Answer:
true
Explanation:
because global helps local
Potential Energy: A cat which weighs 10 kg walks up a ladder. The ladder has a height of 15 m. How many joules of gravitational
potential energy does the cat have?
Which part of and organism is preserved in cast and mold fossils
Answer:
bones
Explanation:
Bones are is preserved in cast and mold fossils.
Normally the other 'parts of the body' like muscles, ligaments, blood and organs are soft.
Answer:
bones
Explanation:
A 4kg object has a momentum of 12 kg*m/s, what is the objects velocity?
An alien from the newly discovers planet nine weighs himself on his planet and finds his weight to be 3200 N. When he stoves on earth he once again weighs himself and find his aight to be 800 N. What is the acceleration due to gravity on planet 9?
Answer:
2.45 m/s²
Explanation:
From the question,
On the Earth
W = mg.................. Equation 1
Where W = weight of the alien on the earth, m = mass of the alien on the earth, g = acceleration due to gravity of the earth.
Make m the subject of equation 1
m = W/g................... Equation 2
Given: W = 3200 N
Constant: 9.8 m/s²
Substitute these value into equation 2
m = 3200/9.8
m = 326.5 kg.
Similarly,
On planet 9,
W' = mg'............... Equation 3
Where W' = weight of the alien on planet 9, g' = acceleration due to gravity on planet 9.
make g' the subject of the equation
g' = W'/m............ Equation 4
Given: W' = 800 N
Substitute into equation 4
g' = 800/326.5
g' = 2.45 m/s²
Someone help me extra points & brainlest
Answer:
75 m
Explanation:
Using the image, which area of the ocean floor would have the largest amount of pressure? Explain
Answer: the area were the most pressure is at the deep sea trench (the deepest part)
Explanation: because the more on top of you is the more pressure.
can someone help me with this please what are the two correct answers??
Answer:
The answers should be B and D
Explanation:
I hope this helps!
A plane travels 4.0 km at an angle of 25◦ to the ground, then changes direction and travels 10 km at an angle of 16◦ to the ground. What is the magnitude of the plane's total displacement? Answer in units of km.
Answer:
6.1 km
Explanation:
Given that a plane travels 4.0 km at an angle of 25◦ to the ground, then changes direction and travels 10 km at an angle of 16◦ to the ground. What is the magnitude of the plane's total displacement? Answer in units of km
The magnitude of the total displacement D can be calculated by using cosine formula
Ø = 25 - 16 = 9 degree
D^2 = 4^2 + 10^2 - 2 × 4 × 10 × cos 9
D^2 = 16 + 100 - 80cos9
D^2 = 116 - 79.02
D = sqrt( 36.98)
D = 6.1 m
Therefore, the magnitude of the plane's total displacement is 6.1 km
What is the name of the force that opposes, or the opposite of gravity ???!!
Answer:
Tension.
tension is the name of force that opposes or goes opposite of gravity
Hope this helps!
Answer: Friction
Explanation: Friction opposes gravity and any motion in two surfaces.
Hope This Helped, Have A Great Day!
A5.0 kg TNT explosive, initially at rest, explodes into two pieces. One of the pieces weighing 2.0 kg flies off to
the left at 36
What is the final speed of the remaining piece?
Answer:
v = 24 m/s, rightwards
Explanation:
Given that,
The mass of TBT explosive = 5 kg
It explodes into two pieces.
One of the pieces weighing 2.0 kg flies off to the left at 36 m/s. Let left be negative and right be positive.
The law of conservation of momentum holds here. Let v be the final speed of the remaining piece. So,
[tex]5\times 0=2\times (-36)+3\times v\\\\-72=-3v\\\\v=24\ m/s[/tex]
So, the final speed of the remaining piece is 24 m/s and it is in the right direction.
Explain how air exerts a pressure
air exert a pressure take a glass and put the water on it and small piece a paper and glass take downword and observe it so tha air exert pressure
You pull straight up on the string of a yo-yo with a force 0.19 N, and while your hand is moving up a distance 0.12 m, the yo-yo moves down a distance 0.30 m. The mass of the yo-yo is 0.058 kg, and it was initially moving downward with speed 3.4 m/s. (b) What is the new speed of the yo-yo
Answer:
2.54 m/s
Explanation:
By conservation of energy,
work done by force due to hand = mechanical energy gained by yo-yo
So Fd = mgh + 1/2m(v₂² - v₁²)
where F = force on string = 0.19 N, d = distance moved by hand = 0.12 m, m = mass of yo-yo = 0.058 kg, g = acceleration due to gravity = 9.8 m/s², h = distance moved by yo-yo = 0.30 m, v₁ = initial speed of yo-yo = 3.4 m/s and v₂ = final speed of yo-yo = unknown
So, Fd = mgh + 1/2m(v₂² - v₁²)
Fd/m = gh + 1/2(v₂² - v₁²)
Fd/m - gh = 1/2(v₂² - v₁²)
2(Fd/m - gh) = (v₂² - v₁²)
(v₂² - v₁²) = 2(Fd/m - gh)
v₂² = v₁² + 2(Fd/m - gh)
taking square-root of both sides, we have
v₂ = √[v₁² + 2(Fd/m - gh)]
Substituting the values of the variables into the equation, we have
v₂ = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]
v₂ = √[(3.4 m/s)² + 2(0.19 N × 0.12 m/0.058 kg - 9.8 m/s² × 0.30 m)]
v₂ = √[(3.4 m/s)² + 2(0.0228 Nm/0.058 kg - 9.8 m/s² × 0.30 m)]
v₂ = √[(3.4 m/s)² + 2(0.393 Nm/kg - 2.94 m²/s²)]
v₂ = √[(3.4 m/s)² + 2(-2.547 m²/s²)]
v₂ = √[11.56 m²/s² - 5.094 m²/s²)]
v₂ = √[6.466 m²/s²]
v₂ = 2.54 m/s
To Calculate Velocity and Average Velocity you can use the same formula as both.
