Answer:
its a. and jusing that youl
part g a transmitter on the earth's surface radiates sinusoidal radio waves equally in all directions above the ground. an airplane flying directly over the radio station at an altitude of 11.5 km measures the wave from the station to have electric-field amplitude 0.360 v/m. find the magnetic-field amplitude measured by the airplane. express your answer with the appropriate units. templatessymbols undoredoresetkeyboard shortcutshelp bmax
After solving the equation the amplitude of magnetic field is 1.2× 10^-9 T.
What is amplitude of magnetic field?
Amplitude of magnetic field is a measure of the strength of the magnetic field. It is measured in units of Tesla (T) or gauss (G). The magnetic field is produced by electric currents, the movement of charged particles, or the spin of an atomic nucleus. The amplitude of the magnetic field depends on the source, the amount of current, and the distance from the source. The Earth's magnetic field has an amplitude of approximately 30-60 microtesla (0.3 - 0.6 mG). At the surface of the Earth, the magnetic field is strongest near the poles, where it can reach over 65 microtesla (0.65 mG). In space, magnetic fields can reach amplitudes of up to 40,000 microtesla (400 G).
The distance between airplane and transmitter, R = 11.5 km
Amplitude of electric field, E = 0.360 v/m.
Amplitude of magnetic field, B = E/c
= 0.36 /3 × 10^8
= 1.2× 10^-9 T
Hence the amplitude of magnetic field is 1.2× 10^-9 T.
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The magnetic-field amplitude measured by the airplane 1.2× 10^-9 T
What is magnetic field?
The magnetic field is the area where the force of magnetism acts on a magnetic material or a moving electric charge. In order to impose a force on other adjacent moving charges and magnetic dipoles, moving electric charges and magnetic dipoles form a magnetic field.
The maximum field strength of the electric and magnetic fields can be found in electromagnetic waves by measuring their amplitude. The amplitude of the wave determines its energy.
The distance , R = 11.5 km
Electric field amplitude, E = 0.360 v/m.
Magnetic field amplitude, B = E/c
= 0.36 /3 × 10^8
= 1.2× 10^-9 T
So the amplitude of magnetic field is 1.2× 10^-9 T
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A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 3 feet/sec. How fast is the top of the ladder moving down the wall when the base of the ladder is 7, 15, and 24 feet from the wall?
The velocity of the ladder when the base of the ladder is 7, 15, and 24 feet from the wall is -0.875, -2.25, and -10.286 respectively.
Given, the length of the ladder= 25 ft
Let x be the distance between the wall and the ladder and h be the height of the ladder from the ground
x² + h² = (25)²
x² +h²= 625
h²= 625- x²
h= [tex](625- x^{2})^{1/2}[/tex]
[tex]\frac{dh}{dx}[/tex] = [tex]\frac{1}{2}[/tex] [tex](625- x^2)^{-1/2} * (-2x)[/tex]
[tex]\frac{dh}{dx}[/tex] = [tex]\frac{-x}{\sqrt{ (625-x^2)}}[/tex]
We have dx/dt= 3 ft/sec
Therefore, by applying the chain rule, we can get the value of dh/dt as:
dh/dt= dh/dx *dx/dt
=[tex]\frac{-x}{\sqrt{ (625-x^2)}}*3[/tex]
=[tex]\frac{-3x}{\sqrt{ (625-x^2)}}[/tex]
Now substituting the different values of x in the acquired equation
When x= 7, dh/dt= [tex]\frac{-7}{8}[/tex] ft/sec= -0.875 ft/sec
When x= 15, dh/dt= [tex]\frac{-9}{4}[/tex] ft/sec= -2.25 ft/sec
When x= 24, dh/dt= [tex]\frac{72}{7}[/tex] ft/sec= -10.286 ft/sec
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A 12-N net force
acts on a 4-kg jug of water. What is the
resulting acceleration of the jug? Show your
calculations.
Answer:
The resulting acceleration of the jug is 3 m/s^2.
Explanation:
To calculate the resulting acceleration of the jug, we need to use the equation F = ma, where F is the force applied to the object, m is the mass of the object, and a is the acceleration of the object.
