The general driving forces behind most chemical interactions is the need for atoms to be electrically neutral and to: O donate Hydrogen ions O complete their nucleus O donate Hydroxyl ions O complete their outer electron orbital area (shell)

Answers

Answer 1

The general driving forces behind most chemical interactions is the need for atoms to be electrically neutral and to complete their outer electron orbital area (shell).

When both the cases are fulfilled i.e. when the enthalpy change is negative and the entropy change is positive, the reaction is said to be spontaneous and thus enthalpy and entropy are the two thermodynamic driving forces of chemical reactions.

Formation of a solid (precipitate)The creation of water.Electron transfer.Gas formation

There are several factors that affects the driving force:

1. Release of heat (exothermic reactions are driven)

2. Free energy – the change in free energy should be negative

3. Entropy – An increase in entropy drives a reaction

4. Equilibrium Shift - Removal of products drives the reaction

The general driving forces behind most chemical interactions is the need for atoms to be electrically neutral and to complete their outer electron orbital area (shell).

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Related Questions

A circular loop of radius 15 cm carries a current of 11 A. A flat coil of radius 0.79 cm, having 66 turns and a current of 1.9 A, is concentric with the loop. The plane of the loop is perpendicular to the plane of the coil. Assume the loop's magnetic field is uniform across the coil. What is the magnitude of (a) the magnetic field produced by the loop at its center and (b) the torque on the coil due to the loop

Answers

Answer:

[tex]4.61\times 10^{-5}\ \text{T}[/tex]

[tex]1.05\times 10^{-6}\ \text{Nm}[/tex]

Explanation:

[tex]\mu_0[/tex] = Vacuum permeability = [tex]4\pi10^{-7}\ \text{H/m}[/tex]

[tex]r_l[/tex] = Radius of loop = 15 cm

[tex]I_l[/tex] = Current in loop = 11 A

[tex]r_c[/tex] = Radius of coil = 0.76 cm

N = Number of turns of coil = 66

[tex]I_c[/tex] = Current in coil = 1.9 A

Magnetic field is given by

[tex]B=\dfrac{\mu_0I_l}{2r_l}\\\Rightarrow B=\dfrac{4\pi\times 10^{-7}\times 11}{2\times 0.15}\\\Rightarrow B=4.61\times 10^{-5}\ \text{T}[/tex]

Magnitude of magnetic field produced by the loop at its center is [tex]4.61\times 10^{-5}\ \text{T}[/tex].

Torque is given by

[tex]\tau=BI_c\pi r_c^2N\sin90^{\circ}\\\Rightarrow \tau=4.61\times 10^{-5}\times 1.9\times \pi\times (0.76\times 10^{-2})^2\times 66\sin90^{\circ}\\\Rightarrow \tau=1.05\times 10^{-6}\ \text{Nm}[/tex]

Magnitude of torque on the coil due to the loop is [tex]1.05\times 10^{-6}\ \text{Nm}[/tex]

To say that electric charge is conserved means that no case has ever been found where :_________
a. the total charge on an object has changed.
b. the total quantity of charge on an object has increased.
c. net charge has been created or destroyed.
d. quantity of negative charge on an object exactly balances positive charge.
e. none of the above

Answers

Answer:

B

Explanation:

To say that electric charge is conserved means that no case has ever been found where :_________

the total quantity of charge on an object has increased

According to conservation of energy, energy is neither created nor destroyed. But can only be converted into another form.

But in the case of charges, the number of charges can not be increased nor decreased it's only the rate of flow that can change due to the pressure supplied.

So therefore, the correct answer is B which say that:

To say that electric charge is conserved means that no case has ever been found where the total quantity of charge on an object has increased

True or False:
If you look at the night sky and see a very bright star, you can tell that that star is closer to Earth than all the other stars.

