How does adding deionized water into a solution containing ions affect the electrical conductivity of the solution?.

The wavelength of these radio waves with a frequency 14GHz is equal to 0.0214m.

Microwave transmission is the transmission of information by using electromagnetic waves within the frequencies 1GHz to 300GHz are called microwaves.

The transmission of signals either directly or via a satellite by sending microwaves. The receivers for microwave signals are disc-shaped antennae and are often seen installed in business locations or near private homes.

The relationship between frequency (ν) and wavelength (λ) can be expressed as follow:

λ = c/ν

Given, the frequency of the radiowaves = 14 GHz

Change the frequency into (per second)  = 14 × 10⁹ s⁻¹

The wavelength of the radiowaves can be calculated from, λ = c/ν

where c = 3× 10⁸ m/s is the speed of light.

λ = c/ν = 3× 10⁸ m/s./ 14 × 10⁹ s⁻¹

λ = 0.0214 m

Therefore, the wavelength of these radio waves is equal to 0.0214m.

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To find the theoretical yield of the equation. First, identify the limiting reactant in a chemical equation.

Step 1: write out the equation and balance it.

Al+ 3mno2=3mn+ 2Alo3.

The limiting reactant is mn02 because it is not found in excess.

Step 2: convert the % to grams. All contain 47.2% mole and mno2 will be 100-47.2= 52.8

All=47.2÷100×250(total gram of the reactants)=118g

Mno2=52.8÷100×250g=132g.

Step 3:calculate the molar mass of mno2 and that of mn. The atomic mass of mn is 54.9380 and that of oxygen is 16.

Mno2=54.938+ (16)2=86.98g/mol.

Mn=54.938.

Step 4:

From your balanced equation, calculate mn.

132g mno2× (1mol mno2÷86.98(molar mass) of mno2×3 mol of mn/4molAl×54.938g of mn÷1mol of mn.

132g×1÷86.98g×3÷4×54.938÷1

=62.53g

What is the molar mass?

The molar mass of a chemical compound is defined in chemistry as the mass of a sample divided by the amount of substance, which is the number of moles in that sample, measured in moles. The molar mass of a substance is a bulk attribute, not a molecular property. The molar mass is an average of numerous instances of the compound, which often vary in mass due to isotopes present. The molar mass is most usually calculated from standard atomic weights and is thus a terrestrial average and a function of the relative abundance of the constituent atoms on Earth. For bulk quantities, the molar mass is ideal for converting between the mass of a substance and the amount of a substance.

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The percentage of the excess stereoisomer in the mixture c.25%.

Stereoisomerism, or spatial isomerism, is a form of isomerism wherein molecules have the same molecular components and series of bonded atoms, but fluctuate in the three-dimensional orientations of their atoms in space.

The observed rotation of the mixture is levorotary (terrible, counter-clockwise), and the precise rotation of the pure S enantiomer is given as dextrorotary (fantastic, clockwise), which means that the pure R enantiomer should be levorotary, and the mixture has to comprise extra of the R enantiomer than of the S enantiomer.

Enantiomers have the same chemical and bodily homes and are indistinguishable from every other except for the route of rotation of the plane of polarized mild. they're described as optically lively.

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Disclaimer:- your question is incomplete, please see below for the complete question.

the specific rotation of a pure substance is 10 degrees. a mixture of this substance and its enantiomer has an observed specific rotation of 2 degrees. what is the percentage of the excess stereoisomer in the mixture

a.50% b.75% c.25% d.0% e.80%

0.0351mol/L is the equilibrium constant, Kc of the given chemical reaction.

The value of a chemical reaction's reaction quotient at chemical equilibrium, a condition that a dynamic chemical system approaches when enough time has passed and at which its composition has no discernible tendency to change further, is the equilibrium constant for that reaction.

Given:

Initial no. of moles of NOCl = 2.5 moles

NOCl dissociated = 28%

total volume = 1.5 L

To find:

Equilibrium constant, Kc = ?

