Find the multiplicative inverse of −1/2.

The solution to the systems are (1, 1), (-3, -1), (1, -2), (2, -1), (7, -1) and (-2, 2)

System 1

In this case, the system of equations is given as

y = -3x + 4

y = 3x - 2

Next, we plot the graph of the system of equations

In this case, the point of intersection of the equations represent the solution to the system

From the graph, the lines intersect at (1, 1)

So, the solution is (1, 1)

System 2

In this case, the system of equations is given as

y = x + 2

x = -3

Next, we plot the graph of the system of equations

In this case, the point of intersection of the equations represent the solution to the system

From the graph, the lines intersect at (-3, -1)

So, the solution is (-3, -1)

System 3

In this case, the system of equations is given as

4x + y = 2

x - y = 3

Next, we plot the graph of the system of equations

In this case, the point of intersection of the equations represent the solution to the system

From the graph, the lines intersect at (1, -2)

So, the solution is (1, -2)

System 4

We have

y = 4x - 9

y = x - 3

Substitute y = 4x - 9 in y = x - 3

4x - 9 = x - 3

Evaluate the like terms

3x = 6

So, we have

x = 2

Recall that:

y = x - 3

So, we have

y = 2 - 3

y = -1

So, the solution is (2, -1)

System 5

We have

x + 7y = 0

2x - 8y = 22

Make x the subject in x + 7y = 0

x = -7y

Substitute x = -7y in 2x - 8y = 22

-14y - 8y = 22

Evaluate the like terms

-22y = 22

So, we have

y = -1

Recall that:

x = -7y

So, we have

x = -7(-1)

x = 7

So, the solution is (7, -1)

System 6

We have

-7x + 2y = 18

6x + 6y = 0

Make x the subject in 6x + 6y = 0

x = -y

Substitute x = -y in -7x + 2y = 18

7y + 2y = 18

Evaluate the like terms

9y = 18

So, we have

y = 2

Recall that:

x = -y

So, we have

x = -2

So, the solution is (-2, 2)

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Answer:

[tex]E[/tex]ach pajama costs $32

Step-by-step explanation:

So, the said person bought:

2 slippers at a price, 3 pajamas at another price. (The prices are unknowns, s, and p)

Each slippers cost $12

We are to find the cost of each pajama, where the total purchase price is $120

With the given conditions, we formulate an equation: 2s + 3p = 120

Since s = 12, we replace for the value of s in the equation. s becomes 2 × 12 = 24.

The new equation is then: 24 + 3p = 120, where we are to find the value of p.

Collect like terms: 3p = 120 - 24 → 3p = 96

Divide both sides of the equation by 3 to find the value of p: 3p/3 = 96/3 → p = 32

Therefore, the price of each pajama is $32

The probability that at most 195 of those purchases are paid with a credit or debit card i.e P(X ≤ 195 ) is 0.9625..

We have given that,

Sample size , n=250

Sample proportion, p= 73.2% = 0.732

np = 183

n(1-p) = 67

both np & n(1-p) values are greater than 5, So normal approximation is applicable

mean, µ = np = 183

std. dev, σ = √np(1-p) =√250×0.732 ×(1-0.732) =7.0031

we have to calculate probability that at most 195 of those purchases are paid with a credit or debit card i.e P(X ≤ 195 )

= P( X < 195.5 )

= P((x - µ) / σ < (195.5 -183)/ 7.0031)

= P( Z < 1.78 )

= 0.9625

Required probability using Excel function ,

Excel command: =NORM.S.DIST(z,1)

= Norm.S.DIST(1.78,1)

= 0.9625

Hence, required probability is 0.9625..

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Answer:

They are equivalent ratios because if you multiply 10 to 2 by 2.5 you get 25 to five

Answer:

equals 25

Step-by-step explanation:

In a case whereby In 1950, a U.S. population model was y = 151. (1.013)^t-1950 million people, where t is the year, the model predict the U.S. population would be 288 million in the year 2000.

