help please it needs to be don by 4:00​

The solution is

a) Option A.

The equation to determine the messages sent by Bria is t/4 = 20

b) Option C.

The student is 1.25 feet above sea level , and the absolute value is 1.25 ft

c) Option C.

The values are opposites of each other , and they are both 5/2 units from zero

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

a)

Let the number of texts sent by Bria be = t

The number of texts sent by April = 20

April sent one fourth of the texts sent by Bria

So ,

The number of texts sent by Bria t = 4 x number of texts sent by April

Substituting the values in the equation , we get

The number of texts sent by Bria t = 4 x 20

Divide by 4 on both sides of the equation , we get

t/4 = 20   be equation (1)

And , t = 80 texts

Therefore , the number of texts sent by Bria is given by the equation

t/4 = 20

b)

Let the sea level be represented as = 0

The number 1.25 is above the sea level of 0

The absolute value of 1.25 is = 1.25

Therefore , the expression will be the student is 1.25 ft above the sea level and the absolute value is 1.25 ft

c)

Let the first number be = -5/2

Let the second number be = 5/2

Now , the difference of the numbers from the point zero = 5/2 units

Because the distances are always positive

The numbers -5/2 and 5/2 are opposite numbers

Hence , the expression will be the numbers are opposites of each other and they are 5/2 units from 0

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Answer:

y(x) = integral(6 c^2 - 20 x^3)/(5 x^2 + 3) dx = -2 x^2 + 1/5 log(5 i x + sqrt(15)) (-i sqrt(15) c^2 + 6) + 1/5 log(-5 i x + sqrt(15)) (i sqrt(15) c^2 + 6) + k_1, where k_1 is an arbitrary constant.

Step-by-step explanation:

Rewrite the equation to -((6 c^2 - 20 x^3) dx)/(3 + 5 x^2) + dy = 0 and solve

Solve (dy(x))/(dx) = (6 c^2 - 20 x^3)/(5 x^2 + 3):

Integrate both sides with respect to x:

Answer: y(x) = integral(6 c^2 - 20 x^3)/(5 x^2 + 3) dx = -2 x^2 + 1/5 log(5 i x + sqrt(15)) (-i sqrt(15) c^2 + 6) + 1/5 log(-5 i x + sqrt(15)) (i sqrt(15) c^2 + 6) + k_1, where k_1 is an arbitrary constant.

The number of visits Jim must make to make Plan A the cheaper option is 6 and 5 visits will cost the same.

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

Suppose n number of visits will make plan A cheaper than B.

The total cost of A <  total cost of B

50 + 10n < 25 + 15n

15n - 10n > 50 - 25

5n > 25

n > 5

n = 6

At n = 5

Total cost of A = 50 + 10 x 5 = $100

Total cost of B = 25 + 15 x 5 = $100

Hence "Jim needs to visit 6 times, and 5 visits will cost the same, for Plan A to be more affordable".

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Answer:

0, zero product property

Step-by-step explanation:

Answer:

∠ b = 108° , ∠ d = 72°

Step-by-step explanation:

(a)

the sum of the 3 angles in a triangle = 180° , that is

∠ a + ∠ b + ∠ c = 180°

25° + ∠ b + 47° = 180°

∠ b + 72° = 180° ( subtract 72° from both sides )

∠ b = 108°

(b)

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles , then

∠ d = ∠ a + ∠ c = 25° + 47° = 72°

Answer:

190

Step-by-step explanation:

500x0.38=190

I just see it that way

Answer:

length and breadth

Step-by-step explanation:

Since the pipeline has to be laid along the boundary of the garden, we need to know the perimeter of the garden. Here, the two variables necessary are length (l) and breadth (b). Hence we need to know the length and breadth in order to find the total length of the garden

Answer:

Step-by-step explanation:

To find the total length of the pipe needed to lay a pipeline along the boundary of a garden, you would need to know the following information:

The shape of the garden: The total length of the pipe needed will depend on the shape of the garden. For example, a rectangular garden will require less pipe than a circular garden of the same size.

The dimensions of the garden: Knowing the dimensions of the garden (such as its length, width, and perimeter) will allow you to calculate the total length of the pipe needed.

The diameter of the pipe: The length of the pipe needed will depend on the diameter of the pipe being used. A larger diameter pipe will require more length than a smaller diameter pipe.

