Answer:
Explanation:
Newton's Third Law states that "every action has an equal and opposite reaction". In a rocket, burning fuel creates a push on the front of the rocket pushing it forward. This creates an equal and opposite push on the exhaust gas backwards.
suppose you want to move the block, but you want to push it with the least horizontal force possible to get it moving. with what horizontal force f must you be pushing the block just before the block begins to move?
For the block to just start moving the horizontal force must equal the static friction.
F⇔ ↑N↓mg
N = mg
F = [tex]m_{s} n[/tex]
= [tex]m_{s} mg[/tex]
Frictional forces act parallel to the surface. The frictional force is the force that resists the movement of an object in contact with the surface and acts parallel to the surface with which the object is in contact. When one body moves relative to another, a constant force called friction force begins to act on the sliding surface in the opposite direction of the movement. A moving object has a constant frictional force.
The magnitude of static friction is equal to the magnitude of the applied force. The supporting force F must be greater than the frictional force. The underlying object that requires less force to move is the pencil. Friction: Friction is defined as the force that opposes the motion of objects on contacting surfaces. On the other hand, if you move a large object, it becomes difficult for friction to work.
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can someone please help im begging
Newton’s first law states that no force is required to maintain motion in a straight line at constant speed. If Newton’s first law is true, why must you continue to pedal a bicycle on a level surface to keep moving?
The reason for the continued pedaling of the bicycle is to be able to overcome the forces of resistance and friction.
What is the Newton first law?According to the Newton first law, an object would remain at rest or continue in a state of uniform motion unless is acted upon by an external force. The external force is thus the reason for motion.
We know that a bicycle moves along a straight line. If we are to follow what is said by the Newton's law then we would know that the bicycle should just continue to move once it has started moving. There would thus be no need for the bicycle to be pedaled since it s already moving along a straight line.
But we have to consider the fact that there is friction and air resistance that tends to prevent the motion of the bicycle along the straight line and this is why we must have to keep pedaling the bicycle.
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A student drops a ball and it falls downward. What types of energy are involved in this energy transformation? Two answers are correct
A student drops a ball and it falls downward. Types of energy are involved in this energy transformation are kinetic and gravity potential.
What is energy?Energy is defined as the capacity of a physical system to perform work.
Types of energy are Kinetic energy and potential energy.
The energy an object has as a result of motion is known as kinetic energy. Applying force to an object will cause it to accelerate.
Potential energy is the energy that is stored in any object or system as a result of its position or component arrangement.
A student drops a ball and it falls downward then there is kinetic energy due to motion and potential energy due to height.
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A pitcher throws a fastball horizontally toward home plate 18.39 meters away. If the ball is traveling at a speed of 40.0 m/s when it leaves his hand, what is the ball's acceleration if it takes 0.500s to reach home plate?
A -6.44 m/s2
B -12.9 m/s2
C 6.44 m/s2
D 12.9 m/s2
The ball's acceleration if it takes 0.500s to reach home -12.9 ms⁻².
The problem we are dealing with is related to acceleration, which is the rate of change of the velocity, Since speed could be a speed and a direction, there are as it were two ways for you to accelerate: alter your direction or change your speed—or alter both. We are given the distance of the home plate 18.39 meters, traveling with the initial velocity of 40.0 ms⁻¹ and the time taken to reach the home plate 0.500s.
Since referring to the equation of motion:
s=ut+1/2at^2
=>a=2(s-ut)/t^2
= 2(18.39-(40*0.500)/(0.500^2)
=-12.88
= -12.9 ms⁻²
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the bottom profile normal to the shore off a section of the coast has the following average depths (in m) at the given segment distance lengths (in nautical miles): 2.7 m (3 n.m.), 3.8 m (7 n.m.), 4 m (10 n.m.), 11 m (20 n.m.), 12.2 m (30 n.m.), 15.5 m (40 n.m.), 27 m (50 n.m.), 48 m (60 n.m.), 73 m (70 n.m.), and 200 m (80 n.m.). there is a sustained wind blowing directly onshore at an average speed of 72 knots. calculate the wind-induced setup at the shore. note: to solve this problem you can assume a flat bottom in each segment (we covered this solution in class) and march your solution from offshore to onshore through each segment just like a simple computer storm surge model would. keep in mind that as you march your solution shoreward, the water level in each segment is influenced by the water level from the previous one.