Formula:

Kc = [products] / [reactants]

Calculations:

(28/100) x 2.5 = 0.7 moles

[tex]2NOCl (g) \leftrightarrow 2NO (g) + Cl_2 (g)[/tex]

According to the above equation,

2 moles of NOCl will give 1 mole of [tex]Cl_2[/tex] and 2 moles of NO

Therefore, no. of moles of NO = 0.7 mol

No. of moles of [tex]Cl_2[/tex] = 0.35 mol

No. of moles of NOCl remaining after dissociation = 2.5 - 0.7 =1.8 mol

Molarity = no. of moles / volume

Therefore, Molarity of NO = 0.7 / 1.5 = 0.466M

Molarity of [tex]Cl_2[/tex] = 0.35 / 1.5 = 0.233M

Molarity of NOCl = 1.8 / 1.5 = 1.2M

Kc = [tex]([NO]^2 [Cl_2]) / [NOCL]^2[/tex]

Kc = [tex][(0.466)^2 (0.233)] / (1.2)^2[/tex]

Kc = 0.0351mol/L

Result:

The equilibrium constant, Kc of the given chemical reaction is found to be 0.0351mol/L.

The complete question is:

A 2.50 mol quantity of NOCl was initially in a 1.50L reaction chamber at 400℃. After equilibrium was established it was found that 28.0% of NOCl had dissociated.

[tex]2NOCl (g) \leftrightarrow 2NO (g) + Cl_2 (g)[/tex]

Calculate equilibrium constant Kc for the reaction.

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If we are to express the pressure of the gas in kilopaschal then we have  303.9 kPa

We define the pressure of the gas as the force with which the gas is able to bump or hit or collide against the walls of the container in which the gas has been stored. In this case, we have been given the pressure of the gas but the unit in which the volume have been given is the unit of the atmosphere and we are asked by the question to express the pressure in the unit of kilopascal.

We know that from the use of the conversion factors;

1 atm = 101.3 kPa

3 atm = 3 atm * 101.3 kPa/ 1 atm

= 303.9 kPa

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Answer:

Calculate the number of moles of gas present in the following gases, at room

temperature and pressure, RTP, (20°C and atmospheric pressure).

Answer:

binomial

Explanation:

because the fact that macromolecules is carry out with functions constant-1,2,3,4 etc

Answer: Protons and Electrons

Explanation:

Atoms are made up of 3 subatomic particles.

Protons (Positive Charge)

Electrons (Negative Charge)

Neutrons (Neutral Charge)

The number of protons must be equal to that of electrons in order for the overall charge to be neutral.

Following are the methods to unplug this drain without physically touching the blockage.

1. Pour hot, boiled water down a drain.

If you choose to attempt to clear a grease blockage on your own and you are certain that your plumbing system is made up of metal pipes rather than plastic, you might try flushing it out with hot water. If your pipes are constructed of plastic, we wouldn't recommend trying this because you run the risk of melting or weakening the joints.

2. Hot water and vinegar

A 50:50 solution of hot, boiling water and vinegar performs similarly to the commercial chemical drain cleaner (and is just as effective). The advantage of a homemade vinegar and water solution is that it is non-toxic and substantially less corrosive than commercial drain cleaners. Grease that has accumulated on the inside walls of your pipes is dissolved by warm water and vinegar. Give yourself another dose a few minutes later if the first dose doesn't work.

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Answer:

potential energy

Explanation:

they only store energy, so they’re not using it which would be kinetic energy.

The no. of moles of [tex]CH_4[/tex] remaining after the reaction is found to be 11.5 moles.

The no. of moles of a material equals the ratio of its given mass to the mass of one mole of that molecule in a chemical reaction.

The coefficients reflect the number of moles, not simply molecules, that react.

Stoichiometric coefficients are the numbers that come before the chemical formula of a molecule participating in a reaction. They assist us in determining the relative amounts or no. of moles of each reactant consumed and product created during a reaction.

