if 10 light rays shined on a mirror what would happen to the 10 light rays?

Answer:

Choice d  
0 acceleration and velocity of 6 m/s

Explanation:

The smart way to tackle questions like these is by POE or Process of Elimination.

We can easily eliminate choices a, b and c since velocity is definitely not 0

So choice (d)

If we look at the graph we see that between 6s and 8s the graph is flat at a velocity value of 6 m/s. So the answer should be velocity of 6 m/s and since there is no increase in velocity, the acceleration is also 0

However, this can also be proved mathematically
Acceleration = change in velocity/change in time
                     =  Δv/Δt

Δv = 6 - 6 = 0
The velocity is 6 m/s at 8 seconds and also 6 m/s at 6 seconds
Δt = 8 - 6 =2

Acceleration = 0/2 = 0 m/s²

Hence choice d

Answer:

Accuracy is how far off a measurement is from its true value. A measured value that's far from a true value is inaccurate, while a measure that is close to a true value is accurate.

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The coefficient of the kinetic friction between the box and the concrete is 0.25. Kinetic friction is the term for the resistance that exists between two systems while they are in contact and moving in relation to one another.

We are constantly surrounded by a force called friction that prevents relative motion between systems in contact while still allowing us to move (which you have discovered if you have ever tried to walk on ice).

Even though friction is a common force, its behavior is actually quite complex and still not fully understood. For any understandings we can obtain, we must heavily rely on observations. We are nevertheless able to deal with its simpler general qualities and comprehend the situations in which it functions.

One of the more basic aspects of friction is that it always occurs in opposition to the motion or attempted motion of the systems with respect to each other and is parallel to the contact surface between the systems. Kinetic friction is the term for the resistance that exists between two systems while they are in contact and moving in relation to one another.

Friction, for instance, makes a hockey puck sliding on ice slower. However, static friction can exist between things while they are immobile; this friction is typically stronger than kinetic friction.

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Explanation:

I think it's the last option

The reason for the continued pedaling of the bicycle is to be able to overcome the forces of resistance and friction.

According to the Newton first law, an object would remain at rest or continue in a state of uniform motion unless is acted upon by an external force. The external force is thus the reason for motion.

We know that a bicycle moves along a straight line. If we are to follow what is said by the Newton's law then we would know that the bicycle should just continue to move once it has started moving. There would thus be no need for the bicycle to be pedaled since it s already moving along a straight line.

But we have to consider the fact that there is friction and air resistance that tends to prevent the motion of the bicycle along the straight line and this is why we must have to keep pedaling the bicycle.

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Because the single bulb has a greater current, it is brighter. Less current is used with the second bulb since the current is split equally between the two bulbs.

The voltage drop across each bulb is 6.0 V when the light bulbs are linked in parallel, and they all glow as the current passing through them combines to generate the current flowing through the battery. Each component in a series circuit needs to be operational for the circuit to be complete.

Energy from the battery is transferred to the circuit's components by an electric current. Nothing in this procedure "uses up" any current. Negatively charged electrons that are constantly present in the circuit's wires and other components make up the majority of the moving charged particles.

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The lorentz Transformation eq enables us to transform velocity from one frame of reference to another, in relative motion with respect to it.

Let S and S' be two inertial frames in relative motion so that S; moves with uniform velocity v to the right. alog the X axis Relative to S

Let u and u' be the velocities of a particle measurd in inertial frames S and S'

so u'=u-v/(1-uv/c^2)

as u=v=c so

u'=u-v

u'=0.500-0.400

u'=0.100c

Answer:

Hope the picture will help you

A student drops a ball and it falls downward. Types of energy are involved in this energy transformation are kinetic and gravity potential.

Energy is defined as the capacity of a physical system to perform work.

Types of energy are Kinetic energy and potential energy.

The energy an object has as a result of motion is known as kinetic energy. Applying force to an object will cause it to accelerate.

Potential energy is the energy that is stored in any object or system as a result of its position or component arrangement.