Entering 20 35 4 is not a valid value. This is the same as 27.6 at 50 frames per second multiplied by nine.16 Two plus one thus. Why I visited the buying power. 10 60 x 10 to the power is equal to the required speed of 20.5 mph.
He had utilized equal to allow the power of 0.16 to take over. U. Cuban is equivalent to two. What 4.16 is used for. First late invitation. U. Cuban is equivalent to one. wherefore in light of part.16.
As a result, Cubans find it difficult to offer you what you desire. Why 2 30? Power 300.16. Why? I continued to solve it up to a power of 0.16. Why do I purchase one at a power of 10.16 30?
The third major issue. Do not enter the value 20 35 4. This is equal to 27.6 at 50 frames per second nine to the power.16
Part B. As a result, two equals one. Why I went to the power to buy.4. The needed speed of 20.5 mph is equivalent to 10 60 x 10 to the power.4.
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Users in motion, wireless connectivity, and a cloud-based resource are the elements in a ________ system.
Users in motion, wireless connectivity, and a cloud-based resource are the elements in a mobile system.
Smartphones, tablets, 2-in-1 PCs, smart speakers, smart watches, and smart eyewear all use mobile operating systems. Because they were originally developed for desktop computers, which historically did not have or require specific mobile capability, the operating systems that are used on "mobile" machines, like ordinary laptops, are often not referred to as mobile operating systems.
The distinction between mobile and other forms has become more hazy recently as a result of current hardware becoming more compact and portable than earlier equipment. This distinction is being muddled by the introduction of tablet computers and lightweight laptops, two major advancements.
Mobile operating systems combine desktop operating system elements with additional functionality that is useful for handheld or mobile use. For telephony and data connectivity, these systems typically have a wireless integrated modem and SIM tray.
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Users in motion, wireless connectivity, and a cloud-based resource are the elements of a mobile system which is the operating system used to run mobile devices like smartphones, tablets, etc.
A mobile system is a computing system with mobile entities. These can be hardware or software. The system runs on a mobile operating system such as android and iOS which are the two major mobile operating systems among others. A mobile operating system (OS) allows smartphones, tablet PCs, and other devices to run applications and programs.
Because mobile systems help in the real-time execution of several applications these must use wireless forms of connectivity and a cloud-based resource and storage system. Also, the fact that users can be in motion should be kept in mind and hence these are important elements in a mobile system
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how much power is required to do 200 joules of work in 4 seconds?
what's Given:
asked:
formula:
substitute:
final answer:
Two airplanes leave an airport at the same time. The velocity of the first airplane is 740 m/h at a heading of 42.8°. The velocity of the second is 580 m/h at a heading of 114°.
How far apart are they after 1.6 h? Answer in units of m.
What is the mass of an object a of 77.5 N?
Answer:
Explanation:
Given:
F = 77.5 N
g = 9.8 m/s²
__________
m- ?
m = F /g = 77.5 / 9.8 ≈ 7,9 kg
an ice cube of volume 15.0 cm3 and density 917 kg/m3 is placed in ethyl alcohol of density 811 kg/m3. what is the buoyant force on the ice? will it float?
a. mass is 917 V , b. Buoyant force = 917 Vg, c. Fь= 1000Vsub g d. Vsub=0.917 V e. Volume Vsub/V=0.764
A force called the buoyant force is generated when an object is submerged in a fluid. The pressure that the fluid is applying to the object is what creates the buoyant force. The pressure at the bottom of an item is always greater than the force at the top because pressure rises with depth, leading to the net upward force.
Whether the object sinks or floats, the buoyant force is still at work. The analysis is essentially the same for a submerged object as well, but let's focus on a floating object first.
Even if a related (more difficult) analysis yields the same conclusion for objects with amusing shapes, we'll also take into account a rectangular block. On each of the object's six sides, forces are applied.
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a small sphere that carries a charge q is whirled in a circle at the end of an insulating string. the angular frequency of rotation is ????. what average current does this rotating charge represent? (use the following as necessary: ???? and q.)