The spacing between the pipes: If the pipes are being laid side by side, the total length of the pipe needed will depend on the spacing between the pipes. If the pipes are being laid end to end, the spacing between the pipes will not affect the total length of the pipe needed.

Any curves or corners in the garden: If the garden has curves or corners, the total length of the pipe needed will be greater than if the garden were a straight line. You will need to account for the additional length needed to bend the pipes around the curves or corners.

Answer:

x ≥ 2.3

Step-by-step explanation:

Product means multiplication

10x ≥ 23  Divide both sides by 10

x ≥ 2.3

Answer:190 small packs and 4 cookies left over

Step-by-step explanation:

Add the boxes of cookies together 105+22=127

Multiply each box by 12

127 x 12=1524

Because we need to put them into smaller packs of 8 cookies

we need to divide by 8

1524÷8=190 small boxes

This is a total of 190 x 8=1520 cookies there are 4 cookies left over

Answer:

x is -7.5 or -14/2 or -7½

Step-by-step explanation:

- Supposing y varies directly with x

[tex] { \tt{y \: \alpha \: x}} \\ \: \: \: \: { \tt{y = kx}} [/tex]

[k is a constant of proportionality (k ≠ 0)]

- When y is 6, x is -2

[tex] \: \: \: \: \: \: \: \: \: { \tt{6 = (k \times ^{ - }2) }} \\ { \tt{6 = - 2k}} \\ { \tt{k = - 3 \: \: }}[/tex]

- Therefore, the equation is;

[tex]{ \boxed{ \tt{y = - 2x}}}[/tex]

- What is x when y is 15

[tex]{ \tt{15 = - 2x}} \\ { \tt{x = - 7.5}}[/tex]

The value of x is -5

The equation for a direct variation is y = kx, where k is the constant of variation. Since we know that y = 6 when x = -2, we can solve for k:

                                        k = y/x

                                        k = 6/-2

                                        k = -3

Therefore, the equation for this direct variation is y = -3x. To find x when y = 15, Substitute k = -3 and y = 15 into the equation

                                15 = -3x

Then solve x,

                       x = [tex]\frac{-15}{3}[/tex]

                        x = -5

Therefore, when y = 15, x = -5.

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The value of the function h(x) = f(x) – g(x) will be h(x) = log5(x) – x³ – 11. The correct option is D.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a cryptographer uses a combination of two functions to develop the initial "key” in a sequence of coded numbers. The functions are:

f(x) = log5(x) – 8

g(x) = x³ + 3

The value of the function h(x) = f(x) - g(x) is,

h(x) = f(x) - g(x)

h(x) = log5(x) – 8 - x³ - 3

h(x) = log5(x) – 8 - x³ - 11

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Answer:

D. h(x) = log5(x) – x3 – 11

Step-by-step explanation:

The inequality equation of the given description of the inequality graph is;  3x - 2y < 7

Given :

X range is negative 10 to 10, and Y range is negative 10 to 10.

Dotted line on graph has positive slope and runs through points: (-3,-8), (1,-2), and (9,10).

Now, since we know the coordinates through which the graph runs, we can pick two coordinates and use it to find the slope through the formula;

m = (y₂ - y₁)/(x₂ - x₁)

If we pick (-3,-8), (1,-2), we have;

m = (-2 - (-8))/(1 - (-3)

m = 6/4

m = 3/2

We will use formula for equation of a line in point slope form to get;

y - y₁ = m(x - x₁)

y - 10 = (3/2)(x - 9)

2y - 20 = 3x - 27

3x - 2y = 7

Because, above the line is shaded, therefore, the correct inequality matching the graph is 3x - 2y < 7

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On solving the provided question, we can say that -  correlation coefficient , r= .95

The Pearson's correlation coefficient, also known as the Pearson's r, Pearson's product-moment correlation coefficient, bivariate correlation, or simply correlation coefficient, is a statistical indicator of the linear relationship between two sets of data.

