Assume y≠60 which expression is equivalent to (7sqrtx2)/(5sqrty3)

Assume Y60 Which Expression Is Equivalent To (7sqrtx2)/(5sqrty3)

Answers

Answer 1

Answer:

The equivalent will be:

[tex]\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)[/tex]

Therefore, option 'a' is true.

Step-by-step explanation:

Given the expression

[tex]\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}[/tex]

Let us solve the expression step by step to get the equivalent

[tex]\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}[/tex]

as

[tex]\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}[/tex]      ∵ [tex]\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}[/tex]

[tex]\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0[/tex]

[tex]=x^{2\cdot \frac{1}{7}}[/tex]

[tex]=x^{\frac{2}{7}}[/tex]

also

[tex]\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}[/tex]         ∵  [tex]\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}[/tex]

[tex]\mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0[/tex]

[tex]=y^{3\cdot \frac{1}{5}}[/tex]

[tex]=y^{\frac{3}{5}}[/tex]

so the expression becomes

[tex]\frac{x^{\frac{2}{7}}}{y^{\frac{3}{5}}}[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}[/tex]

[tex]=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)[/tex]            ∵ [tex]\:\frac{1}{y^{\frac{3}{5}}}=y^{-\frac{3}{5}}[/tex]

Thus, the equivalent will be:

[tex]\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)[/tex]

Therefore, option 'a' is true.


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Answers

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Step-by-step explanation:

Step one:

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