A student drops a ball and it falls downward then there is kinetic energy due to motion and potential energy due to height.

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a. mass is 917 V , b. Buoyant force = 917 Vg, c. Fь= 1000Vsub g d. Vsub=0.917 V e. Volume Vsub/V=0.764

A force called the buoyant force is generated when an object is submerged in a fluid. The pressure that the fluid is applying to the object is what creates the buoyant force. The pressure at the bottom of an item is always greater than the force at the top because pressure rises with depth, leading to the net upward force.

Whether the object sinks or floats, the buoyant force is still at work. The analysis is essentially the same for a submerged object as well, but let's focus on a floating object first.

Even if a related (more difficult) analysis yields the same conclusion for objects with amusing shapes, we'll also take into account a rectangular block. On each of the object's six sides, forces are applied.

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All falling objects experience a downward acceleration equal to the force of gravity.

He jumps 155.96 meters from the ground.

A BASE jumper jumps from rest and is in free fall for 40.0 m,

s= 1/2 g t^2

t^2 = 2* 40/9.2

t= 2.95s

v= at = 9.2 * 2.95 =26.68 m/s

u= 26.68 when  he opens his parachute and slows down at a rate of 3.00 m/s².

v= 4m/s

2as = v^2 -u^2

s= (4^2 - 2.68^2)/2*9.2

s =115.96 m

total distance = 115.96+ 40 = 155.96 m

He jumps 155.96 meters from the ground.

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Impulse  = change in momentum = 0.045 * 36 = 1.62 kg m/sec and Average Force = Impulse / time  = 1.62 / 3.9 x 10^-3    = 415.3 Newton

Impulse forces are those that have a relatively brief duration of action. The term "impulse" refers to the result of the impulsive force and the time at which it acts. I = F dt = dM is the formula for the impulse, which is the change in momentum brought on by the impulsive force.

The momentum of an object will change when a force acts for a predetermined period of time. In other words, an uneven force always accelerates an object, either by making it go faster or slower. When a force opposes an object's motion, the object slows down. When a force is applied in the same direction as an object's motion, the object is accelerated by the force. In either case, a force will alter an object's velocity.

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A car not a good reason to use as a reference point because it is not a fixed object relative to earth.

This is referred to as a point which is used to describe or discover the location of an object. The types of objects which are used as a good reference point are those which are fixed relative to earth.

On the other hand, cars are not fixed relative to earth such as trees, land which is therefore the reason why car is a good reason not to be used as a reference point.

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The resistance of the ground wire is Rg  is mathematically given as Rg=0.025Ф

This is further explained below.

Take into account that the amount of electricity flowing through the worker's body does not surpass 0.1 mA.

The value of the earth's resistors should be extremely low in order to ensure that the greatest possible current is carried by the earth wire and, as a result, that the worker is not shocked.

Determine the highest possible value for R g s o.

[tex]$\begin{aligned}&0.1 \mathrm{~mA}=(2)\left(\frac{R_g}{R_g+500}\right) \\&\frac{R_g+500}{R_g}=20000 \\&R_g+500=20000 R_g \\&\begin{aligned}R_g &=\frac{500}{20000-1} \\&=0.025 \Omega\end{aligned}\end{aligned} \\\\ Rg=0.025Ф[/tex]

The current that flows through the worker is less than or equal to 0.1mA.

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CQ

A worker is standing on a wet concrete floor, holding an electric drill having a metallic case. The metallic case is connected through the ground wire of a three-terminal power outlet to the power-system ground. The resistance of the ground wire is Rg. The resistance of the worker's body is Rw = 500 ?. Due to faulty insulation in the drill, a current of 2 A flows into its metallic case. The circuit diagram for this situation is shown in the figure.Find the maximum value of Rgso that the current through the worker does not exceed 0.1 mA.

Electric current is defined as the total flow of electric charge through a surface over a period of time. Despite not being a vector, electric current has a sense of direction connected with it.

Electric current flows in a direction that is parallel to the motion of the positive charge and transverse to the motion of the negative charge. Ampere is the S.I. unit of electric current (A).

