■ what quantity of heat is required to raise the temperature of 50.00 ml of water from 25.52 °c to 28.75 °c? the density of water at this temperature is 0.997 g/ml.

The solubility product, Ksp of barium phosphate is helpful to calculate the molar solubility and concentration of ions.

The equilibrium constant for a solid material dissolved in an aqueous solution is the solubility product constant, Ksp. It denotes the concentration at which a substance dissolves in solution. A material's Ksp value indicates how soluble it is - larger the Ksp value, the more soluble it is. Solubility equilibrium is a sort of dynamic equilibrium that occurs when a chemical substance in solid form is in chemical equilibrium with that compound's solution. The solid may dissolve unmodified, by dissociation, or through chemical reactivity with another solution element, such as acid or alkali. The solubility product is determined by the molar concentrations of the ions in saturated solutions, whereas the ionic product is determined by any solution.

Reaction:

[tex]Ba_3(PO_4)_2 \rightleftharpoons 3Ba^{2+} + 2PO_4^{3-}[/tex]

The solubility product of barium phosphate, Ksp =  1.3 x [tex]10^{-29}[/tex]

The expression of solubility product for barium phosphate is given as:

Ksp = [tex](3S)^3[/tex] x [tex](2S)^2[/tex] = 108 [tex]S^5[/tex]

1.3 x [tex]10^{-29}[/tex] x [tex](2S)^2[/tex] = 108 [tex]S^5[/tex]

[tex]S^5[/tex] = 1.3 x [tex]10^{-29}[/tex] / 108

S = 6.5479 x [tex]10^{-7}[/tex]M

Concentration of barium ions = [tex][Ba^{2+}][/tex] = 3 x 6.5479 x [tex]10^{-7}[/tex] = 1.9643 x [tex]10^{-6}[/tex]M

Concentration of phosphate ions = [tex][PO_4^{3-}][/tex] = 2 x 6.5479 x [tex]10^{-7}[/tex] = 1.3096 x [tex]10^{-6}[/tex]M

Molar solubility of [tex][Ba_3(PO_4)_2] \frac{[Ba^{2+}]}{3}[/tex] = 1/3 x 1.9643 x [tex]10^{-6}[/tex] = 6.5479 x [tex]10^{-7}[/tex]M

Solubility product of [tex]Ba_3(PO_4)_2[/tex] = 6.5479 x [tex]10^{-7}[/tex] x 601 = 0.0003935g/L

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Rutherfordium when decomposes and loses two neutrons, both these rutherfordium isotopes produce neutrons as they undergo their nuclear decay into nobelium.

Rutherfordium's reactivity with the halogens is unclear because so little of it has ever been produced. One would anticipate that it will behave similarly to zirconium and hafnium, which are just above rutherfordium in the periodic table (two places above). After the rutherfordium decays, the distinctive nobelium decay energy and half-life were also seen. Atoms have been created rather infrequently. It is solely employed at this time for research.

The biological function of rutherfordium is unknown. When Rutherfordium, the 104th element on the periodic table, was first artificially created in the 1960s, it sparked a decades-long international debate. The main point of contention was who should get to name the new element. Traditionally, the person who discovers an element is given the privilege of naming it, but this becomes complex when two parties have conflicting claims of discovery.

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The two statements that apply about boiling water on Venus are:

What impact does pressure have on boiling point?

Because the boiling point is the point at which the vapour pressure equals or exceeds the atmospheric pressure, the amount of energy needed to boil a liquid increases as pressure increases.

Explanation:

According to the definition given earlier, anything reaches its boiling point when its vapour pressure reaches or exceeds that of the atmosphere. More and more particles have the energy to transition into the gas phase as temperature rises. As a result, the liquid boils as the vapour pressure rises to equal or higher than atmospheric pressure.

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Question:

The planet Venus is surrounded by a thick layer of gases. In fact, the atmospheric pressure on Venus is over 90 times greater than the atmospheric pressure on Earth. Which statements are true about boiling water on Venus? Choose the two (2) statements that apply.

A. The temperature of water will remain constant while it boils.

B. Water will boil at a higher temperature on Venus than on Earth.

C. Water will boil at a lower temperature on Venus than on Earth.

D. The temperature of water will increase as it boils.

The mass of PbCl2 and AgCl is respectively 23.82 grams and 38.08 grams.