Answers

This is a true statement

Answer:

hi

Explanation:

false because the light of some stars can be very bright, but it can also be very far from the earth.

have a nice day

Calculate the induced electric field (in V/m) in a 52-turn coil with a diameter of 17 cm that is placed in a spatially uniform magnetic field of magnitude 0.45 T so that the face of the coil and the magnetic field are perpendicular. This magnetic field is reduced to zero in 0.10 seconds. Assume that the magnetic field is cylindrically symmetric with respect to the central axis of the coil. (Enter the magnitude.)

Answers

Answer:

the induced electric field is 9.95 V/m

Explanation:

Given the data in the question;

Number of turns N = 52

Diameter of coil D = 17 cm = 0.17 m

Radius r = D/2 = 0.17/2 = 0.085 m

Now,

cross-section area A of the coil  = πr²

A = π × ( 0.085 m )²

A = 0.0227 m²

Also given that;

Initial magnetic field B₁ = 0.45 T

Final magnetic field B₂ = 0

∴ change in magnetic field ΔB = B₁ - B₂ = 0.45 T - 0 = 0.45 T

Time taken dT = 0.10 seconds

Now, we know that;

Induced emf ∈ = N[tex](\frac{d\eta }{dt} )[/tex]

where η = BAcosθ

We know that, magnetic field is cylindrically symmetric, coil is also perpendicular to magnetic field.

Hence, the angle between B & A is 0°

∴ θ = 0°

Induced emf ε = N[tex](\frac{d }{dt} )BAcos\theta[/tex]

we substitute

ε = N[tex](\frac{d }{dt} )[/tex] (BAcos0°)

A is constant and cos0° = 1

so

ε = NA[tex](\frac{dB }{dt} )[/tex]  

We now substitute in our values;

ε = 52 × 0.0227 m² ×  [tex](\frac{0.45T }{0.10s} )[/tex]

ε  =  5.3118 V

we know that, from the relation between electric and emf

ε = ∫∈.dl or ε = ∈∫dl         { for coil; ∫dl = πD }

so we have;

ε = ∈πD

solve for ∈

∈ = ε/πD

we substitute

∈ = 5.3118 V / ( π × 0.17 m )

∈ = 9.95 V/m

Therefore, the induced electric field is 9.95 V/m

What do radio waves and gamma rays have in common?

They are both electromagnetic waves.
They are both low frequency waves.
They can only travel in a vacuum.
They both are part of the visible light spectrum.

Answers

They are both electromagnetic waves.

Answer:

Both Magnetic

Explanation:

what must be the mass of a rock if a boy applies a 64N force and causes it to accelerate at 4.51m/s2

Answers

first of all the formula of force is F=ma,so we are searching for m,so we can divide a on both sides F/a=m, after this substitute the values given above 64N/4.51=14.2°Kg

There is a bell at the top of a tower that is 45 m high. The bell weighs 190 kg. The bell has
energy. Calculate it

Answers

Answer: The bell has 8550 J energy.

given, There is a bell at the top of a tower that is 45 m high. The bell weighs 190 N

i.e., bell is located at the top of tower, h = 45m

weight of the bell, F = 190 N

workdone by the gravitational force = F.hcos180°

[ gravitational force (i.e., weight ) acting downward while body is located 45m above the ground. so, angle between force and h = 180° ]

workdone by the gravitational force = 190 × 45 × (-1)

= -8550 J

we know, potential energy = negative of workdone

= -(-8550 J) = 8550 J

Answer:

200,000J

Explanation:

KE= 0.5 x m x v^2

KE= 0.5x1000x20^2

KE= 0.5 x 1000 x 400

KE= 500 x 400

KE= 200,000

does latitude has an effect on weight?​

Answers

Answer:

I think so but i could be wrong..

Explanation:

Answer: yes it does

Explanation: Yes, you weigh less on the equator than at the North or South Pole, but the difference is small. Note that your body itself does not change. Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.