Population models are mechanical theories that link alterations in population structure and density to responses at the individual level (life history features in eco-evolutionary theory or vital rates in demographic theory).

The model was given as y=151x(1.013)^t-1950

where the future time t = 2000

Then we can substitute the given year 2000 as the value of 't'

then we will have y=[151x(1.013)^(2000-1950)] = 288 million

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This is a SAS situation, only one triangle is possible. Then the correct option is C.

The polygonal shape of a triangle has a number of sides and three independent variables. Angles in the triangle add up to 180 °.

In triangle ΔABC, the angle ∠A is 22°. And the measure of the side BC is 18.9 cm and the measure of the side AC is 15.1 cm.

To fix a triangle, the known dimensions of the triangle should be three which one must be a side.

This is a SAS circumstance, just a single triangle is conceivable. Then the right choice is C.

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Based on the following question the primary sources of a problem using the 80/20 rule, wherein 80 percent of defects often come from only about 20 percent of all the sources is false

Only 20% of causes result in 80% of all consequences, according to the 80/20 rule. It is used to pinpoint the crucial elements of success (often in a corporate context) and concentrate efforts therein to enhance outcomes.

According to the 80-20 rule, 20% of activities produce 80% of the consequences. Or, to put it another way, just 20% of the input results in 80% of the outcome. An old proverb that promotes focus is the 80-20 rule, often known as the Pareto Principle.

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The slope and y-intercept, or the points, should be used to graph the line.  Slope: 3 y-intercept: (0, 1 )

g ( x ) = − 3 x − 1

Create an equation using the function.

y = − 3 x − 1

Calculate the slope and y-intercept using the slope-intercept form.

Less steps by tapping...

In the slope-intercept form, y = m x + b denotes the slope and the y-intercept, respectively.

y = m x + b

With the use of the formula y = m x + b, determine the values of m and b.

m = − 3 b = − 1

m is the line's slope, and is the value of the y-intercept.

B. Slope: 3 Y-intercept: (0, 1 )

Two points are all that are required to graph any line. To determine the associated y values, enter two x values into the equation.

Less steps by tapping...

Assign the x and y values to a table.

x     y

0   − 1

1    − 4

The slope and y-intercept, or the points, should be used to graph the line.

Slope: 3 y-intercept: (0, 1 )

x        y

0        1

1         4.

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Part (a)

Given data table.

[tex]\begin{array}{|c|c|} \cline{1-2}t & T\\\cline{1-2}0 & 81\\\cline{1-2}5 & 69\\\cline{1-2}10 & 60.5\\\cline{1-2}15 & 54.2\\\cline{1-2}20 & 49.3\\\cline{1-2}25 & 45.4\\\cline{1-2}30 & 42.6\\\cline{1-2}\end{array}[/tex]

where,

It's unfortunate that T is used twice for these variables. It might cause some confusion.

This is what happens when we subtract 24 from each temperature.

[tex]\begin{array}{|c|c|} \cline{1-2}t & T-24\\\cline{1-2}0 & 57\\\cline{1-2}5 & 45\\\cline{1-2}10 & 36.5\\\cline{1-2}15 & 30.2\\\cline{1-2}20 & 25.3\\\cline{1-2}25 & 21.4\\\cline{1-2}30 & 18.6\\\cline{1-2}\end{array}[/tex]

The graph of each set of points is shown in figure A. I used GeoGebra to make the graph.

The first set of data points are in red. The second set in blue. Notice the set of blue points is the result of shifting the red points 24 units down.

The green exponential model is also shown as the curve through the set of red points.

The green regression exponential model doesn't go through each point perfectly. Rather it tries to get as close as possible.

To go from

T-24 = 54.4(0.964)^t

to

T = 54.4(0.964)^t + 24

we simply add 24 to both sides. This means there isn't much to show in terms of steps when solving for T.

=======================================================

Part (b)

Use spreadsheet technology or something like GeoGebra to generate this data table.