Electric current is defined as the total flow of electric charge through a surface over a period of time. Despite not being a vector, electric current has a sense of direction connected with it.
Electric current flows in a direction that is parallel to the motion of the positive charge and transverse to the motion of the negative charge. Ampere is the S.I. unit of electric current (A).
Every revolution, the charged particle that is rotating around the circle passes by a single point on the circle. That is, a charge of Q passes by a point on the circle over the course of evolution, and since que is provided in the question, we can simply use que in the numerator.
We do not, however, know the precise time period because omega, a related quantity, is provided in the question; therefore, we will just relate to these two quantities. T is equal to two pi radiance over Omega Radiance per second since we know that the angular velocity is equal to the circumference of the circle divided by the time it takes for a revolution to occur.
Our expression for the present is therefore cute over T, which is to buy over Omega, which only comes out to good Q over two pi. There is also our typical electric current.
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consider a mach 4 airflow at a pressure of 4 atm. we wish to slow this flow to subsonic speed through a system of shock waves with as small a loss in total pressure as possible.
The density of the gas remains constant and the flow of gas can be characterized by momentum and energy conservation if the speed of the object is substantially slower than the gas's speed of sound.
We must examine the impact of the gas's compressibility when the object's speed approaches that of sound. As the gas is compressed by the object, its local density changes.
Entropy is constant for compressible flows with little to no flow turning, and the flow process is reversible. The isentropic relations then provide the change in flow attributes. Constant entropy is the definition of entropy. However, the flow process becomes irreversible and the entropy rises when an object travels faster than the speed of sound and the flow area suddenly decreases. There are shock waves produced. Shock waves are incredibly small areas in a gas where the gas's properties change significantly.
The static pressure, temperature, and gas density all rise almost instantly across a shock wave. The total enthalpy and the total temperature remain constant because a shock wave doesn't produce any work and there isn't any heat addition.
The total pressure downstream of the shock is, however, always lower than the total pressure upstream of the shock since the flow is non-isentropic. A shock wave is associated with a drop of overall pressure. The slide displays the total pressure ratio. We cannot apply the standard (incompressible) form of Bernoulli's equation across the shock due to variations in total pressure. Over a shock wave, the flow's speed and Mach number both fall.
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Why is using a car not a good reason to use as a reference point
A car not a good reason to use as a reference point because it is not a fixed object relative to earth.
What is a Reference point?This is referred to as a point which is used to describe or discover the location of an object. The types of objects which are used as a good reference point are those which are fixed relative to earth.
On the other hand, cars are not fixed relative to earth such as trees, land which is therefore the reason why car is a good reason not to be used as a reference point.
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why is chlorophyll green? why is chlorophyll green? it absorbs wavelengths in only the blue and red parts of the visible spectrum. it absorbs wavelengths only in the red portions of the spectrum (680-700 nm). it absorbs wavelengths only in the blue part of the visible spectrum (450-480 nm). it absorbs all wavelengths in the visible spectrum.
chlorophyll is green because It absorbs wavelength in only the blue and red parts of the visible spectrum
The pigment chlorophyll is what gives green plants their green color. A portion of the visible light spectrum is absorbed by chlorophyll. Chlorophyll is a pigment that absorbs visible light in the red (long wavelength) and blue (short wavelength) portions of the spectrum. The plant appears green because it reflects rather than absorbs green light.
The chloroplasts of plants contain chlorophyll. Plants have chlorophylls a and b, though there are other forms as well. Only one side chain's makeup distinguishes these two forms of chlorophyll from one another.
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the acceleration due to gravity on the surface of a planet is four times as large as it is on the surface of earth. the mass density of the planet is known to be eight times that of earth. what is the radius of this planet in terms of earth's radius?
The radius of the planet is √2 times radius of earth or 1.414 times the radius of Earth.
What is gravitational force?