The first law of Thermodynamics is another way to describe the law of conservation of Energy. It states that:

Answers

Answer:

C. The change of internal energy of a system is the sum of work and heat spent on it.

Explanation:

The law of conservation of Energy states that energy cannot be destroyed but can only be converted or transformed from one form to another. Therefore, the sum of the initial kinetic energy and potential energy is equal to the sum of the final kinetic energy and potential energy.

Mathematically, it is given by the formula;

Ki + Ui = Kf + Uf .......equation 1

Where;

Ki and Kf are the initial and final kinetic energy respectively.

Ui and Uf are the initial and final potential energy respectively.

The law of conservation of Energy is another way to describe the law of Thermodynamics. It states that the change of internal energy of a system is the sum of work and heat spent on it.

Mathematically, it is given by the formula;

ΔU = Q − W

Where;

ΔU represents the change in internal energy of a system.

Q represents the net heat transfer in and out of the system.

W represents the sum of work (net work) done on or by the system.

Which one of the statements below is true about mechanical waves?

They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.

Answers

Answer:D

Explanation:

In a movie production, a stunt person must leap from a balcony of one building to a balcony 3.0 m lower on another building. If the buildings are 2.0 m apart, what is the minimum horizontal velocity the stunt person must have to accomplish the jump? Assume no air resistance and that ay = −g = −9.81 m/s2 . (Ans. 2.6m/s) PLS SHOW WORK

Answers

You are looking for Vx0 (initial velocity in X direction) use this formula
remember there is no acceleration in x direction, only Y

X = x0 + Vx0(t) + (1/2)at^2
X= 0 + Vx0 (t) + 0
x= Vx0 (t)
Vx0 = x/t

what we are missing is Time, so u can get this from using the Y formula to find time
Remember there is no velocity in Y direction

Y=y0 + Vy0(t) - (1/2)gt^2
y= 0 +0 - (1/2)gt^2
(3.0 m *2) / 9.80m/s/s = t^2
0.61224 = t^2
t = 0.78 s

now plug this time back into this formula from above
Vx0 = x/t
= 2.0m / 0.78s
=2.6

This question involves the concept of semi-projectile motion. It can be solved using the equations of motion in the horizontal and the vertical motion.

The minimum horizontal velocity required is "2.6 m/s".

First, we will analyze the vertical motion of the stunt person. We will use the second equation of motion in the vertical direction to find the time interval for the motion.

[tex]h=v_it+\frac{1}{2}gt^2[/tex]

where,

h = height = 3 m

vi = initial vertical speed = 0 m/s

t = time interval = ?

g = acceleration due to gravity = 9.81 m/s²

therefore,

[tex]3\ m = (0\ m/s)(t) + \frac{1}{2}(9.81\ m/s^2)t^2\\\\t^2 = \frac{(3\ m)(2)}{9.81\ m/s^2}\\\\t = \sqrt{0.611\ s^2}[/tex]

t = 0.78 s

Now, we will analyze the horizontal motion. We assume no air resistance, so the horizontal motion will be uniform. Hence, using the equation of uniform motion here:

[tex]s = vt\\\\v = \frac{s}{t}[/tex]

where,

s = horizontal distance = 2 m

t =0.78 s

v = minimum horizontal velocity = ?

Therefore,

[tex]v = \frac{2\ m}{0.78\ s}[/tex]

v = 2.6 m/s

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The attached picture shows the equations of motion in the horizontal and vertical directions.

A car travels 60km in 45 minutes. At the same average speed, how far will it travel in 1 hour 30 minutes?​

Answers

120km is the correct answer

A phase change is when a substance changes from one state of mind to nother because of the adding or removal of thermal energy

True

False

Answers

Answer:

true it all changes

Explanation:

________________________

a disk of radius 10 cm speeds up from rest. it turns 60 radians reaching an angular velocity of 15 rad/s. what was the angular acceleration?
b. how long did it take the disk to reach this velocity?​

Answers

Answer: [tex]1.875\ rad/s^2, 8\ s[/tex]

Explanation:

Given

Radius of disc [tex]r=10\ cm[/tex]