Every revolution, the charged particle that is rotating around the circle passes by a single point on the circle. That is, a charge of Q passes by a point on the circle over the course of evolution, and since que is provided in the question, we can simply use que in the numerator.

We do not, however, know the precise time period because omega, a related quantity, is provided in the question; therefore, we will just relate to these two quantities. T is equal to two pi radiance over Omega Radiance per second since we know that the angular velocity is equal to the circumference of the circle divided by the time it takes for a revolution to occur.

Our expression for the present is therefore cute over T, which is to buy over Omega, which only comes out to good Q over two pi. There is also our typical electric current.

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Net ebony x-axis. ∅ ≈ 2° west of north.

= Rx = 5+ 7 cos 20° - 12

= -0.42 mi

Now, -axis  y axis

Ry = 7 Sin 20° +15 - 5

= 12.39 mi

= [tex]\sqrt{Rx^{2} + R}y^{2}[/tex] = [tex]\sqrt{(0.42)^{2} + (12.39)^{2} }[/tex]

IRI = 12.40 mi

Its direction:

tan ∅ = Rx/Ry west of North Ry  

∅ = [tex]tan^{-1}[/tex](0.42/12.39)

∅ = 1.94° west of north

∅ ≈ 2° west of north.

In the graphical method of adding vectors A and B, the vectors are drawn on the graph and added from head to tail. The resulting vector R is defined as A + B = R. The magnitude and direction of R are determined using a ruler and protractor, respectively. Draw the vectors so that their starting points coincide. Then draw a line to make a perfect parallelogram.

The diagonal from the starting point of the parallelogram to the opposite vertex is the result. GRI allows users to graphically display the detailed results of technical and economic analysis of a project. Hybrid2 uses two types of simulation models. One is for long-term performance prediction called the logistic model.

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Answer:

Explanation:

Given:

F = 77.5 N

g = 9.8 m/s²

__________

m- ?

m = F /g = 77.5 / 9.8 ≈ 7,9 kg

For the block to just start moving the horizontal force must equal the static friction.

F⇔ ↑N↓mg

N = mg

F = [tex]m_{s} n[/tex]

=  [tex]m_{s} mg[/tex]

Frictional forces act parallel to the surface. The frictional force is the force that resists the movement of an object in contact with the surface and acts parallel to the surface with which the object is in contact. When one body moves relative to another, a constant force called friction force begins to act on the sliding surface in the opposite direction of the movement. A moving object has a constant frictional force.

The magnitude of static friction is equal to the magnitude of the applied force. The supporting force F must be greater than the frictional force. The underlying object that requires less force to move is the pencil. Friction: Friction is defined as the force that opposes the motion of objects on contacting surfaces. On the other hand, if you move a large object, it becomes difficult for friction to work.

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When the circuit's current doubles, the power lost in the circuit is given by, Beginning with "begin aligned" and ending with "end aligned," P =I 0 2 R =(2 I) 2 R =4 I 2 R. The power dissipated by the circuit is quadrupled if the current in the circuit is twice.

The idea of a resistance's power loss at constant voltage. The square of the potential across the resistor over its resistance, then, represents the power dissipated or the bubble that generated at constant volume at constant voltage. From this, we might conclude that power and resistance are inversely related.

Starting with "begin aligned" and continuing with "end aligned," P =I 0 2 R =(2 I) 2 R =4 I 2 R gives the power lost in the circuit when the circuit's current doubles. If the circuit's current is doubled, the power it dissipates is multiplied by four.

Now that we know this, we may write the original power P equals are over our buddies and the power BI prime over it. We can express the power P prime equals P times are greater than our prime from this. The resistance is prime is off by double the initial help in the problem now.

As a result, the power Well will decrease by a factor of 2, and the new power P prime will therefore be P over two.

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The ball's acceleration if it takes 0.500s to reach home -12.9  ms⁻².