[tex]CH_4 (g) + 2O_2 (g) \rightarrow CO_2 (g) + 2H_2O (g)[/tex]

No. of moles of [tex]CH_4[/tex] = 13.0 mol

No. of moles of [tex]O_2[/tex] = 3.0 mol

Here [tex]O_2[/tex] is limiting reagent because moles of [tex]O_2[/tex] is less.

Thus, [tex]CH_4[/tex] is in excess

1 mol [tex]CH_4[/tex] = 2 mol [tex]O_2[/tex]

x mol [tex]CH_4[/tex] = 3 mol [tex]O_2[/tex]

Moles of [tex]CH_4[/tex] used = 3 x 1 / 2 = 1.5 mol

Here we have 13 moles of [tex]CH_4[/tex],

Therefore,

No. of moles of [tex]CH_4[/tex] left = 13 - 1.5 = 11.5

Result:

11.5 moles of [tex]CH_4[/tex] will remain after the reaction.

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The total reactive power absorbed by the line is: 120-J 160 VA

Given that, a load of 30 - j 40 is connected to a source of 100 v with a phase angle of 30o , through a transmission line with an inductive reactance of 80 ohms.

[tex]current, $I=I_L=\frac{100 \angle 30^{\circ}}{30-j 40+j 80}=\frac{100 \angle 30^{\circ}}{30+j 40}$[/tex]

[tex]$=2 \angle-23.13^{\circ}$[/tex]

[tex]$\begin{aligned} V_L &=\left(100\left(30^{\circ}\right)-I(j 80)\right.\\ &=\left(100 < 30^{\circ}\right)-(2 L-23.13)(j 80) \\ &=100 L-76.26 \text { volts. } \end{aligned}$[/tex]

[tex]$\begin{aligned} \text { Power delivered toads }=& V_l I_L^* \\=&(100 < -76.26)(2 L-23.13)^* . \\=&(100 < -76.26)(1.839-j 0.786)^* \\ &=(100 < -76.26)(1.839+j 0.786) \\ &=(100 < -76.26)(2 L+23.13) \\ S &=120-j 160 \mathrm{VA} \end{aligned}$[/tex]

The component of complex power known as reactive power pertains to energy storage and retrieval rather than consumption. Real power, which really does work, and reactive power, which permits transformers to change, generators to produce, and motors to rotate, are the two types of power found in an AC power system.

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Answer: To me i think it’s “A” because one of the geological processes is

hydrothermal process which I think is also cooling down

If the volume of a sample of gas is doubled while holding the temperature of the gas constant, then the pressure of the gas is half the initial pressure.

The relationship between the volume and pressure of a gas is given by Boyle's law of gases.

The equation of Boyle's law of gases is given as follows:

P₁V₁ = P₂V₂

Where;

Solving for the final pressure of the gas;

V₂ = 2 V₁

P₂ = P₁ * V₁ / 2 V₁

P₂ = P₁ / 2

Hence, the final pressure is half the initial pressure.

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Average molar mass of sulfur is 32.80 g/mol

The average atomic mass of a chemical element is calculated by taking into account the atomic masses of its naturally occurring isotopes and their respective abundances

Here given data is

95.0% sulfur= 32 (31.97 amu)

0.75% sulfur= 33 (32.97 amu)

4.21% sulfur= 34 (33.96 amu)

We have to find average molar mass of sulfur = ?

Average molar mass = ∑i × isotope of i × abundance of i

Average molar mass = 31.97×95.0 + 32.97 ×0.75 + 33.96×4.21

Average molar mass = 32.80 g/mol

Average molar mass of sulfur is 32.80 g/mol

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When 224 g sample of water cools down from 56°C to 20°C with specific heat of water 4.184 J/g °C, the amount of heat energy lost is 33,739 J

Given that,

Mass (m) = 224 g

Specific heat (C) = 4.184 J/g ℃

Initial temperature = 56 ℃

Final temperature = 20 ℃

Heat energy = (mass) × (specific heat) × (change in temperature)

Q = m × C × ΔT

Q = 224 × 4.184 × (56 – 20)

Q = 224 × 4.184 × 36

Q = 33,739 J

Therefore, the heat energy that was lost in the process is 33,739 J

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Will HCl donates a proton and acts as an acid? Option C

Will water accept a proton and act as a conjugate base? Option F.