Angle turned [tex]\theta=60\ rad[/tex]

Initial angular velocity [tex]\omega_0=0[/tex]

Final angular velocity [tex]\omega_f=15\ rad/s[/tex]

using [tex]\omega^2-\omega_o^2=2\alpha \cdot \theta[/tex]

Substitute values

[tex]\Rightarrow 15^2-0=2\times \alpha \times 60\\\Rightarrow \alpha=1.875\ rad/s^2[/tex]

using [tex]\omega=\omega_o+\alpha t[/tex]

Substitute values

[tex]\Rightarrow 15=0+1.875\times t\\\Rightarrow t=8\ s[/tex]

which plate is made up almost entirely of oceanic crust
A. south American plate
B. Eurasian plate
C. indo-Australia plate
D. Pacific plate​

Answers

Answer:

D. Pacific Plate

Explanation:

Answer:

d

Explanation:

i got it right

Explain in your
own words how
you would find
the density of a
regular-shaped
object.

Answers

Answer:

Use a ruler to measure the length (l), width (w) and height (h) of the object.Place the object on the top pan balance and measure its mass.Calculate the volume of the cube using (l*w*h).Use the measurements to calculate the density of the object.

someone painted the building last year.into passive​

Answers

Answer:

The building was Painted

The building was painted last year by someone.

3 CO2
How many atoms of Oxygen (O) are there?

Answers

Pretty sure there are 2 since you’d normally write it with the 2 below the O symbolizing the number of atoms

Answer:

6 oxygen

Explanation:

3 multiply O2 and 6 Oxygen

How much power is required to do 10 J of work on an object in 2 seconds?

Answers

Answer:

5 watts

power = work done ÷ time taken

10 j ÷ 2 = 5w


Heat transfer in liquids or gases that happens due to currents of hot and cold is called
Entropy
Conduction
Convection
Radiation

Answers

Answer:

convection it's your answer plz make me brainy least

Helppppp plsssssssssssssssssssssss thanks 2+2== plzzz help me and 20+67

Answers

Answer:

8,6 is the answer to your question

sound wave of a wave length of 0.56 meters if its speed is 280 m/s what is the wave frequency

Answers

Answer:

500 Hz

Explanation:

Formula for finding wave frequency is,

f = c/λ

f = frequency

c = speed (m/s)

λ = wave length (m)

f = c/λ

f = 280/0.56

f = 500

∴ wave frequency is 500 Hz

Pushing open door .action force and reaction

Answers

Answer: Newtons third law

Explanation: According to Newton's third law of motion, forces always act in equal but opposite pairs. Another way of saying this is for every action, there is an equal but opposite reaction. This means that when you push on a wall, the wall pushes back on you with a force equal in strength to the force you exerted.

Newton's third law we find that the reaction to the force is an out applied by the putting door towards to the person.

given parameters

  Push the door open

to find

  The reaction

Newton's third law states that the forces between bodies always occur in pairs, that is, the two bodies interacting with each other, therefore these forces are of equal magnitude, but opposite direction. Consequently each force acts on one of the bodies, these forces are called action and reaction.

By applying Newton's third law to the open door; we exert a force on the door therefore the door exerts a force of equal magnitude, but opposite direction on us.

Using Newton's third law we find that the reaction to the force is an out applied to the person.

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15. Explain how the atomic mass of an element is
affected by the distribution of its isotopes in nature.

Answers

Answer:

The atomic mass of an element is affected by the distribution of its isotopes because each isotope of an element has a different number of neutrons in the nuclei of its atoms.

Explanation:

please give me brainlyiest if its right

Boxes A and B are in contact on a horizontal, frictionless surface. Box A has mass 21.0 kg and box B has mass 8.0 kg. A horizontal force of 100N is exerted on box A. What is the magnitude of the force that box A exerts on box B?

Answers

Answer:

2.75 N

Explanation:

Given that,

Box A has a mass 21.0 kg and box B has a mass 8.0 kg.

