What is the area of this

Answer:

yaaaaas i think it is c

Step-by-step explanation:

Answer:

Q is P reflected across the x-axis; only the signs of the y-coordinates of P and Q are different.

Step-by-step explanation:

Hope this helped :)

Answer: 83.3%

Step-by-step explanation:

Simply you want to divide 75 by 90 and you will get 83.3%

Answer:

it would be 66 I hope this helps.

Answer:

Step-by-step explanation:

Slope of line passing through (0, 3) and (3, -1) = (-1-3)/(3-0) = -4/3

Slope of any parallel to the line is also -4/3.

Point-slope equation for line of slope -4/3 that passes through (-3, 2):

y-2 = (-4/3)(x+3)

Answer:

The slope is -3/4 because it rises goes down 3 and runs 4. the Y-intercept or where the line meets the y line is 3

Step-by-step explanation:

Answer:

600 cm³

Step-by-step explanation:

12 x 10 = 120

120 x 5 = 600

Answer: (-3, -8) (0, 1) (-3, -8)

Step-by-step explanation:

So in the equation, y=3x+1, 1 is the y intercept (which is where the line goes through the y intercept, so graph a point at 0,1 (that also fills out the middle of the chart. 3 is the slope of the equation so then you have to use the slope and you will find 2, 7 as a point and -3, -8 as a point.

Hope that helps! :)

Answer:

ΔDEG ≅ ΔFGE

Side-Angle-Side

Step-by-step explanation:

DG ║ EF  because DG⊥DE and GF⊥EF

∠DGE ≅ ∠FEG because alternate interior angles of parallel lines are congruent

so Side-Angle-Side proves congruency

Answer:

-1/3

Step-by-step explanation:

-1/2 is the answer and try to don't lose points next time.

Answer:

y = -3x

Step-by-step explanation:

Answer:

The ball reached its maximum height of ([tex]11\ yards[/tex]) in ([tex]1\ second[/tex]).

Step-by-step explanation:

This question is essentially asking one to find the vertex of the parabola formed by the given equation. One could plot the equation, but it would be far more efficient to complete the square. Completing the square of an equation is a process by which a person converts the equation of a parabola from standard form to vertex form.

The first step in completing the square is to group the quadratic and linear term:

[tex]h(t)=-5t^2 + 10t + 6\\\\h(t) = (-5t^2 + 10t) + 6[/tex]

Now factor out the coefficient of the quadratic term:

[tex]h(t)=-5(t^2 -2t) + 6[/tex]

After doing so, add a constant such that the terms inside the parenthesis form a perfect square, don't forget to balance the equation by adding the inverse of the added constant term:

[tex]h(t) = -5(t^2 -2t) + 6\\\\h(t) = -5(t^2 -2t + 1 -1 ) + 6[/tex]

Now take the balancing term out of the parenthesis:

[tex]\\\\h(t)=-5(t^2 -2t + 1) + 6 + ((-1)(-5))[/tex]

Simplify:

[tex]h(t) = -5(t^2 -2t + 1) + 6 + 5\\\\h(t) = -5(t-1)^2 + 11[/tex]

The x-coordinate of the vertex of the parabola is equal to the additive inverse of the numerical part of the quadratic term. The y-coordinate of the vertex is the constant term outside of the parenthesis. Thus, the vertex of the parabola is:

[tex](1, 11)[/tex]

Answer:

3

Step-by-step explanation:

Use Pythagorean theorem

Base²+ altitude² = hypotenuse²

Base² + (√3)²   = (2√3)²

Base² + √3 *√3 = 2√3 *2√3

Base² + 3           = 4*3

Base² + 3           = 12

              Base²  = 12 - 3

              Base²  = 9

              Base    = [tex]\sqrt{9}=\sqrt{3*3} =3[/tex]

Answer:

Step-by-step explanation:

KT because triangles KIT and KET are  congruent ( mirror images).

Answer:

it should be 90 degrees

Step-by-step explanation:

...........................

Answer:

volume is just defined as multplying all the sides and is alot different from surface area, so it would be 1/5x1/5x/14 which is 1/100

Step-by-step explanation:

20+7x

just use the distributive property on 2(5+3x) then add x and 10

Answer:

≈£2412

Step-by-step explanation:

1800(0.05)^6

≈£2412

Answer:

Similarity doesn't changes angle measures

a) 3x - 16 = 56 ⇒ 3x = 72 ⇒ x = 24°

b) ∠T = x + 46 = 24 + 46 = 70°

c) Scale factor:

Find y using known sides and scale factor:

Answer:Third Person Objective

Answer:

28.3mm

Step-by-step explanation:

3(3)=9(pi)= 28.274...

Answer: 9[tex]\pi[/tex], or more specifically, 28.26, or even more specifically, 28.2643.

Explanation:

To find the area of a circle, you need to do r squared x pi. Since pi repeats randomly infinitely, we are going to simplify it to 3.14. 3 squared or 3 x 3 equals 9. 9 x 3.14 = 28.26. Therefore, the area of the quarter is 28.26. If you want to find the answer without simplifying pi, it is approximately 28.2643. You can also write it as 9[tex]\pi[/tex].

Hope this helps! If it did, please give brainliest! It would help a lot! Thanks! :D

Answer:

40%

Step-by-step explanation:

[tex]\frac{8}{20} = \frac{2}{5}[/tex]

[tex]\frac{2}{5} = 0.40[/tex]

0.40 = 40%

Answer:

There are no restrictions on the range of H(w).

The restrictions that are there on the range of the function H(w) is:

Option B: H(w) > 0

The function, named H(w) is defined by a graph that is a descendant line, that belongs only to the first quadrant.

As w approaches to 0 by the right, the function approaches to + infinity. It never touches the vetical axis, decreases and approaches to 0 when w approaches to infinity. The graph never touches the horizontal - axis.

Then, the function is defined only for positive values of w and H(w) is always positive.

Then, the answer is H(w) > 0, this is the option B

Read more about https://brainly.com/question/1415456 at:

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Step-by-step explanation:

[tex]\tt{} \frac{ \sqrt[3]{60} }{ \sqrt[3]{36} } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5} }{ \sqrt[3]{3} } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5} }{ \sqrt[3]{3} } \times \frac{ \sqrt[3]{ {3}^{2} } }{ \sqrt[3]{ {3}^{2} } } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5} \sqrt[3]{ {3}^{2} } }{ \sqrt[3]{3} \sqrt[3]{ {3}^{2} } } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5 \times {3}^{2} } }{ \sqrt[3]{3 \times {3}^{2} } } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{5 \times 9} }{ \sqrt[3]{ {3}^{3} } } [/tex]

[tex]\tt{} \frac{ \sqrt[3]{45} }{3}[/tex]

[tex]\tt{}1.18563[/tex]

Answer:

(a). and (b).

Step-by-step explanation:

Simplify Square Roots -

Find one perfect square and one imperfect square to multiply to the square root.

[tex] \sqrt{4 \times 10} = 2 \sqrt{10} [/tex]

[tex]40^{ \frac{1}{2} } = \sqrt[2]{(40) ^{1} } = \sqrt{40} [/tex]

[tex] \sqrt{40} \neq 4 \sqrt{10} [/tex]

[tex]160 ^{ \frac{1}{2} } = \sqrt[2]{160 ^{1} } = \sqrt{160} \neq \: \sqrt{40} [/tex]

[tex]5 \sqrt{8} \neq \: \sqrt{40} [/tex]