According to Newton's law of universal gravitation, every object in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
F = GmM/R²
where;
G is universal gravitation constantm, M are the massesR is the distance between the objectsThe acceleration due to gravity on surface of Earth is given as;
g = GM/R²
G = gR²/M
For a planet whose acceleration due to gravity is 4 times of Earth and mass is 8 times of earth, the radius of the planet is calculated as;
(4gR_p²)/(8M) = (gR²)/(M)
where;'
R_p is the radius of the planet(4R_p²)/8 = R²
4R_p² = 8R²
R_p² = 8R²/4
R_p² = 2R²
R_p = √(2R²)
R_p = R√2
R_p = 1.414 (R)
Thus, the radius of the planet is root two times radius of earth or 1.414 times the radius of Earth.
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Question 2 of 6
Read the problem below and find the solution. Draw a diagram on your own
paper to help solve it.
If your teacher tells you to do questions 28 through 41 in your math book for
homework, how many questions is that?
(Do not include units in your answer.)
Answer here 14
If your teacher tells you to do questions 28 through 41 in your math book for homework, 14 questions are required, and this can be found out through general mathematical concepts such as addition and subtraction.
What are the general mathematical concepts?The general mathematical concepts can be said as the basic concepts or formulas that are taught to everybody. these include the concepts such as Addition, Subtraction, Multiplication and Division.
These are the base formulated concepts basing upon which the whole lot of other generalized equations and formulas are set up.
As per the question, we see that your teacher tells you to do questions a total of 28 through 41 in your math book for homework. Thus, we are then asked to find out the total number of questions.
Since we need to solve a total of questions 28 through 41, this means we have to solve question number 28 and 41 as well.
We already know that 28-37 would be 10 questions and then further 38-41 would be about 4 questions.
So, the total questions required = 10 +4
Total questions = 14
Thus, you just need to solve 14 questions in total to complete the homework.
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an 800 n crate is pulled up a 4m long ramp. the high end of the ramp is elevated 2 m above the ground. it takes 3200 j of work to pull the crate to the top of the ramp. find the magnitude of the friction acting on the crate.
400N magnitude of the friction acting on the crate.
work done by gravity
[tex][w=mg sin \theta \cdotS],[w=mgh=],[w=800 \cdot2=w=1600][/tex]
Then was done by friction external work - wask done by gravity
[tex][f_S \cdot S=3200-1600],[f_S \cdot4=1600],[f_S=400 N][/tex]
Thus the crate is not moving with constant speed then we can say that the value of friction Force is less then 400 N
So Friction Force is not zero but less then the 400N
The resistance present at the contact surface at the point of contact when two or more objects move over one another can be referred to as friction force. The direction of friction force is always perpendicular to the object's motion.
The amount of friction is influenced by the surface's roughness and outside pressures. The force of friction works more strongly on a surface the rougher it is. The same is true of outside factors.
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If an object has a mass of 85g and a volume 92cm^3
The density of the object mentioned in the question when mass and volume are given is 0.924 g[tex]/cm^{3}[/tex]
According to the problem we have the following data given,
The mass of object m= 85g
The volume of object V= 92[tex]cm^{3}[/tex]
To find the density of the object we use the formula [tex]density=\frac{mass}{volume}=\frac{m}{V}[/tex]
∴density ρ [tex]=\frac{m}{V}=\frac{85}{92}=0.924g/cm^{3}[/tex]
Thus the density of the object = 0.924 g/[tex]cm^{3}[/tex]
Your question was not complete but most probably the question was if an object of mass 85g and volume 92cm^3 is given, what is its density?
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a worker is standing on a wet concrete floor, holding an electric drill having a metallic case. the metallic case is connected through the ground wire of a three-terminal power outlet to power-system ground. the resistance of the ground wire is rg. the resistance of the worker's body is rw
The resistance of the ground wire is Rg is mathematically given as Rg=0.025Ф
This is further explained below.
What is resistance?Take into account that the amount of electricity flowing through the worker's body does not surpass 0.1 mA.
The value of the earth's resistors should be extremely low in order to ensure that the greatest possible current is carried by the earth wire and, as a result, that the worker is not shocked.
Determine the highest possible value for R g s o.