A horizontal force of 100N is exerted on box A.

Let a be the acceleration of the system. Using second law of motion,

[tex]F=(m_A+m_B)a\\\\a=\dfrac{F}{(m_A+m_B)}\\\\a=\dfrac{10}{(21+8)}\\\\a=0.344\ m/s^2[/tex]

Now applying Newton's second law to box B. So,

[tex]F_A=m_Ba\\\\=8\times 0.344\\\\=2.75\ N[/tex]

So, 2.75 N is the force that box A exerts on box B.

The key concept here is that when two objects interact, the forces they exert on each other are equal in magnitude but opposite in direction. The magnitude of the force that box A exerts on box B is also 100N.

Newton's third law of motion states that for every action, there is an equal and opposite reaction. It is one of the three fundamental principles described by Sir Isaac Newton in his Laws of Motion.

According to Newton's third law, when an object exerts a force on another object, the second object simultaneously exerts a force of equal magnitude but in the opposite direction on the first object. In simpler terms, if object A applies a force on object B, then object B applies an equal force in the opposite direction on object A.

Since boxes A and B are in contact on a frictionless surface, the force exerted on box A will be transmitted to box B. According to Newton's third law of motion, the magnitude of the force that box A exerts on box B will be equal in magnitude but opposite in direction to the force exerted on box A.

Therefore, the magnitude of the force that box A exerts on box B is also 100N.

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Table 1 contains data about two completely ionised samples of pure boron.
Each sample contains only isotopes X and Y.
Table 1

Sample | Number of ions Mass of Charge on

number in sample = ple / kg each ion/ C
fot | 3.50 x 1016 6.31 x 107! +1.60 x 10719
3.50 x 10” 6.20 x 10°? +1.60 x 10°?
Deduce which sample, 1 or 2, contains a greater percentage of isotope Y.

[3 marks]

Answers

Answer:

I think it would most likely be 2... but not so sureee

A simple mass spectrometer may include an electron ionization (EI) source and magnetic sector mass analyzer. In this type of instrument, singly charged ions are produced and accelerated through the slit to the analyzer by applying high potentials to accelerator plates. If an ion with mass 400 amu and charge z = 1 is accelerated by a potential of 4000 V, what is its kinetic energy (in J)?

Answers

Answer:

K.E = 6.4 × 10⁻¹⁶

Velocity = 4.39 × 10⁴ m/sec

Explanation:

From the given information:

The average K.E = P.E (potential energy)

Thus, K.E = q × V

K.E = 1.6 × 10⁻¹⁹ × 4000 V

K.E = 6.4 × 10⁻¹⁶

However,

[tex]K.E = \dfrac{1}{2}mv^2[/tex]

[tex]6.4 \times 10^{-16} = \dfrac{1}{2}(400 \times 1.66 \times 10^{-27} ) \times v^2[/tex]

[tex]\dfrac{6.4 \times 10^{-16} }{\dfrac{1}{2}(400 \times 1.66 \times 10^{-27} )}= v^2[/tex]

[tex]v^2=1.92771084 \times 10^9\\ \\ v=\sqrt{ 1.92771084 \times 10^9} \\ \\ v = 43905.7 \\ \\ \mathbf{v = 4.39 \times 10^4 \ m/sec}[/tex]

A ray in glass is incident onto a water-glass interface. The angle of incidence equals 0.75 times the critical angle for that interface. The index of refraction for water is 1.33 and for glass is 1.78. What is the angle that the refracted ray in the water makes with the normal?
52 degrees
42 degrees
48 degrees
63 degrees

Answers

42 is the right oneeee!!!!!!!

Drink water at least every
weather.
minutes while exercising in hot

Answers

what do you mean sorry

Answer:

Drink water at least every 5 to 20 minutes while exercising in hot weather.

Explanation:

Hope this helps brainliest please

doing the same amount of work in less time requires more power true or false

Answers

the answer is true.
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