Plugging in the values given in the question, we get:
F = ma
12 N = (4 kg) * a
Solving for a, we get:
a = F/m
a = (12 N) / (4 kg)
a = 3 m/s^2
Therefore, the resulting acceleration of the jug is 3 m/s^2.
consider the follwing discussion between two students working on this tutorial regarding the relationship between parallax angle and the distance we measure to a star
Due to the fact that a star's parallax angle and distance are inversely related, I concur with student 2 and disagree with student 1. The farther away the star is, the smaller the parallax angle is.
Student 1: That's not necessarily true. It's true that the triangle in the diagram would be pointier for a star that is farther away, but the parallax angle depends on the ratio of the distance between the Earth and the star to the distance from the star to the edge of the solar system.
Student 2: But if the star is farther away, then the distance between the Earth and the star will be larger, which means the parallax angle will be smaller.
Student 1: Not necessarily. Remember that the distance from the star to the edge of the solar system is also increasing. If the distance from the star to the edge of the solar system increases more quickly than the distance between the Earth and the star, then the ratio of these two distances will decrease, which means the parallax angle will actually increase.
Student 2: Oh, I see what you mean. So it's possible for the parallax angle to increase as the distance to a star increases.
Student 1: That's correct. It's important to consider both the distance between the Earth and the star and the distance from the star to the edge of the solar system when determining the parallax angle.
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Question- Consider the following debate between two students regarding the relationship between parallax angle and the distance we measure to a star.
Student 2: If we drew a diagram for a star that was much more than 1 parsec away from us, the triangle in the diagram would be pointier than the one we just drew in Part II. That should make the parallax angle smaller for a star farther away.
T/F copernican astronomers believed that the earth orbited the sun and rotated on its own axis, while ptolemaic astronomy held that it was motionless.
Insofar as the Copernican cosmos differed from the Ptolemaic universe, the assertion about how it did so is correct.
Why is Ghost missing from Motionless in White?Devin "Ghost" Sola, a bassist for Motionless in White, is no longer with the band. The group revealed that Sola had split ways amicably and had decided to go to the next phase of his career in a statement posted on social media. 2011 saw Sola's band debut.
Motionless: What is it used for?He was on the ground, unmoving. He briefly held her in his arms while appearing to dance without moving. He remained immobile and with his eyes closed after being placed on his camp bed for a considerable amount of time.
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at one particular moment, a 17.0 kg toboggan is moving over a horizontal surface of snow at 4.40 m/s. after 6.75 s have elapsed, the toboggan stops. use a momentum approach to find the magnitude of the average friction force (in n) acting on the toboggan while it was moving.
The magnitude of the provided average friction force F (in n) which is acting on the toboggan during it was moving is 8.66 N
What is a toboggan in the USA?Toboggan is a long flat-bottomed light sled composed usually of thin boards curved up at one end with usually low handrails at the sides. : a downward course as well as a sharp decline.
Solution:Given:
vi = 4.1 m/s
vf = 0
Δv = v final - v initial
= 0 - 4.1 = -4.1 m/s
Δ momentum i.e mΔv = (19 kg).(-4.1 m/s)
= 77.9 kgm/s
The average friction force (Ff) takes 9 seconds to take the toboggan to a end point, hence, impulse = Ft
= Ff(9)
Impulse is = Δ momentum, so
Ff(9) = 77.9;
Ff = 8.66 N
Is a beanie and a toboggan the same thing or not ?Touque, Toque and Tuque is in fact the same wool which has a Beanie with three distinct spellings. And at last but not at least in the southern American states , Toboggan is the name used for a wool knitted hat that is worn during the colder months of the year.To know more about toboggan visit
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(round to tenth) 1. How much power is required to do 40.3 J of work on an object in 5.5 seconds?
Answer:
7.3 W (watts)
Explanation:
Power = Work / time
P = W/t = 40.3J / 5.5 s = 7.3 W
A roller coaster car is released from rest at the top of the first rise and then moves freely with negligible friction. The roller
coaster shown in Fig. P7.62 has a circular loop of radius R in the vertical plane. (a) First, suppose the car barely makes it around the
loop; at the top of the loop the riders are upside down and feel weightless. Find the required height of the release point above the bottom
of the loop, in terms of R. (b) Now assume that the release point is at or above the minimum required height. Show that the normal force
on the car at the bottom of the loop exceeds the normal force at the top by six times the weight of the car. The normal force on each rider
follows the same rule. Such a large normal force is dangerous and very uncomfortable for the riders. Roller coasters are therefore not
build with circular loops in vertical planes. Figure P5.24 and the photograph on page 134 show two actual designs.
a) Height is calculated as = 5R/2 b) It is shown that the normal force on the car at the bottom of the loop exceeds the normal force at the top by six times the weight of the car.