[tex]S_{xx}[/tex] = ∑[tex]x^2[/tex] + [tex]nx^2[/tex] = 60

[tex]S_{yy} = 60[/tex]

r  = .95

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The Answers for the four parts are

a)  5-9+7-6=-3

b) -8 + 12-9-2=-7

c) 10-3-5 + 11 =13

d)  −2+2+7+8= 15

Integers come in three types:

Given:

a)  5-9+7-6

= -4 +7-6

= 3-6

=-3

So, the value of 5-9+7-6 is (-3).

b) -8 + 12-9-2

= 4-9-2

= -5-2

=-7

So, the value of -8 + 12-9-2 is (-7).

c) 10-3-5 + 11

= 7-5+11

= 2+11

=13

So, the value of  10-3-5 + 11 is (13).

d)  −2+2+7+8

= 0+7+8

= 7+8

= 15

So, the value of −2+2+7+8 is (15).

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The Translation of the Attached Question:

Solve as in the example

Answer:

Tan(f) = 24/7

Step-by-step explanation:

Tan is opposite over adjacent.

The opposite of angle F is 24 and the adjacent is 7.

Answer:

a. x = 1/4

b. x = [tex]+\sqrt{6}[/tex], [tex]-\sqrt{6}[/tex], 1/4

Step-by-step explanation:

a. I factorised the polynomial.

[tex]g(x) = 4x^3 - x^2 -24x +6 = 0[/tex]

[tex]-x^2 (-4x + 1) +6 (-4x +1)[/tex]

[tex](-4x+1)(-x^2+6)[/tex]

  Solved for the roots.

[tex]-4x + 1 = 0[/tex]

[tex]-4x = -1[/tex]

[tex]x = \frac{1}{4}[/tex]

[tex]-x^2+6 = 0[/tex]

[tex]-x^2 = -6[/tex]

[tex]x^2 = 6[/tex]

[tex]x = +\sqrt{6}[/tex]

[tex]x=-\sqrt{6}[/tex]

A rational number is a real number that's digits terminate and/or repeat. Therefore, 1/4 is the only rational zero.

b. All of the zeros we found in part A. are [tex]+\sqrt{6}, -\sqrt{6}, and \frac{1}{4}[/tex]

The proportion to calculate triangle side LM in the given triangle is 3/2

The side LM is calculated using the idea of similar triangle, in this case the triangles are equal in proportion to each other

To find the proportion we take the ratio of the sides this is done as follows

LM / HJ = MN / JK = LN / HK

substituting the values

MN / JK = 9 / 6 = 3 / 2

the proportion is = 3/2

to find LM

4.5 * 3/2

= 6.75 cm

Using proportion of 3/2 the length of side LM is solved to be 6.75 cm

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The value of  m/JHI and m/GHI is  angle 19 and 46.

What is  angle ?

An angle is a figure in Euclidean geometry made up of two rays that share a common terminal and are referred to as the angle's sides and vertices, respectively. Angles created by two rays are on the plane where the rays are located. The meeting of two planes also creates angles. Dihedral angles are these.

[tex]\begin{aligned}2 x+7+8 x-2 & =65 \\10 x+5 & =65 \\10 x & =60 \\x & =6\end{aligned}[/tex]

m/JHI =(2x+7) = (2* 6+7)=12+7=19.

m/GHI = (8x - 2)° = (8*6-2)=48-2=46

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Answer:

d=9

Step-by-step explanation:

42 km is 2 of the 3 legs

51 is the total triathlon

51 - 42 = 9

Answer:

  a) v(t) = 30600 -1440t

  b) 8 years

Step-by-step explanation:

You want an equation that models the value of a car that is initially $30,600 and falls at the rate of $1440 per year. Then you want the number of years it takes for the value to fall to $19,080.

Since the rate at which the value falls is a constant, we can use a linear equation for the model. Its form will be ...

  value = initial value - (depreciation per year) × years

  v(t) = 30,600 -1440t

The time it takes for the value to fall to 19080 can be found by solving for t:

  19080 = 30600 -1440t

  1440t = 30600 -19080 = 11520

  t = 11520/1440 = 8

After 8 years the car's value will be $19,080.

Step-by-step explanation:

the expected value is the sum of all values multiplied by their corresponding probabilities.

and a probability is always

desired cases / totally possible cases.

in the bag are

28 + 6 + 1 = 35 marbles

the probability to pull the gold is

1/35

the probability to pull a silver is

6/35

the probability to pull a black is

28/35 = 4/5

the expected value = $3×1/35 + $2×6/35 - $1×28/35 =

= 3/35 + 12/35 - 28/35 =

= -13/35 = -0.371428571... ≈

≈ -$0.37

that means (like with all games of that kind like all casino games) the bank will win in the long run.

your only chance to win is to play very few times and get a winner by pure chance. the longer you play you might actually hit a winner somewhere in between, but the surer you still lose in total.