[tex]$\begin{aligned}&0.1 \mathrm{~mA}=(2)\left(\frac{R_g}{R_g+500}\right) \\&\frac{R_g+500}{R_g}=20000 \\&R_g+500=20000 R_g \\&\begin{aligned}R_g &=\frac{500}{20000-1} \\&=0.025 \Omega\end{aligned}\end{aligned} \\\\ Rg=0.025Ф[/tex]
The current that flows through the worker is less than or equal to 0.1mA.
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CQ
A worker is standing on a wet concrete floor, holding an electric drill having a metallic case. The metallic case is connected through the ground wire of a three-terminal power outlet to the power-system ground. The resistance of the ground wire is Rg. The resistance of the worker's body is Rw = 500 ?. Due to faulty insulation in the drill, a current of 2 A flows into its metallic case. The circuit diagram for this situation is shown in the figure.Find the maximum value of Rgso that the current through the worker does not exceed 0.1 mA.
WHAT IS THE ANSWER
IS IT A OR C AND PLS EXPLAIN WHY
Answer:
the answer is the options c
At which part a of a river would you have the best luck
growing food??
Answer:
Delta !
Explanation:
You’re driving a car East on the 91 fwy for a total distance of 230 km. If it took you 2.3 hours to reach your destination, then what was your speed?
What was GIVEN?
Answer:
Explanation:
Given:
S = 230 km
t = 2.3 h
_________
V - ?
Speed:
V = S / t
V = 230 / 2.3 = 100 km/h
the angular area of the entire sky is about 41,250 square degrees. how many pictures would the hst have to take with its camera to obtain a complete picture of the entire sky?
It will takes years of time to obtain a complete picture of the entire sky of angular area is about 41,250 square degrees.
Divide 41250 by 0.0036 , we will get 11458333 and 1/3 image. but to take image for all of the sky it will takes years of time.
An angular distance used to describe how big a sphere or circle seems from a certain point of view is known as the angular diameter, angular size, apparent diameter, or apparent size. It is known as the visual angle in the vision sciences and as the angular aperture in optics (of a lens).
The angular diameter may also be thought of as the angle that a camera or eye must spin around in order to view from one side of an apparent circle to the other. Humans are able to distinguish sizes of up to around 1 arcminute (about 0.017° or 0.0003 radians) with their unaided eyes.
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What makes a method accurate or inaccurate?
Answer:
Accuracy is how far off a measurement is from its true value. A measured value that's far from a true value is inaccurate, while a measure that is close to a true value is accurate.
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Consider a toy made out of a ball attached to a 7 inch string attached to a pole. the pole is motorized so that the ball at the end of the string moves in a circle clockwise around the pole. the stand is located on origin of an x and y axis and the speed of the ball is constant (22 in/s). find the magnitude and direction.
The ball swings around the pole while maintaining its angular momentum because its angular velocity rises with decreasing radius and mechanical energy falls.
Think about the board at the top of the circle and the speed the bull is traveling at. We converse, and the velocity is the same when the board is at the base of the circle. According to Newton's Second Lawyer Motion, we are aware of this. the overall force applied to an item that is equal to the acceleration of a mustang underneath the object.
Therefore, a minimum velocity is necessary. Keep the board rotating in a circle. If not, the ball will drop to the ground. Therefore, the ground national wait that is acting on the circular's top board.
Additionally, for the minimal velocity, the centripetal force pressing on the kid must be equal to the gravitational weight acting under effort. Additionally, centripetal force can be expressed as fc = M. The bull is at the top of the circle with the lowest velocity, so according to Newton's Second Law of Motion, M. G. must be equal to him.
From the beginning, we debated in a minimum square. Find the least velocity at the circle's top using that expression. Therefore, by rearranging, we can cancel em from both sides of the minimal square G. R., making it equal. taking the highway. The group of G. R. will have the lowest velocity.
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What is the frequency of light when the energy for a mole of photons is 1. 55 × 1013 j?.
The frequency of light is 3.88 x 10^22Hz.
What is electromagnetic radiation?
The electromagnetic spectrum is the area where the electromagnetic radiation that we see as light, or visible light, is found. Visible light usually has wavelengths between 400 and 700 nanometers (nm) or frequencies between 750 and 420 terahertz, which are between the longer wavelengths of infrared and ultraviolet (with shorter wavelengths).