What is meant by normal force?The force that surfaces exert to prevent solid objects from passing through each other is known as the normal force .
a) At point A, PE = m g h
At point B, PE = 1/2 * m * (vB)²
At point C, PE = m(vC)²/R - mg
m is mass vB is velocity at B
vC= √mgR/m = √gR
For conservation of energy at point C and B
1/2 * m * (vB)² + 1/2 * m * (vC)² + mg (2R) ( height of c = 2R)
(vB)² = gR + 2(2gR)
So, vB = √5gR
Conservation of energy between point A and B,
1/2 * m * (vB)² = mgh
Height, h = 5R/2
b) Normal force at topmost point C is
= m(vC)²/R - mg
Normal force at bottom point B is
= mg + m (vB)²/R
NB = mg + m(5gR)/R
= 6 mg
Therefore, we can say that NB > NC
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When an RLC-circuit is connected to a constant voltage E at time t=0, the current I in the circuit can be solved from the differential equation L⋅d^2I/dt^2+R⋅dI/dt +I/C=0 Where resistance R, inductance L and capacitance C are constants. Solve the equation with the initial conditions I(0)=0 and dI/dt(0)=E/L and assuming that (R/2L)^2−1/LC<0 I(t)=?
By dividing each side of the voltage triangle by its current, I, an impedance triangle for a series RLC circuit can be created. The source voltage is equal to I*Z, the voltage across the two reactive elements is I×X = I×XL – I*XC, and the voltage drop across the resistive element is equal to I*R.
What RLC-circuit is connected to a constant voltage?At resonance, the impedance, Z, is at its lowest value, (=R), because the current flowing through a series resonance circuit is the product of voltage divided by impedance.
Therefore, the circuit current will be at its maximum V/R value at this frequency.
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explain the difference between a ligand-gated k channel and a voltage-gated k channel. match the words in the left column to the appropriate blanks in the sentences on the right. make certain each sentence is complete before submitting your answer. resethelp 1. the ligand-gated channel opens or closes in response to blank .target 1 of 2 2. the voltage-gated channel opens or closes in response to blank .
The voltage-gated ion channels allows permeation of only one type of ion whereas, ligand-gated channels are less selective and allows permeation of two or more types of ions via the channel pore.
What is the difference between ligand-gated and voltage gated K channels?Ligand-gated ion channels are integral membrane proteins that contain a pore which allows regulated flow of selected ions across plasma membrane. Voltage-gated potassium channels are transmembrane channels specific for potassium and are sensitive to voltage changes in the membrane potential of cell .
1. Ligand-gated channel opens or closes in response to blank the binding of a ligand.
2. Voltage-gated channel opens or closes in response to differences in membrane potential.
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Consider the ballistic pendulum collision. The projectile, of mass m, is fired into a large block of mass M Derive a formula for the fraction of the magnitude of kinetic energy lost Express your answer in terms of the variables m and M Evaluate the fraction for m = 18.0 g and M = 380 g . Express your answer using three significant figures..
A massive block of known Mass is struck by the projectile, which has mass m. The amount of kinetic energy wasted as a percentage is 0.955.
Describe mass.A quantitative representation of inertia, the fundamental property of all matter. In essence, it describes the resistance of a body of theory to altering its movement or location in reaction to the applied load. More and more volume a body has, the less the change brought on by an external load is.
The mass formula is what?The average concentration (M), which is a physical property, is the same mass as one mole of a hazardous chemical or the ratio of the quantities of a psychoactive compound to its own amounts of pollutants.
Briefing:kinetic energy lost = change KE/KE
=1-m/(m + M)
=0.955.
momentum,
mv = (m + M)*V
V=m(1/( M + m))v
kinetic energy lost,
ΔKE / KE
= 1-m (1 / (m + M)
ΔKE/KE = 1-18(1/(18+380)
ΔKE/KE = 0.955
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What happens when a loop of wire turns between two permanent magnets in
a generator?