The problem we are dealing with is related to acceleration, which is the rate of change of the velocity, Since speed could be a speed and a direction, there are as it were two ways for you to accelerate:  alter your direction or change your speed—or alter both. We are given the distance of the home plate 18.39 meters, traveling with the initial velocity of 40.0 ms⁻¹ and the time taken to reach the home plate 0.500s.

Since referring to the equation of motion:

s=ut+1/2at^2

=>a=2(s-ut)/t^2

     = 2(18.39-(40*0.500)/(0.500^2)

    =-12.88

   = -12.9  ms⁻²

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The kind of finger print that could be used in this case is the latent finger print.

The term finger print refers to a unique pattern that could be obtained from the fingers of an individual. The use of the finger prints have been very helpful in the science of forensics as many complex crimes have been solved by the use of this method.

The latent finger prints are the kind of finger prints that are not readily visible thus they could be used when we are dealing with very tough crimes.

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Missing parts;

You’ve searched an area for fingerprints but haven’t found any in your initial visual examination of an area. If you are still curious if there are fingerprints, what would you need to start looking for?

Plastic fingerprints

Latent fingerprints

Visible fingerprints

Abbil fingerprints

The greatest static resistance between the upper and lower block is f1max = f 1max = s m 1g = 0.6×2×10 = 12N.

According to Newton's second law of motion, an object's net force must equal the sum of its mass and the acceleration it experiences. In the direction of the net force is where acceleration is moving.

The force of action and reaction between two bodies is equal in magnitude but opposite in direction, according to Newton's third law of motion. The highest frictional force that prevents slippage on a surface is known as the limiting friction force.

The highest static resistance between the lower block and the ground is

f2max

​ =μ s (m 1 +m 2 )g=0.6(2+2)10

=24N

Assumedly, both blocks move to the right at the same speed.

Consequently, (m 1 + m 2 )a = T- μk (m1 + m2)g

or 4a = T - 0.4(2+2)10

or a = T-16 / 4

for upper block, f1 = 2a = T - 16 / 2

For just sliding, f1 = f1max

or T - 16 / 2 = 12

or T - 16 = 24 => T = 40N

The complete question is:

You are lowering two boxes, one on top of the other, down the ramp by pulling on a rope parallel to the surface of the ramp. Both boxes move together at a constant speed of 15.0 cm/s. The coefficient of kinetic friction between the ramp and the lower box is 0.441, and the coefficient of static friction between the two boxes is 0.834. (a) What force do you need to exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?

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Answer: the tension in the upper string will be larger than the tension in the lower string because of the weight of the stone. So, the upper string will break first.

Explaination:

Step 1. Newton’s second law

According to Newton’s second law, the value of the force can be obtained by examining the value of the object’s acceleration and the mass. Its value is altered linearly to the value of the object’s acceleration.

Step 2. Draw a free-body diagram

Here,  is the tension force in the string,  is the mass of the object,  is the gravitational force, and  is the applied force.

Step 3. Application of Newton’s second law

When given a sharp pull, there is a sudden application of force. When a large, sudden force is applied to the bottom of the string, the bottom string will have a large tension. Because of the stone's inertia, the upper string does not experience this large force, and therefore, the bottom string breaks.

If a slow and steady pull is applied, the tension in the bottom string increases. The stone is in equilibrium until the string breaks.

The block will be in equilibrium as long as T = F + mg

Thus, the tension in the upper string will be larger than the tension in the lower string because of the weight of the stone. So, the upper string will break first.

Answer:

Delta !

Explanation:

A series RC circuit that receives its power from a DC source will experience transient phenomena when the circuit closes.

Therefore, it follows that the current flow is not constant over time. Beginning high and falling off exponentially, it eventually reaches zero. The current will be (V/R) x (1/e) at the moment when t=RC. The greatest current value is V/R.

1/e is roughly equal to 0.37.

Therefore, RC is the period of time in a series RC circuit during which the current will decrease to about 37% of its maximum value.

To obtain the necessary current vs. time characteristic, etc., the appropriate value of R and C is chosen based on the needs of the electronic circuit.