HCl is a Bronsted-Lowry acid because it is a proton donor, and H2O is a proton acceptor and Bronsted-Lowry base. Acids lose electrons and bases gain electrons. Acids and bases that work together in this way are called conjugate pairs, consisting of conjugate acid and a conjugate base.

Here we can see that the hydrogen ion moves from the HCl molecule to the H2O molecule, forming chloride and hydronium ions. As a hydrogen ion donor HCl acts as a Brønsted-Lowry acid. As a hydrogen ion acceptor H2O is a Brønsted-Lowry base. Bronsted acids are proton donors and thus donate H+. In this case, HCl is an acid because it donates its H+ to NH3. Lewis acids are electron acceptors. Acids are substances that can donate H+ ions to bases.

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The cloud of electrons surrounding the nucleolus of an atom takes up all the volume or space.

The simplest unit of matter is the atom. As matter makes up everything in the universe (apart from energy), atoms are the building blocks of matter.

The protons, neutrons, and electrons that make up an atom are three different types of incredibly small particles known as subatomic particles. The nucleus of the atom, which is made up of protons and neutrons, is where all the action happens, and an electron cloud flies around it.

In contrast to the protons, which have a positive charge, electrons have a negative charge. Both protons and electrons are equal in number in a typical (neutral) atom. The quantity of neutrons is also usually the same, though not always.

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The empirical formula of mesitylene is C₃H₄.

To solve this problem, we need to determine the molar ratio of carbon and hydrogen in mesitylene. We can do this by first calculating the masses of carbon and hydrogen in the sample. Because all the carbon in mesitylene is transformed into carbon dioxide, the mass of carbon in CO₂ will be equal to the mass of carbon in the mesitylene. All we need is the molar mass of carbon dioxide: 44 g/mol

12 g of carbon : 44 g of carbon dioxide = X : 0.379 g of carbon dioxide

X = 12 g of carbon * 0.379 of carbon dioxide / 44 g of carbon dioxide

X = 0.103 g of carbon

Because mesitylene is composed of just carbon and hydrogen, we can determine the mass of hydrogen by subtracting the mass of carbon from the mass of mesitylene:

0.115 g - 0.103 g = 0.012 g of hydrogen

Now we divide these masses by the molar masses of the elements:

0.103 g / 12 g/mol =0.009 mol of carbon

0.012 g / 1 g/mol = 0.012 mol of hydrogen

We divide the moles by the smaller of the two numbers to get the molar ratio:

0.009 mol / 0.009 mol = 1 for carbon

0.012 mol / 0.009 mol = 1.33 for hydrogen

Because we need the molar ratio to be in integers, we multiply both values by 3:

1 * 3 = 3 for carbon

1.33 * 3 = 4 for hydrogen

This means that the empirical formula of mesitylene is C₃H₄.

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The specific heat is 0.00892181.

The specific heat capacity of a substance is the amount of heat required to raise the temperature of a unit amount of the substance by 1 degree. At the specific heat Cp of the substance, we name the amount of heat supplied Q that causes a temperature change for the weight W of the substance. Specific heat capacity is the amount of heat required to raise the temperature of 1 kg of a substance by 1 Kelvin.

Specific Heat Capacity C or S  The amount of heat required to raise the temperature of a substance by 1 degree Celsius is called the specific heat capacity of the substance. Heat is often measured in joules J. The mass of the sample is denoted by m. The amount of heat is represented by Q. Heat is expressed in J or Joules. T is the temperature of the substance.

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The mass percent of bromine in this tellurium and bromine compound is 71.47%.