A. A current flows through the loop of wire.
B. Mechanical energy transforms into electromagnetic radiation.
C. Electrical energy transforms into mechanical energy.
D. A current flows through the permanent magnets.
Answer:
A. A current flows through the loop of wire.
Explanation:
When a loop of wire turns between two permanent magnets in a generator, a current flows through the loop of wire. This is because the movement of the wire through the magnetic field of the permanent magnets causes the electrons in the wire to move, which creates an electric current. This process is known as electromagnetic induction, and it is the principle behind the operation of generators.
In the annual battle of the dorms, students gather on the roofs of Jackson and Walton dorms to launch water balloons at each other with slingshots. The horizontal distance between the buildings is 35.5 m, and the heights of the Jackson and Walton buildings are, respectively, 15.5 m and 22.5 m. Ignore air resistance.
(a) The first balloon launched by the Jackson team hits Walton dorm 2.2 s after launch, striking it halfway between the ground floor and the roof. Find the direction of the balloon's initial velocity. Give your answer as an angle measured above the horizontal.
(b) A second balloon launched at the same angle hits the edge of Walton's roof. Find the initial speed of this second balloon.
The basic kinematic equations for horizontal and vertical motion are as follows:
s = v₀t + ¹/₂at²
Horizontal motion is:
x = v₀ₓt + ¹/₂aₓt²
x = v₀ₓt
x = v₀ cosαt
Because there is no air resistance: x = v₀ cosθt
Vertical motion is:
y = v₀[tex]__y[/tex]t + ¹/₂a[tex]__y[/tex]t²
y = v₀ sinαt - ¹/₂gt²
Solve both for the velocity trigonometric function term as follows:
y = v₀ sinαt - ¹/₂gt²
v₀sinαt = ¹/₂gt² + y
v₀sinα = ¹/₂gt² + y/t
and
x = v₀ cosαt
v₀cosα = x/t
Now divide these two equations and we get
v₀sinα/v₀cosα = tanα [tex]=\frac{1/2gt + \frac{y}{t} }{\frac{x}{t} }[/tex]
tan α [tex]= \frac{1/2gt + \frac{y}{t} }{\frac{x}{t} } = \frac{gt^2}{2x} + \frac{y}{x}[/tex]
tan α [tex]= \frac{gt^2}{2x} + \frac{y}{x}[/tex]
Enter a value, x is the distance between the boarding 35.5 m, and y is the difference between the launch height and the drop point. The launch height is 15.5 m and the landing height is 11.0 m, so y = -4.5 m. Finally, we are told the projectile travel time is 2.2 s.
tan α [tex]= \frac{gt^2}{2x} + \frac{y}{x}[/tex]
tan α [tex]= \frac{(9.8)(2.2)^2}{2(35.5)} + \frac{-4.5}{35.5}[/tex]
tan α [tex]= 0.668 - 0.126[/tex]
tan α [tex]= 0.542[/tex]
α = tan⁻¹ 0.542
α = 28.4°
For the second launch, y₂ is +7.0 m launch altitude is still 15.5 m, but the deployment altitude is now 22.5 m, and x is still 35.5 m. The angle remains 28.4°. This time we don't know the flight time or initial velocity we are asked to find. Using horizontal distances, we can solve for time.