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The gravitational acceleration on the asteroid is 0.195 m/s².

Gravitational acceleration has an important role in uniform motion. Uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration (gravitational acceleration), t is time and s is displacement.

From the question above, we know that

h = 100 m

vo = 5 m/s

vt = 8 m/s

By substituting the given parameters, we get

vt² = vo² + 2a . s

vt² = vo² + 2g . h

8² = 5² + 2.g . 100

64 = 25 + 200g

g = 0.195 m/s²

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The heat supplied to increase the temperature of the substance is used up to transform the state of matter of that substance. Hence the temperature of the substance stays constant until the phase transition completes.

In chemistry, phase transitions or phase changes are the physical processes of transition between a state of a medium of a substance. This term is used to refer to changes in the basic states of matter such as solid, liquid, and gas.

When a substance is heated or cooled and approaches a temperature corresponding to one of its phase transitions. Further gain or loss of heat results in diminishing or enhancing intermolecular attractions, instead of changing the molecular kinetic energies.

While a substance is undergoing a change in state which is a phase transition, its temperature remains constant. The horizontal lines on the graph represent the transition between the states of the substances X and substances Y.

When adding heat leads to the temperature of a substance being increased as the kinetic energy of the molecules of the substance increases. The conduction of heat occurs when these molecules start vibrating with high energy, Hence the heat transfer from one molecule to another.

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400N  magnitude of the friction acting on the crate.

work done by gravity

[tex][w=mg sin \theta \cdotS],[w=mgh=],[w=800 \cdot2=w=1600][/tex]

Then was done by friction  external work - wask done by gravity

[tex][f_S \cdot S=3200-1600],[f_S \cdot4=1600],[f_S=400 N][/tex]

Thus the crate is not moving with constant speed then we can say that the value of friction Force is less then 400 N

So Friction Force is not zero but less then the 400N

The resistance present at the contact surface at the point of contact when two or more objects move over one another can be referred to as friction force. The direction of friction force is always perpendicular to the object's motion.

The amount of friction is influenced by the surface's roughness and outside pressures. The force of friction works more strongly on a surface the rougher it is. The same is true of outside factors.

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The density of the gas remains constant and the flow of gas can be characterized by momentum and energy conservation if the speed of the object is substantially slower than the gas's speed of sound.

We must examine the impact of the gas's compressibility when the object's speed approaches that of sound. As the gas is compressed by the object, its local density changes.

Entropy is constant for compressible flows with little to no flow turning, and the flow process is reversible. The isentropic relations then provide the change in flow attributes. Constant entropy is the definition of entropy. However, the flow process becomes irreversible and the entropy rises when an object travels faster than the speed of sound and the flow area suddenly decreases. There are shock waves produced. Shock waves are incredibly small areas in a gas where the gas's properties change significantly.

The static pressure, temperature, and gas density all rise almost instantly across a shock wave. The total enthalpy and the total temperature remain constant because a shock wave doesn't produce any work and there isn't any heat addition.

The total pressure downstream of the shock is, however, always lower than the total pressure upstream of the shock since the flow is non-isentropic. A shock wave is associated with a drop of overall pressure. The slide displays the total pressure ratio. We cannot apply the standard (incompressible) form of Bernoulli's equation across the shock due to variations in total pressure. Over a shock wave, the flow's speed and Mach number both fall.

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The density of the object mentioned in the question when mass and volume are given is 0.924 g[tex]/cm^{3}[/tex]

According to the problem we have the following data given,

The mass of object m= 85g

The volume of object V= 92[tex]cm^{3}[/tex]

To find the density of the object we use the formula [tex]density=\frac{mass}{volume}=\frac{m}{V}[/tex]

∴density ρ [tex]=\frac{m}{V}=\frac{85}{92}=0.924g/cm^{3}[/tex]

Thus the density of the object = 0.924 g/[tex]cm^{3}[/tex]

Your question was not complete but most probably the question was if an object of mass 85g and volume 92cm^3 is given, what is its density?

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