Answer:

The tightened spot is 10 feet away from the foot of the pole.

Step-by-step explanation:

1. Draw the diagram. Notice that the shape of the electric pole and its supporting wire creates a right triangle.

2. We know 2 side lengths already (26ft, 24ft), and we need to find 1 more side length. Therefore, to find the 3rd side length of a right-triangle, utilize Pythagoras' Theorem.

⭐What is the Pythagoras' Theorem?

3. Substitute the values of the side lengths into the equation, and solve for the unknown side length.

Let B= the distance from the tightened spot to the foot of the pole.

[tex](C)^2 = (A)^2 + (B)^2[/tex]

[tex]26^2 = 24^2 + B^2[/tex]

[tex]676 = 576 + B^2[/tex]

[tex]100 = B^2[/tex]

[tex]\sqrt{100} = \sqrt{(B)^2}[/tex]

[tex]10 = B[/tex]

∴ The tightened spot is 10 feet away from the foot of the pole.

Diagram:

The recursion tree is log2m and has log2m nodes .

A recursive algorithm calls itself with smaller input values and returns the result for the current input by carrying out basic operations on the returned value for the smaller input.

A iterative method is a mathematical procedure that uses an initial value to generate a sequence of improving approximate solutions for a class of problems, in which the n-th approximation is derived from the previous ones.

In the analysis of algorithms, the master theorem for divide-and-conquer recurrences provides an asymptotic analysis for recurrence relations of types that occur in the analysis of many divide and conquer algorithms.

Two integers x and y are given. x and y require n bit and m bit respectively. Two algorithms to compute x y need to be analyzed.

Iterative: The pseudocode for this algorithm is as follows.

product = x;

for i = 2 to y do

product = product * x

The result after the multiplication of two integers, one p bits long and another one q bits long requires p q bits to to store. Therefore, for a given i , we are multiplying one ( i − 1)n bits long integer with an n bit long integer. This multiplication cost is ( i − 1)n2 .

The resulting number after the multiplication is i.n bits long. Thus

adding up all the multiplication cost we get

n2 + 2n2 + 3n2 + . . . + (y − 1)n2. Thus the complexity of the iterative algorithm is O(n2y2) which exponential in

the input length of y which is m = log2 y.

Recursive: The pseudocode for this algorithm is as follows:

function recursive (x ,y)

if y is even then return (x(by2c))2

if y is odd then return x ∗ (x(by2)c)2.

Computing (x(by2c))2

requires a multiplication involving two y2

n bits integers. The cost of this operation is y24.n2 which is O(y2n2). The recurrence relation for this

recursive routine is

T(y) = O(n) when y is 1-bit long.

T(y) = T(y2) + O(y2n2) otherwise.

Applying the Master Theorem we can conclude that T(y) ∈ O(y2n2). The height

of the recursion tree is log2m and has log2m nodes.

Thus both the algorithms have the same worst case complexity.

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Two integers x and y are given. x and y require n bit and m bit respectively. Two algorithms to compute x y need to be analyzed.

product = x;

for i = 2 to y do

product = product * x

The result after the multiplication of two integers, one p bits long and another one q bits long requires p q bits to to store. Therefore, for a given i , we are multiplying one ( i − 1)n bits long integer with an n bit long integer. This multiplication cost is ( i − 1)n2 .

n2 + 2n2 + 3n2 + . . . + (y − 1)n2. Thus the complexity of the iterative algorithm is O(n2y2) which exponential in

the input length of y which is m = log2 y.

function recursive (x ,y)

if y is even then return (x(by2c))2

if y is odd then return x ∗ (x(by2)c)2.

Computing (x(by2c))2

requires a multiplication involving two y2

n bits integers. The cost of this operation is y24.n2 which is O(y2n2). The recurrence relation for this

recursive routine is

T(y) = O(n) when y is 1-bit long.

T(y) = T(y2) + O(y2n2) otherwise.

Thus both the algorithms have the same worst case complexity.