[tex]\begin{array}{|c|c|} \cline{1-2}t & ln(T-24)\\\cline{1-2}0 & 4.043051\\\cline{1-2}5 & 3.806662\\\cline{1-2}10 & 3.597312\\\cline{1-2}15 & 3.407842\\\cline{1-2}20 & 3.230804\\\cline{1-2}25 & 3.063391\\\cline{1-2}30 & 2.923162\\\cline{1-2}\end{array}[/tex]

The values in the 2nd column are approximate.

Then plot each of those points on the same xy grid. Use technology of your choice to determine the regression line is roughly

y = -0.03723x + 3.99739

So we can say

ln(T-24) = -0.03723t + 3.99739

the right hand side fits the format at + b where

both of which are approximate.

Then,

e^(ln(T-24)) = e^(at+b)

T-24 = e^(at+b)

T-24 = e^(-0.03723t + 3.99739)

T-24 = e^(-0.03723t)*e^(3.99739)

T-24 = e^(-0.03723t)*54.45583

T-24 = 54.45583*e^(-0.03723t)

T = 54.45583*e^(-0.03723t) + 24

T = 54.456*e^(-0.037t) + 24

Let's verify that this is equivalent to the model found in part (a).

T = 54.456*e^(-0.037t) + 24

T = 54.456*(e^(-0.037))^t + 24

T = 54.456*(0.963676)^t + 24

T = 54.5*(0.964)^t + 24

which is very close to the model mentioned in part (a). There's some slight rounding error. That's to be expected in problems like this.

-----------------------------

Answer: T = 54.456*e^(-0.037t) + 24

See figure B for the graph. Like with the other regression curve, this straight line doesn't go through all of the points. It tries to get as close as possible.

=======================================================

Part (c)

Refer to the 2nd table mentioned in part (a).

We'll apply the reciprocal to each item in the column labeled T-24.

For instance, the item 57 becomes 1/57 = 0.017544 approximately.

This is what the data table looks like:

[tex]\begin{array}{|c|c|} \cline{1-2}t & 1/(T-24)\\\cline{1-2}0 & 0.017544\\\cline{1-2}5 & 0.022222\\\cline{1-2}10 & 0.027397\\\cline{1-2}15 & 0.033113\\\cline{1-2}20 & 0.039526\\\cline{1-2}25 & 0.046729\\\cline{1-2}30 & 0.053763\\\cline{1-2}\end{array}[/tex]

The values in the 2nd column are approximate.

The set of points and regression line are shown in figure C1. This line does not go through all of the points. Like with the others, it tries to get as close as possible to each point.

Use technology to determine the equation of the regression line is approximately:

y = 0.00121x + 0.01613

Which tells us that

1/(T-24) = 0.00121t + 0.01613

Let's solve for uppercase T.

1/(T-24) = 0.00121t + 0.01613

T-24 = 1/(0.00121t + 0.01613)

T = 1/(0.00121t + 0.01613) + 24

T = 1/(0.0012t + 0.0161) + 24

which is the approximate final answer.

Figure C2 shown below represents the original data points (t, T) in red. The blue curve is y = 1/(0.0012x+0.0161)+24, which is the rational regression curve we just found. This curve tries its best to get as close as possible to each red point.

Compare the regression curves of figure A and figure C2. We have a very close tie in terms of which curve does a better job of fitting the original data.

Answer:

Step-by-step explanation:

To solve this problem, we need to calculate Martha's out-of-pocket expenses, and the total amount of money she had to pay for her medical bills.

First, we need to calculate the amount of money Martha had to pay toward her deductible. Since her deductible is $200, this is the amount she had to pay out of pocket.

Next, we need to calculate the amount of money Martha had to pay toward her co-payment. Since her co-payment is 20%, we can calculate this by multiplying her medical bills by the co-payment rate: $6,500 x 0.2 = $1,300.

To find Martha's total out-of-pocket expense, we can add the amount she paid towards her deductible ($200) and the amount she paid towards her co-payment ($1,300):

$200 + $1,300 = $1,500

Therefore, Martha's out-of-pocket expense was $1,500.