x = v₀.cosα.t
t² = x/v₀.cosα
Now do it for y₂:
y₂ [tex]= v_0sin(\alpha) t - 1/2gt^2[/tex]
y₂ [tex]= v_0sin(\alpha) (\frac{x}{v_0cos(\alpha)} ) - 1/2g (\frac{x}{v_0cos(\alpha)} )^2[/tex]
y₂ [tex]= x tan (\alpha ) - \frac{gx^2}{2v_0cos(\alpha)^2}[/tex]
[tex]\frac{gx^2}{2v_0cos(\alpha)^2} = x tan (\alpha ) - y_2[/tex]
We need to solve v₀:
[tex]\frac{gx^2}{2v_0cos(\alpha)^2} =\frac{1}{ x tan (\alpha ) - y_2}[/tex]
2v₀cos (α)² [tex]= \frac{gx}{ x tan (\alpha ) - y_2}[/tex]
v₀² [tex]= (\frac{1}{2cos(\alpha)^2} ) \frac{gx}{ x tan (\alpha ) - y_2}[/tex]
v₀² [tex]= (\frac{x^2}{cos(\alpha)^2} ) \frac{g/2}{ x tan (\alpha ) - y_2}[/tex]
v₀² [tex]= (\frac{x}{cos(\alpha)^2} ) \sqrt{ \frac{g/2}{ x tan (\alpha ) - y_2}}[/tex]
Now we can enter values:
v₀² [tex]= (\frac{x}{cos(\alpha)^2} ) \sqrt{ \frac{g/2}{ x tan (\alpha ) - y_2}}[/tex]
v₀² [tex]= (\frac{35.5}{cos(28.4^0)} ) \sqrt{ \frac{9.8/2}{ 35.5 tan (28.4^0) - 7.0}}[/tex]
v₀² = 40.386 [tex]\sqrt{\frac{4.9}{12.17} }[/tex]
v₀² = 40.386 (0.634)
v₀² = 25.62 m/s
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A square meter of the axon membrane has a resistance of 0.2 ohms. The membrane is 7.5 x 10‐⁹ m thick. What is the resistivity of the membrane?
Answer:
using the formula
Resistance=Resistivity × length/area
Area=1 ,Resistance(R)=0.2ohm ,resistivity(P)=? ,length=7.5×10^-9
R=Pl/A
Pl=RA
P=RA/l
P=0.2×1/7.5×10^-9
P=0.027×10^9
P=2.7×10^7ohmsmeter
The resistivity of the membrane is 2.7×10⁷ ohm-meter.
What is resistivity?
Electrical resistance of a conductor with a unit cross-sectional area and unit length is called resistivity. Resistivity is a distinctive attribute of any material that may be used to compare different materials based on how well they conduct electric currents. Low conductivity is indicated by high resistance.
Mathematically the relation between resistance and resistivity can be written as:
Resistance=Resistivity × length/area
Given parameters:
Area of the membrane: A=1 m²
Resistance(R)=0.2ohm ,
resistivity(ρ)=?
length=7.5×10^-9 m.
Now:
R=ρl/A
⇒ρl=RA
⇒ρ=RA/l
⇒ρ=0.2×1/7.5×10⁻⁹
⇒ρ=0.027×10⁹
⇒ρ=2.7×10⁷ ohm-meter.
Hence, the resistivity of the membrane is 2.7×10⁷ ohm-meter.
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One mole of oxygen gas is at a temperature of 30°C. If the gas is heated at constant volume until the pressure triples, what is the final temperature?
A. 60°C B. 50°C C. 363 K D. 423 K
The final temperature is 909 K or 636° C.
What is Gay-Lussac's law?According to Gay-Lussac's law, the pressure that a gas (with a given mass and maintained at a fixed volume) exerts varies directly with the gas's absolute temperature.
Initial temperature of the gas: T₁ = 30⁰ C = 273 + 30 K = 303 K.
Initial pressure of the gas = P₁ = P
Final pressure of the gas = P₂ = 3P
Final temperature of the gas: T₂ = ?
Now from Gay-Lussac's law;
T₁/P₁ = T₂/P₂
T₂ = T₁P₂/P₁
= 303 K × 3P/P
= 3 × 303 K
=909 K
Hence, the final temperature is = 909 K = 636° C.
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suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen but the violet lines are at 424nm and 400nm instead of the usual 434nm and 410nm. from this evidence, you can conclude that the star is
Star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen but the violet lines are at 424nm and 400nm instead of the usual 434nm and 410nm. from this star is Moving towards us.
Information about a star's temperature, chemical make-up, and inherent luminosity can be found in its spectrum. A series of photographs taken at various wavelengths of the slit in the star's light make up spectrograms produced by slit spectrographs. Astronomers can identify an element by its spectral lines, as well as its temperature and density within the star. The magnetic field of the star can also be shown via the spectral line. How quickly the material is travelling can be determined by the line's width. This teaches us something about the winds in stars. The object is also referred to as the "Seven Sisters" and Messier 45, and its English name comes from a Greek tale. The Pleiades are seven of Atlas, the Titan deity, and the Pleiades' daughters.