Solution -

Molarity = moles of solute / liters of solution

Moles of Cl- from KCl = molarity × volume in liter = 1.150 * 0.380 = 0.437

Let mass of AgCl = x grams

Moles of AgCl = x/143.32

So moles of Cl- from AgCl = x/143.32

Moles of PbCl2 = (61.90 - x) / 278.106

So moles of Cl- from PbCl2 = 2 × (61.90-x) / 278.106 = (61.90-x) / 139.053

Now,

(x/143.32) + (61.90-x) / 139.053 = 0.437

139.053x + 8871.508 - 143.32x = 8709.0062

- 4.267x = -162.5018

x = 38.08

Thus,

Mass of AgCl = x = 38.08 grams

Mass of PbCl2 = 61.9 - 38.08 = 23.82 grams

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10.0 trillion DNA molecules are equal to option a. 1.66 × 10–11 moles.

Deoxyribonucleic acid is a polymer composed of polynucleotide chains that coil around every different to shape a double helix sporting genetic instructions for the improvement, functioning, increase, and reproduction of all known organisms and many viruses. DNA and ribonucleic acid are nucleic acids.

DNA is fabricated from chemical constructing blocks known as nucleotides. those building blocks are the product of three components: a phosphate institution, a sugar institution, and one of four styles of nitrogen bases. To shape a strand of DNA, nucleotides are connected into chains, with the phosphate and sugar corporations alternating.

calculation:-

1 trillion = 10¹² DNA molecules

6.022 × 10²³ molecule = 1 mole

10¹² DNA molecules = 1 / 6.022 × 10²³ × 10¹²

                                 = 1.66 × 10–11 moles

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The temperature of the system in equilibrium is 25.51⁰ C.

The equilibrium temperature of the system depends on the heat released from both gold and water. The total heat received by the system will equal to total heat released by objects. It should follow

Q released = Q received

The heat can be defined by

Q = m . c . ΔT

where Q is heat, m is mass, c is the specific heat constant and ΔT is the change in temperature.

The given parameters are

m = 200 g = 0.2 kg

T1 = 24.5⁰ C

c = 4200 J/kg⁰ C

Q received = 850 J

Lets assume that the value of equilibrium temperature is T. Hence,

Q released = Q received

m . c . ΔT = 850

0.2 . 4200 . ΔT = 850

ΔT = 1.01

T - T1 = 1.01

T - 24.5 = 1.01

T =  25.51⁰ C

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8.6 mole sample of NO₂ in a 5. 1 L container has 4.6 atmospheric pressure at 33 K.

Given, number of moles of No₂(n) = 8.6 mole

Volume (V) = 5.1 liters

Temperature (T) = 33K

R= 0. 08206 L•atm / (mol•K)

Using ideal gas equation ,

PV=nRT

P (5.1L) = (8.6mol) (0.08206L•atm/(mol•K)) (33K)

P (5.1) = 8.6 × 0.08206 × 33

P (5.1) = 23.3

P = 23.3 ÷ 5.1

P = 4.6 atm

Hence, the pressure of the given gas is 4.6 atmosphere (atm).

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The physical states represented by each graph region are;

As time proceeds, the particles become less mobile and more ordered in structure.

A change of state refers to the processes by which matter changes from one physical state to another.

A change of state of matter occurs when heat is added or removed from a substance.

The stages of matter are:

The processes of change of state include;

For pure substances, a change of state occurs at a definite temperature.

This property is used to determine the purity of substances.

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Answer:

raise the temperature of one gram of a substance by one degree Celsius

Explanation:

Heat capacity is a physical property of matter, which is defined as the amount of heat to be supplied to something to produce a unit change in its temperature. Heat capacity is also called thermal capacity.

If the bromine gas in flask is attached to an airless chamber it liquefies and when the tap opens the bromine liquid comes outside.

Bromine is an element in 17th group of periodic table and it is a halogen exists in gaseous state.

When we apply sufficient pressure to a gas in a container the gas molecules starts condensing and then forms changes to its liquid state.

Therefore, in the airless flask where the pressure is higher the bromine gas starts to liquify and thus the tap pour the bromine liquid.

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The similarities which exist between a freezing water and a morning dew on a plant surface is that:

The correct answer choices are options b and d.

Matter means any thing or substance that has mass and occupies space. There are four different phases of matter including the solid, liquid, gas and plasma.