True Or False?
Answer:
I believe it's True! Brainliest??
Explanation: Hope you have a great day :)
8.
2
AI
6
HCI
AICI:
+
H
에
싶
Answer:
I'm sorry I can't help you...
What method is used when you try several different solutions to see what
works?
A. Trial and error
B. Stages
C. Heuristic
D. Rational
Answer:
A
Explanation:
Trial and error is basically trying something, if it works, great. If it does not work, try another way.
Answer:
A. Trial and error
Explanation:
The other user is correct.
number of atoms of each element ammonium hydroxide?
Answer:
Explanation:
Ammonium Hydroxide has the chemical formula of
NH4OH
There is 1 Nitrogen (N) = 1
There are 5 Hydrogens (H) = 5
There is 1 Oxygen (O) = 1
In total, there are 7 atoms in 1 molecule of NH4OH
What will be the change in velocity of a 850 kg car if a force of 50,000N is
applied for 0.5 s? (Round to one decimal)
Answer:
i'm not quite sure
Explanation:
just grive me a sec
Answer:
29.4 m/s
Explanation:
f = ma
a = [tex]\frac{f}{m}[/tex]
a = [tex]\frac{50000}{850}[/tex]
a = 58.8 [tex]m/s^{2}[/tex]
a = [tex]\frac{change in velocity}{t}[/tex]
change in velocity= at
change in velocity = 58.8 × 0.5
change in velocity = 29.4 m/s
CAN SOMEONE HELP ME WITH THIS
Answer:
D
Explanation:
I need help with this question it's science
which diagram represents the greatest magnitude of displacement for an object
Answer: if every arrow=1m do 1 times 1 times 1 times 1
Explanation:
(p.s. it equals 1 meter in area 4 meters in perimeter)
Marcus tries to move a refrigerator but can't. Has he done work?
A) Yes, because he used energy.
B) Yes, because he exerted a force.
C) No, because he did not move the object.
D) No, because he did not use energy.
Answer:
A
Explanation:
Even if the refrigerator did not move he still used energy to try to push it it's just his energy wasnt stronger than the refrigerator's energy
Jake appears to have several personalities. One is his dead cousin Bob, who
apparently bought a car Jake didn't know about. Jake said he had no memory
of buying the car. Jake also has a personality of a 12-year-old child. Jake
appears to be suffering from:
A. schizophrenia.
B. generalized anxiety disorder.
C. dissociative identity disorder.
D. major depression.
SUBMIT
Answer: DISSOCIATIVE IDENTITY DISORDER
Explanation:
(True/False) The normal force is always opposite in direction to weight.
Answer:
True
Explanation:
Astronomers build optical telescopes on tops of mountains because a. there is less air to dim the light. b. the seeing is better. c. CCDs work better with a beautiful mountain view. Astronomers build optical telescopes on tops of mountains because a. there is less air to dim the light. b. the seeing is better. c. CCDs work better with a beautiful mountain view. all choices, a, b and c choice c only choice a only choice b only choices a and b
Answer: choices a and b
Explanation:
Telescope can be defined as am optical instrument which is designed to observe the distant objects clear and nearer. It comprises of arrangement of lenses which allow the rays of light to be collected. The collected light is focused and the image so produced is magnified in the form of an image. The telescopes are prepared and manufactured on mountains top as this will help in preventing the distortion of light obtain from the star due to the fluctuation of air mass in the atmosphere. The atmospheric distortion affects the resolution, and affects the vision. The atmospheric pressure is low at the mountain tops so it will help in better observation of the sky.
A television that requires an average of 0.40 ampere of current is operated on a
120-volt service for 5.0 hours. How much energy is used?
a. 1.5 kWh
b. 0.15 kWh
C. 0.24 kWh
d. 0.67 kWh
The energy that has been used is 0.24 kWh
What work is the person doing doing to the box if the box is just being held and it is not moving?
Giving brainliest!! if you answer correctly :) (30pts)
Answer:
32000joule.
Explanation:
given
mass. (m)=160kg
speed (v)=20m/s
now
kinetic energy =1/2 (mv²)=1/2 ×{160×20²}=32000joule.