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DUE TODAY MIDNIGHT PLEASE HELP!!!!
Describe the process involved in the tip to tail addition of vectors.
Via moving one vector so that its tail sits on the tip of the first vector, you may add by the tip-to-tail approach. New vector drawn from first vector's origin to the second vector's arrow is the resulting vector, A+B, or the sum of the two.
What is the process of vector addition?The head of the first vector must meet the tail of the second vector in order for two vectors to be added together, according to the triangle law of vector addition. We may thus acquire the resulting sum vector by connecting the head of the second vector to the tail of the first vector.The vector's terminal point is the arrow's tip, and its starting point is the arrow's tail. A vector whose magnitude is 0 is known as the zero vector. The only vector without a clear direction is this one.The parallelogram law of vector addition and the triangle law of vector addition are the two different forms of vector addition.Learn more about vector addition refer to :
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the sun goes down, and over all these barren reaches by the tide such unelusive glories fall, i almost dream they yet will bide 5until the coming of the tide
The passage is describing the beauty of Acadie, a place that is home to the speaker. This passage is from Bliss Carman's "LOW TIDES" .
The sun is setting, and the speaker is captivated by the beauty of the landscape, which is enhanced by the unelusive glories of the tide. The speaker also reflects on a beloved face being gone for a long time and is moved by a grievous stream, which meanders through the fields of Acadie as if it is trying to figure out why the beloved face is gone. The speaker almost dreams that the beauty of the place will remain until the beloved face returns. The passage conveys a sense of longing and hope for the beloved to come back to Acadie.
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when a hurricane moves onto land, it rapidly declines because of friction and lack of warm, moist air. t/f
False, supposedly when a hurricane moves ashore, it quickly rises due to friction and a lack of warm, moist air.
Hurricanes are known as cyclones as well as typhoons in other tropical regions. Typhoons are one of the most disturbing types of natural disasters at the moment.
Scientifically, the cause of hurricanes from warm water, warm moist air, and light upper-level winds as the primary ingredients of their formation.
Typhoons have other terms, depending on where they occur. the scientific term for a hurricane is a tropical cyclone. Only tropical cyclones that form over the Atlantic Ocean or the eastern Pacific Ocean are called "hurricanes".
The cause of a hurricane occurs when a warm, moist air mass from the sea surface begins to rise rapidly and collides with a colder air mass. The friction pushes the warm water vapor to condense. During the condensation process, latent heat is emitted.
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A box of mass m slides up a ramp with initial velocity +0. The kinetic friction force on the box has magnitude f. Which of the following is a correct equation that could be used to determine the acceleration a of the box? (A) -f=ma (B) mg sin 0 - - F=ma (C) f-mg sino 0 = ma
(D) -f-mg sino 0 = ma
The equation that could be used to determine the acceleration a of the box is (-f-mg sin 0 = ma)
What is kinetic friction force on inclined plane?If the direction of motion of the mass is up the plane, then the frictional force F will act down the plane.
Normal force N is exerted on the body by the plane due to the force of gravity i.e. mg cos θ. These two will be equal hence cancelled out.
Here, according to the question,
Box is moving up so, Force of friction is acting downwards and mg sin 0 is also acting downwards. Both are acting against the motion of the box so both terms will be negative i.e. (-f) and (-mg sin 0)
We know resultant force is equal to (ma)
So, (-f) + (-mg sin0) = ma
-f - mg sin0 = ma
The equation that could be used to determine the acceleration a of the box is (-f-mg sin 0 = ma)
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A wire carrying a 30.0 -A current bends through a right angle. Consider two 2.00 -mm segments of wire, each 3.00 cm from the bend (the figure ).uploaded imageA) Find the magnitude of the magnetic field these two segments produce at point P, which is midway between them.
B) Find the direction of the magnetic field at point P.
A) The magnitude of the magnetic field these two segments produce at point P is 1.95 nT B) Direction of the magnetic field is into the page.
What is Biot - Savart's law?An equation that describes the magnetic field generated by a constant electric current is called Biot –Savart law.