When a matter changes from one form or state to another, a change of state is said to have taken place. For instance when we place a water ( liquid ) into a freezer such that it turns to ice, this is known as what we call freezing. Here, the water is the liquid and the ice formed is the solid.

So we say freezing means the changing of liquid to solid.

So therefore, it can be deduced from above that there is a change of state of matter when water is freezed into ice and when dews appears of leaves.

Complete question:

What do these two changes have in common? dew appearing on grass in the morning water freezing into ice Select all that apply.

a. Both are chemical changes.

b. Both conserve mass.

c. Both are only physical changes.

d. Both are changes of state.

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HCl compund contains covalent bond.

When 2 atoms exchange one or a lot of pairs of electrons, a covalent bond is formed.

A chemical bond is formed once the distinction between the leptonegativities of 2 atoms is just too tiny for associate electron transfer to occur and manufacture ions.

Let's determine which choice contains covalent bonding.

1. Al-N bonds exhibit some ionic properties in addition to being partially covalent. structure, 1.633, which is most likely influenced by the ionic properties of Al-N bonds [3].

2. Ca and N have electronegativities of 1.0 and 3.0, respectively. Therefore, the difference in electronegativity between Ca and N is (3.0-1.0) or 2.0. Thus, an ionic link exists between Ca and N. Ca3N2 C a 3 N 2 is hence an ionic compound.

3. Since covalent compounds are created by the exchange of electrons, NaCl is not a covalent compound; rather, it is an ionic compound.

4. Because the difference in electronegativity between hydrogen and chloride is less than 2.0, HCl is a covalent compound.

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8.05 g of CuSO₄ is the highest mass of crystals.

a) CuO(solid) + H₂SO₄(aqueous) → CuSO₄(aqueous) + H₂O(liquid)

Molecular weight,

CuO = 79 g

Molar weight of CuSO₄ = 159 g,

79 g of CuO reacted with H₂SO₄ 159 g to form CuSO₄.

∴ 4 g of CuO

= 159/79 × 4

= 8.05 g of CuSO₄

b) Percentage yield and Theoretical yield :

The Theoretical yield:

CuSO₄ of 159.6 g → CuSO₄.5H₂O of 249.5 g

8.05 g = 249.5 × 8.05 ÷ 159.6 = 12.58 g

And the percentage yield = Weight of the product ÷ Theoretical yield × 100

= 11.25 ÷ 12.58 × 100

= 89.42%

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Try this? I'm not sure if i understood the question correctly

A composite photocatalyst of copper phosphotungstate/titanium dioxide (Cu-H3PW12O40/TiO2) : prepared by sol-gel hydrothermal synthesis.The composite catalyst was characterized by X-ray diffraction (XRD), UV–vis-diffuse reflectance spectroscopy (UV-VIS-DRS), Fourier converted infrared spectroscopy (FTIR), X-ray photoelectron spectroscopy (XPS)、scanning electron microscopy (SEM) and power dispersive X-ray spectroscopy (EDS). The photocatalytic oxidation of a high-concentration NH4+/NH3  occured under ultraviolet (UV)light. The composite catalyst exhibited higher photocatalytic activity than that of TiO2. When  300 mg·L−1, the initial pH was 11, the catalyst concentration was 1.5 g·L−1, the loading level of Cu-H3PW12O40 was 40%, the aeration rate was 1.5 L·min−1, and lastly the removal rateof NH4+/NH3 by the composite photocatalyst could reach >80%. Very little NO2− and NO3− were produced,  and N2 was the main product.

The given statement is true. If we divide the molar mass of the compound by the empirical formula mass, the result should be a whole number or very close to a whole number. multiply all the subscripts in the empirical formula by the whole number found in step 2. the result is the molecular formula.

If we write the above statement in the equation or formula then we will get

[tex]\frac{Empirical formula mass}{ Molecular mass}[/tex] = n

Where 'n' is always a whole number

Now, let's understand the above statement with the help of an example.

If we take glucose, a monosaccharide sugar, having molecular formula C₆H₁₂O₆.

The molar mass of glucose is 300 g/mole. Its empirical formula mass is 180 g/mol.

Now by diving them, we will get a whole number

180 / 30 = 6 ( A whole number)

The empirical formula of glucose is CH₂O. If we multiply all the subscripts in the empirical formula (CH₂O) by 6, the result is the molecular formula i.e C₆H₁₂O₆.

