energy = 693.5 n cm
The potential energy of the spring is equal to the kinetic energy of the glider, so we can use the equation for kinetic energy to solve for the maximum speed of the glider:
Kinetic Energy = (1/2) * m * v^2
where m is the mass of the glider and v is its speed.
In this case, the mass of the glider is 175 g, and its speed is unknown. Plugging these values into the equation above, we get:
(1/2) * 175 g * v^2 = 693.5 n cm
This simplifies to:
v^2 = 693.5 n cm / (1/2) * 175 g
This further simplifies to:
v^2 = 3960.7 g cm / 175 g
This simplifies to:
v^2 = 22.60 g cm
To find the maximum speed of the glider, we can take the square root of both sides of the equation:
v = √(22.60 g cm)
This simplifies to:
v = 4.75 m/s
To find the angular frequency of the oscillations, we can use the equation:
ω = √(k/m)
where ω is the angular frequency, k is the force constant of the spring, and m is the mass of the glider.
In this case, the force constant of the spring is 155 n/m, and the mass of the glider is 175 g. Plugging these values into the equation above, we get:
ω = √(155 n/m / 175 g)
This simplifies to:
ω = 2.86 rad/s
we can use the equation for kinetic energy to find the amplitude of the motion:
Kinetic Energy = (1/2) * m * v^2
where m is the mass of the glider and v is its maximum speed.
In this case, the mass of the glider is 175 g, and its maximum speed is 4.75 m/s. Plugging these values into the equation above, we get:
(1/2) * 175 g * (4.75 m/s)^2 = 693.5 n cm
This simplifies to:
(1/2) * 175 g * 22.60 g cm = 693.5 n cm
To find the amplitude of the motion, we can solve for x:
x^2 = 693.5 n cm / (1/2) * 155 n/m
This simplifies to:
x^2 = 4.5 cm^2
To find the amplitude of the motion, we can take the square root of both sides of the equation:
x = √(4.5 cm^2)
This simplifies to:
x = 2.12 cm
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If you were to get up out of your seat and walk to the office, then return and sit in your seat again what is your displacement?
Answer:
0
Explanation:
Displacement is the distance between the start and end point of your travel. If you start in your seat, and end up in your seat, your displacement is 0.
76.9kg male and 44.4kg female pair figure skating team gliding across the ice at 7.26 m/s preparing for a throw jump maneuver. The male skater tosses the female skater forward with a speed 8.83 m/s . Determine the speed of male skater after the throw .
The speed of male skater after the throw will be 6.35 m/s.
What is momentum?The relationship between a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction.
Given that 76.9kg male and 44.4kg female pair figure skating team gliding across the ice at 7.26 m/s.
the female skater is tossed forward with a speed 8.83 m/s .
Let the speed of male skater after the throw = v m/s.
From principle of conservation of momentum,
Total initial momentum = total final momentum
⇒ (76.9 + 44.4) × 7.26 = 76.9×v + 44.4×8.83
⇒ 76.9×v = (76.9 + 44.4) × 7.26 - 44.4×8.83
⇒ v = 6.35 m/s.
Hence, the speed of male skater will be 6.35 m/s.
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the amount of internal energy needed to raise the tempreture of .25kg of water by 0.2C is 209.3 J. how fast must a 0.25 kg baseball travel in order for its kinetic energy to equal this internal energy?
help me!
Answer:
Explanation:
To find the speed at which a 0.25 kg baseball must travel in order to have kinetic energy equal to 209.3 J, you will need to use the formula for kinetic energy, which is:
KE = 1/2 * m * v^2
Where KE is the kinetic energy, m is the mass of the object, and v is the speed of the object.
To solve for v, you will need to rearrange the equation to solve for v:
v = sqrt(2 * KE / m)
Plugging in the values given in the problem, we get:
v = sqrt(2 * 209.3 J / 0.25 kg)
Solving this equation gives us a speed of approximately 29.3 meters per second. This is the speed at which the 0.25 kg baseball must travel in order to have kinetic energy equal to 209.3 J.
I hope this helps!
a body is thrown up from a wall of height 2.2m with a speed of 10ms^-1 the distance travelled in the last second of its motion
Answer:
To solve this problem, we need to use the equations of motion for an object undergoing uniformly accelerated motion. Specifically, we can use the equation for the displacement of an object in the vertical direction:
y = y0 + v0t + 1/2at^2
where y is the displacement of the object, y0 is the initial displacement (in this case, the height of the wall), v0 is the initial velocity (in this case, 10 m/s), t is the time elapsed, and a is the acceleration (in this case, the acceleration due to gravity, which is approximately 9.81 m/s^2).
To find the distance travelled in the last second of motion, we need to find the displacement of the object at t = 1 s, and subtract the displacement at t = 0 s (which is the initial displacement). Substituting these values into the equation above and solving, we get:
y1 = 2.2m + 10m/s * 1s + 1/2 * 9.81m/s^2 * 1s^2 = 12.61 m
y0 = 2.2m
The distance travelled in the last second of motion is therefore y1 - y0 = 12.61 m - 2.2 m = 10.41 m.
Explanation:
the mass of a golf ball is 45.9 g . if it leaves the tee with a speed of 69.0 m/s , what is its corresponding wavelength?
The golf ball has a wavelength of 2.3281034m. The distance between identical points (adjacent crests) in adjacent cycles of a waveform signal carried in space or along a wire is defined as the wavelength.
This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).
A matter wave is connected with all moving particles with mass. These matter waves are referred to as deBroglie waves.
A particle's deBroglie wavelengths is given by, where h is the Planck's constant, m is the mass of the ball, and v is its velocity.
Calculate the deBroglie wavelength of a moving golf ball by substituting 6.6261034J s for h, 45.9103kg for m, and 62.0 m/s for v.
The golf ball has a wavelength of 2.3281034m.
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which is the correct answer
it stop flies from sitting on the food
what is the answer of this question
Answer:
Option C as it stops flies from sitting on the food
On a graph of galaxy colors and luminosities, spiral galaxies are usually found in the ____________.
On a graph of galaxy colors and luminosities, spiral galaxies are usually found in the blue cloud.
any of the star systems and interstellar materials that make up galaxys. Hundreds of billions of stars can be found in several of these massive assemblages.
From dim, hazy dwarf objects to magnificent spiral-shaped giants, nature has created a vastly diverse assortment of galaxies. Almost all galaxies seem to have formed shortly after the universe started, and they can be found everywhere throughout space, even in the deepest regions that are beyond the reach of even the most potent contemporary telescopes. Galaxies typically exist in groups called clusters, some of which are then combined into larger clusters with a diameter of hundreds of millions of light-years. (A light-year is a distance traveled by light during one year at a speed of 300,000 km/sec or 650,000,000 mph.)
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