Martha's insurance required her to pay a $200 deductible and a 20% co-payment on the remaining balance of her medical bills. After paying the deductible, she pays 20% of the remaining $6,300 which is $1,260. So, Martha's total out-of-pocket expense was $1,460.

Martha's health insurance plan includes a $200 deductible and a 20% co-payment. The deductible is the amount Martha has to pay before the insurance company starts to pay. In this case, Martha first pays a $200 deductible from her $6,500 medical bills, which leaves her with $6,300 to be covered by insurance and her co-payment. The 20% co-payment means Martha is responsible for paying 20% of the remaining $6,300. To calculate this, we multiply $6,300 by 0.20 (20%), which equals $1,260. Therefore, Martha's total out-of-pocket expense for her medical bills last year was the $200 deductible plus the $1,260 co-payment, equalling $1,460.

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Explanation:

You can make use of the properties of parallel lines to prove ∠ACB≅∠DAC.

Statement . . . . Reason

2. ∠DAB +∠ABC = 180° . . . . definition of a right angle

3. AD║BC . . . . consecutive interior angles are supplementary

4. ∠ACB≅∠DAC . . . . alternate interior angles are congruent

The number of times a large popcorn without butter is sold is, 49.

The conditional relative frequency of no.of Item2 sold given that

50% off is 0.27.

Conditional probability is a term used in probability theory to describe the likelihood that one event will follow another given the occurrence of another event.

The number of times a large popcorn without butter is sold is,

= 49.

The total no. of items that is 50% off is (12 + 20 + 32) = 74.

The no. of Item2 which is 50% off is 20.

So, The conditional relative frequency of no.of Item2 sold given that 50% off is,

= 20/74.

= 0.27.

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Answer:

[tex] \huge{ \boxed{x = 3}}[/tex]

Step-by-step explanation:

[tex] {x}^{2} - 6x + 9 = 0[/tex]

Using the quadratic formula that's,

[tex] \bold{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}} \\ [/tex]

Comparing the equation to the general form of a quadratic equation ( ax² + bx + c), we have.

[tex]a = 1 \\ b = - 6 \\ c = 9[/tex]

Substituting the values into the formula we have.

[tex]x = \frac{- ( -6) \pm \sqrt{( - {6})^{2} - 4(1)(9) } }{2(1)} \\ x = \frac{6 \pm \sqrt{36 - 36} }{2} \\ x = \frac{ 6 \pm\sqrt{0} }{2} \\ x = \frac{6}{2} \: \: \: \: \: \\ \\ x = 3 \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

Answer:

The answer is approximately 770 bacteria after 3 hours.

Answer:

|
|
|
∆∆∆∆∆∆∆∆∆∆∆∆∆∆

Step-by-step explanation:

get better

The 95% confidence interval for this population proportion is (0.10, 0.23).

A confidence interval is a range of values that are constrained by the statistic's mean and that are likely to include an unidentified population parameter. The proportion of likelihood, or certainty, that the confidence interval would include the real population parameter when a random sample is drawn several times is referred to as the confidence level.

Sample size n = 125

number of people who planned to take an extended vacation = 21

sample proportion p = 21/125 = 0.168

Confidence level = 0.95

significance level α = 1-0.95 = 0.05

Z score =[tex]Z_{\alpha 2}[/tex] = Z(0.05) = 1.96, from Z table.

The confidence interval for population proportion is-

p±[tex]Z_{\alpha 2}[/tex] x √{p(1-p)}/n =0.168±1.96 x 0.168 x √{(1-0.168)}/125

                        =0.168±1.96 x 0.0334

                        =0.168±0.0655

                        =(0.1025, 0.2335)

                        =(0.10, 0.23)

Therefore, the confidence interval is (0.10, 0.23).

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The probability of needing to catch 8 fish to get the first salmon is D) 0.2 (0.8)^7.

How to calculate probability of needing to catch 8 fish to get the first salmon?

Given that he probability of fishing a salmon in a certain river is 20% i.e. 0.2. Now, the probability of not getting a salmon will be

1 - probability of not getting salmon  = 1 - 0.2 = 0.8.