If the compound is made up only of tellurium and bromine, then if the mass percent of tellurium is 28.53%, we can safely assume that the rest is bromine. So, we take the 100% and subtract the mass percent of tellurium to calculate the mass percent of bromine:

100% - 28.53% = 71.47%

The mass percentage of bromine in this compound is 71.47%.

We can even use this data and the molar masses of tellurium and bromine to calculate the empirical formula of the compound if needed.

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The density of water decreases as it becomes warmer, more space. When comparing two samples same salinity of water, sample with the higher temperature will have more volume and hence be less dense.

The accumulation of salt from rainfall over a long period of time or the weathering of rocks are two examples of natural processes that contribute to primary salinity.

By running an electric current between a salinity meter's two electrodes in a sample of soil or water, it is possible to determine the salinity of both water and soil. The quantity and make-up of dissolved salts affect the electrical conductivity, or EC, of a soil or water sample.

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Refer to attachment <⁠(⁠￣⁠︶⁠￣⁠)⁠↗

The partial pressure of oxygen when the mixture is delivered at pressure of 8.2 atm is 0.020 atm.

Each gas that makes up a mixture of gases has a partial pressure, which is the notional pressure of that gas as if it alone filled the original combination's complete volume at the same temperature.

The formula, which calculates partial pressure,

Total pressure = partial pressure Mole fraction

Mole proportion of oxygen in a mixture is equal to the sum of the moles of oxygen and helium.

109 grams are equal to one gigagram, or gg.

= 2 × 10⁹/32 /2 × 10⁹/32 + 98 × 10⁹ / 4

= 2.54 × 10⁻³

oxygen's partial pressure is equal to its mole fraction plus its overall pressure.

= 2.54 × 10⁻³ × 8.0 atm

= 0.02032 atm

= 0.020 atm

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Explanation:

ok so I believe:

a. increase in atomic radii going down a group and decrease going across a period.

b. increase in IE1 going across a period and up a group. the highest IE1 elements are like He, Ne, F and first ionization energy decreases moving further away from those elements moving south west on the periodic table.

c. electron affinity increases moving across a period left to right.

d. ionic radii increases going down a group and decreases going across a period left to right

e. electronegativity increases across a period but decreases down a group. (opposite for electropositivity)

what is meant by the d-block elements? are you referring to the spdf location?

The volume of the solution of NaOH required is obtained as 400 mL.

The term titration has to do with the procedure by which an acid reacts with a base to give salt and water only. The process of titration is a volumetric process.

We can see that the reaction shows that  2 moles NaOH reacts with 1 mole of the acid.

Number of moles of  acid= 2.0 mol/L x 0.1 L = 0.2 moles

Number of moles of base required = 2 x 0.2 = 0.4 moles

Number of moles of NaOH that we need = (x L)(1.0 mol/L) = 0.4 moles

Volume of NaOH that we need =  0.4 L or 400 mL

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Missing parts;

How many ml of 1.0 M NaOH solution are needed to neutralize 100 ml of 2.0 M H2SO4 solution

The total time taken by half of the oxygen to effuse through the membrane is 68.18 hours.

The rate of effusion can be calculated by :

r = V/t

r = 1.5 L/24hr

r = 0.0626 L/hr

According to Graham's Law, effusion is inversely proportional to the square root of their molar mass.

[tex]\frac{r1}{r2}[/tex]  = √[tex]\frac{M2}{M1}[/tex]

The molar mass of He is 4 g/mol  and molar mass of O is 32 g/ mol.

Putting the values

0.0626 L/hr ÷ [tex]r_{2}[/tex] = √32/4

[tex]r_{2}[/tex] = 0.022 L/hr

Therefore, the time taken for effusion of half of 3 L that is 1.5 L of oxygen is:

Time = 1.5 L/ 0.022L/hr = 68.18 hours

Hence, the total time taken by half of the oxygen to effuse through the membrane is 68.18 hours.

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The energy levels present in argon, aluminum and chlorine is 3 , with two electrons on the first energy level , 8 in the second level and third level have 8 electrons of argon.

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