E = 1.55 x10^13 J/ mol
E = hv
v = 1.55 x 10^13/1mol x 1mol/6.023 x )/6.626 x
velocity = 3.88x10^22 s-1
since 1 Hz = 1/ s = 1
velocity =3.88x 10^22 Hz
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f the coefficient of kinetic friction between tires and dry pavement is 0.80, what is the shortest distance in which you can stop an automobile by locking the brakes when traveling at 31.3 m/s ?
The shortest distance in which you can stop an automobile by locking the brakes when traveling at 31.3 m/s is 62.48m
Force of friction f=N=mg,
where m is the mass of the car.
Acceleration,
a=f/m=mg/m=g
=0.8 x9.8
=7.84m/s2
The distance travelled, S before coming to rest (v = 0)
S=(v2- u2)/2
=(0 - 31.3x31.3)/2x7.84
=62.48 m
The shortest distance in which you can stop an automobile by locking the brakes when traveling at 31.3 m/s is 62.48m
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A mechanic uses a hydraulic car jack to lift the front end of a car to change the oil. The jack used exerts 8000 N of force from the larger piston. To pump the jack, 4000 N of force is exerted on the small piston, which has an area of 2 m2 . What is the area of the large piston?
Answer:
Hope the picture will help you
in the olympiad of 708 b.c., some athletes competing in the standing long jump used handheld weights called halteres to lengthen their jumps. the weights were swung up in front just before liftoff and then swung down and thrown backward during the flight. suppose a modern 88 kg long jumper similarly uses two 6.00 kg halteres, throwing them horizontally to the rear at his maximum height such that their horizontal velocity is zero relative to the ground. let his liftoff velocity be v with arrow
His range would increase by 0.55m yards if he used the halteres. Therefore, using halteres results in a 0.55 m improvement in range.
A speed velocity of, 9.5, was heard. Before the hotter, I last four J. meters per second. finally at the peak of the puff. Okay. The long jumper went with the bank route. Okay. Helter is also present, so we do have the long jumper. A long jumper is currently in motion at the top. So let's talk about RE X. then assisted her. Moving to the rear roof, indeed. none m/s. Okay, in the frame of the ground.
Okay, So, we're curious to know if the long jumper had the conventional distance added. Okay, so in order to properly answer this topic, we must apply the conservation of momentum at the highest point in addition to the concepts from projectile motion.
Therefore, we have 9.5 I. Without the water, speed remains the same. Thus, we might conclude that this is the V. X. The U. I. is this. We can locate a moment of light, okay. Okay hence, multiplying by two and four. Yes, there were roughly 9.8, which is equivalent to your argument. It's 1/6. The range then became hotter without us having to do anything. Then, this is V. X. multiplied by T. I guess there are 25 aches. 0.816. Let's begin. 7.76. Because. Next, we'll locate a range and figure out how to use it.
Therefore, after a long leap, the time of flights for the for the speed duration of light 0.816 seconds remain. Okay. though 1/2 T. is large and in the. 9.5. He performs it again where T is the other half. So his range would increase by 0.55m.
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A BASE jumper jumps from rest and is in free fall for 40.0 m, then he opens his parachute and slows down at a rate of 3.00 m/s². If he
reaches the ground with a speed of 4.00 m/s, how far did he fall in total?
All falling objects experience a downward acceleration equal to the force of gravity.
He jumps 155.96 meters from the ground.
What is free fall motion ?In free fall, an item is traveling only as a result of gravity. Wind and air resistance need to be disregarded for an object to fall freely. On Earth, all falling objects experience a downward acceleration equal to the force of gravity.A body is said to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.A BASE jumper jumps from rest and is in free fall for 40.0 m,
s= 1/2 g t^2
t^2 = 2* 40/9.2
t= 2.95s
v= at = 9.2 * 2.95 =26.68 m/s
u= 26.68 when he opens his parachute and slows down at a rate of 3.00 m/s².
v= 4m/s
2as = v^2 -u^2
s= (4^2 - 2.68^2)/2*9.2
s =115.96 m
total distance = 115.96+ 40 = 155.96 m
He jumps 155.96 meters from the ground.
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