A) Given; A0 and B0 = 3cm
I= 30 A and l= 2mm
Bio Savart's law;
dB= μIdl sinФ/4πr
Ф = 45° as ΔAOB is an isosceles triangle and Q is the angle between I dL and r.
dB at point P due to 2mm is;
dB= [μIdl sin45°/4πr][1/(AP)² + 1/(BP)²]
= [μIdl sin45°/4πr] [1/(1/2 AB)²+ 1/(1/2 AB)²]
dB= [μIdl sin45°/4πr] [ 8/ (AB)²]
=[(4π * 10^-7 * 30 *2 *10^-3*1/√2)/ 4π] * 8/18
= 1.948 * 10^-9 T
dB = 1.95 nT
B) Direction of the magnetic field is into the page.
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04
Production methods to produce solar cells
06
Future trends in solar cells
The production methods to produce solar cells are as follows;
GenerationSeparationCollectionThe future trends in solar cells include:
introducing AIreducing costsimproved durabilityWhat are the production methods to produce solar cells?Solar cells are cells that use solar energy to produce electricity. These cells are also called voltaic cells.
The solar energy from the Sun is collected by these and then converted to electrical energy.
The production methods to produce solar cells include the following processes:
Generation - electron-hole pairs are generated due to the absorption of photons in a semiconductorSeparation - separation of electrons and holes to the n-sides and p-side respectively.Collection - electrons are collected by the front contact and holes are collected by the back contact leading to the separation of charges and production of photovoltage.Learn more about solar cells at; https://brainly.com/question/29729669
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Analyze physical activities from which derived cardiovascular activity and one strength training activity of moderate to vigorous intensity that can be performed by a person that works out 3 a week doing a of exercises the gym Explain why you chose these activities adults, and briefly describe the long-term of each activity
The physical activities from which derived cardiovascular activity and one strength training activity of moderate to vigorous intensity that can be performed by a person is by jogging, running etc.
What is Exercise?This is referred to as a type of physical activity which helps to keep am individual fit and improves the overall being snd examples include running, squatting etc.
Running was chosen as a form of activity which can be used as a form of cardiovascular activity and strength training activity of moderate to vigorous intensity.
A long-term of running is that it helps to strengthen the muscles and bones which are present in the individual and also improves the cardiovascular fitness which is therefore the reason why it was chosen as the correct choice.
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EXPLAIN THE MEASUREMENT PRINCIPLE OF ATOMIC SPECTROMETERS
Atomic absorption spectroscopy, often known as AAS or AA spectroscopy, is one of the earliest methods for elemental analysis to be established for the market.
What is Atomic Spectrometer?The analytical method known as flame atomic absorption spectroscopy (Flame AAS or FAAS) was first commercially released in the 1960s after being invented in 1952.
The method has been well-liked ever since for its dependability and simplicity. AAS is an analytical method for figuring out how much of a particular element is in a sample. It is based on the idea that atoms (and ions) may absorb light with a certain, distinct wavelength.
The atom absorbs the energy (light) when it is present at this particular wavelength. By absorbing energy (light) at a certain wavelength, an electron is stimulated from the ground state to a higher energy level.
Therefore, Atomic absorption spectroscopy, often known as AAS or AA spectroscopy, is one of the earliest methods for elemental analysis to be established for the market.
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in 2021, which of the following miscellaneous deductions remain deductible, and are not completely disallowed, although they may have been allowed as deductions subject to the 2 % percent of adjusted gross income (agi) limitation
Miscellaneous deductions subject to the 2% limit fall into the following three categories:
Un-reimbursed Employee ExpensesTax Preparation Fees Other expensesWhat are miscellaneous tax deductions?
Other individual deductions are deductions subject to the 2% Adjusted Gross Income (AGI) limit. You may claim certain expenses as personal deductions on Schedule A (Form 1040), Schedule A (1040-NR), or as income adjustments on Forms 1040 or 1040-SR.
In general, nonresident aliens in one of the eligible employment categories are entitled to deductions so long as they are directly related to income effectively related to the pursuit of trade or business in the United States.