So, the first fish should be salmon and the others should not be salmon. So, the required probability of independent events can be calculated as,

P =0.2×0.8×0.8×0.8×0.8×0.8×0.8×0.8×0.8

P = 0.2× (0.8)^7

Hence,the probability of needing to catch 8 fish to get the first salmon is 0.2 (0.8)^7.

The probability of needing to catch 8 fish to get the first salmon is D) 0.2 (0.8)^7.

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Answer:

Equation of side AB:

We know the coordinates of A and B, so we can use the point-slope form to create the equation of the line:

y - 3 = (3/5)(x - 5)

y - 3 = 3/5x - 15/5

5/3y - 15/3 = x - 5

5/3y - x = -15/3 + 5

5/3y - x + 15/3 = 5

5/3y - x + 15/3 = 0

Equation of side AB: 5/3y - x + 15/3 = 0

Equation of side DC:

We know the coordinates of C and D, so we can use the point-slope form to create the equation of the line:

y - 1 = (2/5)(x - 10)

y - 1 = 2/5x - 20/5

5/2y - 10 = x - 10

5/2y - x = -10

5/2y - x - 10 = 0

Equation of side DC: 5/2y - x - 10 = 0

Equation of side BD:

We know the equation of side BC (x - 2y = 8) and that consecutive sides are perpendicular, so we can use the slope-intercept form to find the equation of line BD:

Slope of BC = -2/1

Slope of BD = -1/-2 = 1/2

y = (1/2)x + b

We can use the coordinates of B to find b:

1 = (1/2)(8) + b

2 = 4 + b

b = -2

Equation of side BD: y = (1/2)x - 2

Step-by-step explanation:

∠SWV is congruent to ∠TWU because vertically opposite angle.

If one of the geometric figures can be superimposed on the other so that their entire surface coincides, then the two are said to be congruent, or to be in the relation of congruence. Two triangles are said to be congruent if their two sides and their included angle are the same in both of them. Congruence appears to be based on the concept of a "rigid body," which may be transported from one location to another without affecting the internal relationships between its components.

Given

∠SWV ≅ ∠TWU

Vertically opposite angle

∠SWV is congruent to ∠TWU because vertically opposite angle.

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The function h is defined, for all real numbers h(-3) = -1/2 , h(2) = -2 and h(4) = -4.

What is a function ?

When it comes to arithmetic, a function is represented as a rule that produces a different result for each input x. Mathematicians refer to functions as mapping or transformations.

The given function,

h(x) =  -1/2 x^2 + 4 if x≠ 2

                 -2         if x=2

So, h(-3) = -1/2 (-3)^2 + 4

             = - 9/2 + 4

             = -1/2

     h(2) = -2 ( given )

     h(4) = -1/2 (4)^2 + 4

            = -8 + 4

            = -4 .

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x3y2 is the result of the expression employing the common factor (x - 6y).

Here,

The sentence is,

x⁴y² - 6x³y³

We must use the common factor to solve.

Mathematical expression refers to the combining of numbers and variables utilizing the operations addition, subtraction, multiplication, and division.

Now,

The sentence is,

x⁴y² - 6x³y³

The common factor is used to solve as,

6x3y3 - x4y2 equals x*x*x*y*y - 6*x*x*x*y*y.

= x³y² (x - 6y) (x - 6y)

Consequently, x3y2 is the value of the expression employing the common factor (x - 6y).

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a.The formula that describe the sequence or progression is a+(7-7n)

b. 2nd term = -10 , 3rd term = 10, 4th term = -10 and 5th term = 10

Geometric Progression (GP) is a type of sequence where each succeeding term is produced by multiplying each preceding term by a fixed number, which is called a common ratio.

Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value. It is also called Arithmetic Sequence.