Answer:
Explanation:
Ke = 1/2 mv2
Ke = 1/2(160)(20)2
= 1/2(160)(400)
= 32000J
Option B is the correct answer
Select the correct location on the image.
Which color in the visible spectrum has the highest frequency?
Answer:
Violet I took the test and it was right
Answer:
Violet the dude above was correct i took the test and got it right
Explanation:
Calcular la densidad absoluta de un fluido cuya masa es de 12.8 kg y que ocupa un volumen de 16.3 cm
Answer:
[tex]d=785.27\ g/cm^3[/tex]
Explanation:
The question says that, "Calculate the absolute density of a fluid whose mass is 12.8 kg and which occupies a volume of 16.3 cm³".
Mass, m = 12.8 kg = 12800 g
Volume, V = 16.3 cm³
The density of an object is defined as the mass per unit volume i.e.
[tex]d=\dfrac{m}{V}\\\\d=\dfrac{12800}{16.3}\\\\d=785.27\ g/cm^3[/tex]
So, the absolute density of the fluid is equal to [tex]785.27\ g/cm^3[/tex].
A 90° elbow in a horizontal pipe is used to direct water flow upward at a rate of 40 kg/s. The diameter of the entire elbow is 10 cm. The elbow discharges water into the atmosphere, and thus the pressure at the exit is the local atmospheric pressure. The elevation difference between the centers of the exit and the inlet of the elbow is 50 cm. The weight of the elbow and the water in it is considered to be negligible. Determine (a) the gage pressure at the center of the inlet of the elbow and (b) the anchoring force needed to hold the elbow in place. Take the momentum-flux correction factor to be 1.03 at both the inlet and the outlet.
Answer:
(a) The gauge pressure is 4,885.3 Pa
(b) The anchoring force needed to hold the elbow in place is approximately 296.5 N
The direction of the anchoring force is approximately ≈ 134.8
Explanation:
The given parameters in the fluid dynamics question are;
Pipe elbow angle, θ = 90°
The mass flowrate of the water, [tex]\dot m[/tex] = 40 kg/s
The diameter of the elbow, D = 10 cm
The pressure at the point of discharge of the fluid = Atmospheric pressure
The elevation between the inlet and exit of the elbow, z = 50 cm
The weight of the elbow and the water = Negligible
(a) The velocity of the fluid, v₁ = v₂ = v is given as follows;
ρ·v·A = [tex]\dot m[/tex]
v = [tex]\dot m[/tex]/(ρ·A)
Where;
ρ = The density of the fluid (water) = 997 kg/m³
A = The cross-sectional area of the of the elbow = π·D²/4 = π×0.1²/4 ≈ 0.00785398163
A = 0.00785398163 m²
v = 40 kg/s/(0.00785398163 m² × 997 kg/m³) ≈ 5.1083 m/s
Bernoulli's equation for the flow of fluid is presented as follows;
[tex]\dfrac{P_1}{\rho \cdot g} +\dfrac{v_1}{2 \cdot g} + z_1 = \dfrac{P_2}{\rho \cdot g} +\dfrac{v_2}{2 \cdot g} + z_2[/tex]
v₁ = v₂ for the elbow of uniform cross section
P₁ - P₂ = ρ·g·(z₂ - z₁)
P₁ - P₂ = The gauge pressure = [tex]P_{gauge}[/tex]
z₂ - z₁ = z = 50 cm = 0.5 m
∴ [tex]P_{gauge}[/tex] = 997 kg/m³ × 9.8 m/s² × 0.5 m = 4,885.3 Pa
The gauge pressure, [tex]P_{gauge}[/tex] = 4,885.3 Pa
(b) The forces acting on the elbow are;
[tex]F_{Rx}[/tex] + [tex]P_{gauge}[/tex]·A = -β·[tex]\dot m[/tex]·v
[tex]F_{Ry}[/tex] = β·[tex]\dot m[/tex]·v
∴ [tex]F_{Rx}[/tex] = -β·[tex]\dot m[/tex]·v - [tex]P_{gauge}[/tex]·A
[tex]F_{Rx}[/tex] = -1.03 × 40 kg/s × 5.1083 m/s - 4,885.3 Pa × 0.00785398163 m² ≈ -208.83 N
[tex]F_{Ry}[/tex] = 1.03 × 40 kg/s × 5.1083 m/s = 210.46196 N
The resultant force, [tex]F_R[/tex], is given as follows;
[tex]F_R[/tex] = √([tex]F_{Rx}[/tex]² + [tex]F_{Rz}[/tex]²)
∴ [tex]F_R[/tex] = √((-208.83)² + (210.46196)²) ≈ 296.486433934
Therefore;
The anchoring force needed to hold the elbow in place, [tex]F_R[/tex] ≈ 296.5 N
The direction of the anchoring force, θ
[tex]\theta = tan^{-1}\left( \dfrac{F_{Ry}}{F_{Rx}} \right)[/tex]
∴ θ = arctan(210.46196/(-208.83)) = -45..2230044°
θ = 180° + -45.2230044° = 134.7769956°
∴ The direction of the anchoring force is approximately, θ ≈ 134.8°