Miscellaneous deductions subject to the 2% limit fall into the following three categories:
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Every winter morning when the sun is shining bright, a man living in Montana pulls back the drapes on a large, south-facing window. In this way, he helps heat his home using ________.
a. passive solar
b. active solar
c. photovoltaic
d. conductive solar
e. radioactive solar
Answer:
(b) active solar because the solar radiation passing thru the window will help to heat his room
A student is trying to determine the muzzle
velocity (initial) of a bullet that is too fast to
measure directly. The student fires the 0.05kg
bullet into a 4kg block of wood initially at rest.
After the collision, the block, with the bullet
embedded inside moves to the right with a
speed of 1.87m/s right.
before collision:
Pbullet
Pblock
after collision:
Pcombined
kg m/s
kg m/s
kg m/s
How fast was the bullet fired?
m/s
mu + MU = (m + M) V... eq (1)
given:
m=0.05 kg, M=3.5 kg, U= 0 and V=1.82 m/s.
put these numbers to equation (1)
0.05×u +0 =(0.05+3.5)×1.82
u=3.55×1.82 /0.05
u= 6.461/0.05
u=129.22m/s ...(2)
prior to a collision
Bullet: |p|bullet =mu =0.05129.22=6.461 kg/s
|p | block = MU=3.5×0 =0 kg.m/s
After collision
Combining, |p| equals (m+M)V = (0.05+3.5) 1.82 =6.461 kg.m/s.
Equation (2) shows the initial speed of the projectile.
=129.22 m/s.
what is collision?
Collision is defined as the meeting of two or more things with such force that both or all of them suffer harm or have their development significantly slowed.
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40k undergo beta decayed, electron capture, and positron decayed. write the equation for each of these nuclear reactions
The equation for each of these nuclear reactions is Nucleus A -> Nucleus B + beta particle (-1 charge) + neutrino (0 charge).
Beta decay is a type of radioactive decay in which an atomic nucleus emits a beta particle (an electron or a positron) and transforms into an atomic nucleus with one less atomic number and one more atomic mass. The equation for beta decay can be written as:
Nucleus A -> Nucleus B + beta particle (-1 charge) + neutrino (0 charge)
where Nucleus A is the parent nucleus, Nucleus B is the daughter nucleus, and the beta particle and neutrino are the products of the reaction.
Electron capture is a type of radioactive decay in which an atomic nucleus captures one of its own electrons and transforms it into an atomic nucleus with one less atomic number and the same atomic mass. The equation for electron capture can be written as follows:
Nucleus A + electron (-1 charge) -> Nucleus B + neutrino (0 charge)
where Nucleus A is the parent nucleus, Nucleus B is the daughter nucleus, and the neutrino is the product of the reaction.
Positron decay is a type of radioactive decay in which an atomic nucleus emits a positron (a positively charged particle with the same mass as an electron) and transforms into an atomic nucleus with one less atomic number and one less nuclear mass. The equation for positron decay can be written as:
Nucleus A -> Nucleus B + positron (+1 charge) + neutrino (0 charge)
where Nucleus A is the parent nucleus, Nucleus B is the daughter nucleus, and the positron and neutrino are the products of the reaction.
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Can anyone tell me what is new about atomic theory over the last 23 years?
Answer:
The modern atomic theory establishes the concepts of atoms and how they compose matter. Atoms consist of negatively charged electrons around a central nucleus composed of more massive positively charged protons and electrically neutral neutrons. The atomic model changes over time because the atomic model was based on theories and discoveries.
Explanation:
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three different forces are shown pulling on a heavy trapdoor. which force will have the biggest turning effect
The force that will have the biggest turning effect on the heavy trapdoor is the one that is applied the furthest from the pivot point, or the point around which the trapdoor rotates.
How does Force have effect on Heavy Trapdoor?The farther a force is from the pivot point, the greater the lever arm is, and the greater the turning effect it will have. For example, if there is a force being applied to the edge of the trapdoor, it will have a larger turning effect than a force being applied closer to the pivot point. Similarly, a force being applied to the top of the trapdoor will have a larger turning effect than a force being applied to the bottom.
It's also important to consider the magnitude of the forces being applied. If one force is much larger than the others, it will have a greater turning effect, even if it is applied closer to the pivot point.
It's worth noting that the forces acting on the trapdoor may be balanced, meaning that they cancel each other out and do not cause the trapdoor to rotate. In this case, the trapdoor will remain in its current position.
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