The nth term of an arithmetic progression is given as a(n)= a + (n − 1) × d

In geometric progression the nth term is given as a(n)= ar^(n-1)

where a is the first term

therefore if a = 12 and d is - 7

the formula for the arithmetic progression =

a(n) = 12+(n-1) -7 = 12+( 7-7n)

If the first term of a GP is 10 with common ratio of -1

then the second term = 10×-1 = -10

third term = -10×-1 = 10

fourth term = 10×-1 = -10

fifth term = -10× -1 = 10

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Answer:

Step-by-step explanation:

okay so its 3•7

that's all u need put that

Answer:

[tex]3^{7}[/tex]

Step-by-step explanation:

3×3×3×3×3×3×3= [tex]3^{1+1+1+1+1+1+1+1} =3^{7}[/tex]

3+3+3+3+3+3+3= 3×7

Answer:

x = 40

Step-by-step explanation:

since lines PQ and BC are parallel , then

∠ BCQ and ∠ AQP are corresponding angle and are congruent , that is

∠ BCQ = 80°

the sum of the 3 angles in Δ ABC = 180° , then

x + 80 + 60 = 180

x + 140 = 180 ( subtract 140 from both sides )

x = 40

The indefinite integral is - 1 / [5(6 + [tex]x^{5}[/tex])] + C.

An integral is considered to be indefinite if it has no upper or lower bounds. In mathematics, the most generic antiderivative of f(x) is known as an indefinite integral and expressed by the expression f(x) dx = F(x) + C. Without upper and lower bounds on the integrand, indefinite integrals are stated using the notation f(x), which represents the function as an antiderivative of F. Consequently, "f(x) dx=F" (x). As we observed in the same example with antiderivatives, the integral, x3 dx=14x4+C, is one example.

The area under the f(x) curve from x=a to x=b is represented by the definite integral of f(x), which is a NUMBER. Integral indefinite. An indefinite integral of a function f(x), also known as an antiderivative, is denoted by and its derivative is denoted by f. (x). The indefinite integral is not the only solution because the derivative of a constant is zero. Integration is the action of locating an indefinite integral.

Use a u-substitution with u = (6 + [tex]x^{5}[/tex])

du = 5[tex]x^{4}[/tex]dx

1/5 ∫ [tex]u^{-2}[/tex]du

= -1/5 [tex]u^{-1}[/tex] + C

= - 1 / [5(6 + [tex]x^{5}[/tex])] + C

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Correct Question:

Find the indefinite integral and check the result by differentiation. (Use C for the constant of integration.)

[tex]\int\limits^ {} \frac{x^{4} }{(6+x^{5})^{2} } dx[/tex]

I don't see the full picture but your answer should look like this:

4ab+(-12ab)+9ab+(-5ab)

= 4ab-12ab+9ab-5ab

= (4-12+9-5)ab

= -4ab

Answer:

Step-by-step explanation:

-2 * -10 = 20

Answer:

30×2×(-10)-5+2

=60×(-10)-3

=-60-3

=-63

They like best brand C) A: 11%; B: 16%; C: 34%; D: 39%.

What is probability ?

Probability is simply how likely something is to happen. Whenever we're unsure about the outcome of an event, we can talk about the probabilities of certain outcomes—how likely they are. The analysis of events governed by probability is called statistics.

Have given ,

Ida made four brands A , B , C and D

Mostly students like A brand 11% , B brand 16% , C brand 34% and D brand 39%

So this is best brand like by students male and female

They like best brand C) A: 11%; B: 16%; C: 34%; D: 39%.

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When constructing a confidence interval for a population mean the Degrees of freedom is 11 and critical value is 1.717

Degrees of freedom = df = n - 1 =12 - 1 = 11

At 90% confidence level the t is ,

α = 1 - 90% = 1 - 0.90 = 0.1

α / 2 = 0.1 / 2 = 0.05

tα /2, df = t0.05,22 = 1.717 ( using student t table)

The level of confidence denotes the likelihood that the position of a statistical parameter (such as an arithmetic mean) in a sample survey is also true for the population.

A critical value is the test statistic's value that establishes a confidence interval's upper and lower boundaries or a test statistic's threshold for statistical significance.

To learn more about the critical value

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