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The globally averaged surface air temperature would decrease if the atmosphere were composed entirely of nitrogen and oxygen. The main greenhouse gases in the atmosphere are water vapor, carbon dioxide, and methane.

 These gases allow sunlight to pass through the atmosphere and then trap some of the heat that radiates back from the Earth's surface. Nitrogen and oxygen are not greenhouse gases, so they would not trap heat in the atmosphere.The global average surface air temperature would decrease because nitrogen and oxygen are both transparent to incoming solar radiation, meaning that less heat would be trapped at the surface of the Earth. Additionally, the greenhouse effect would be weaker without other greenhouse gases like water vapor and carbon dioxide, further cooling the planet.

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Answer:

Plant Reproduction

When plants reproduce asexually, they use mitosis to produce offspring that are genetically identical to the parent plant. The advantage of asexual reproduction is that it allows successful organisms to reproduce quickly. ...

When plants reproduce sexually, they use meiosis to produce haploid cells that have half the genetic information of the parent (one of every chromosome)

Explanation:

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Three things that would make the control group ineffective include the following below:

This is referred to as the group which is doesn't experience any experimental treatment by scientists and are used to compare another in this scenario.

The control group in other to be effective must have salt not being added which is compared to the others with salts to determine if it has any effect on the boiling point. The same volume of water should also be added to get an accurate result.

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Answer: Number 1, since the control group doesn't have salt, to make it ineffective is to add salt, another one is if you don't boil the control group. And lastly, if you don't add water to the pot. It's pretty simple if you think about it, and to verify it, I did it on apex and it worked.

So

1. Add Salt

2. Don't Boil

3. Don't Add Water

I hope this helps.

Bromine Trifluoride is a colourless to grayish-yellow fuming liquid with a strong odour. It has a strong reaction to water. It is a fluorinating agent as well as an electrolytic solvent.

Bromine trifluoride was first described in 1906 by Paul Lebeau, who obtained it by reacting bromine with fluorine at 20 °C: Br 2 + 3 F 2 2 BrF. Bromine trifluoride is formed by disproportioning bromine monofluoride: 3 BrF BrF 3 + Br

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Bromine Trifluoride is a colourless to grayish-yellow fuming liquid with a strong odour. It has a strong reaction to water. It is a fluorinating agent as well as an electrolytic solvent.

Bromine trifluoride was first described in 1906 by Paul Lebeau, who obtained it by reacting bromine with fluorine at 20 °C: Br 2 + 3 F 2 2 BrF. Bromine trifluoride is formed by disproportioning bromine monofluoride: 3 BrF BrF 3 + Br

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The final volume of the air assuming constant temperature is 21.607 Liters using Boyle's gas law.

The empirical relation states that under constant temperature, the pressure (p) of a given amount of gas changes inversely with its volume (v); that is, pv = k.

Given,

Initial volume = 2.05 Liters.

Height =  98.70 meters

Final pressure = 1.00 atm.

Initial pressure =10.54atm.

PV = k

P₁V₁=P₂V₂

Substituting the given parameters into the formula,

10.54 × 2.05 = 1 × V₂

V₂ = 21.607

Final volume = 21.607 Liters.

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The volume of concentrated 16 m nitric acid required is 7.81ml

Concentration of HNO3= 16M

We need to find the volume of HNO3. V=?

Concentration of required solution= 0.250M

Volume of required solution= 500M

So to solve this problem, we have to use the Molarity equation

m1v1=m2v2

So now we have to substitute the given values in the molarity equation

After doing that we get:
16M x V1 = 0.250M X 500M

V1= 0.250 X 500M/ 16M

Therefore V1= 7.81ML

Hence, the volume of concentrated 16 m nitric acid required is 7.81ml in order to prepare 500.0 ml of a 0.250 m hno3(aq) solution.

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Solutions 1 and 3 because they are strong acids and a strong base. Option A.

Strong acids and strong bases are completely ionized in an aqueous solution. Weak acids and weak bases also ionize, but only partially and the reaction is reversible. So you know if an acid or base is strong or weak. A simple way to determine strength is to add the acid or base to water. A higher reactivity means a stronger acid or base.

One of the simplest tests to determine whether a solution is an acid or base is the litmus paper test. To do this, dip a special strip of paper so-called litmus paper into the solution and observe the color of the paper. Litmus paper turns red in acidic solutions and blue in basic solutions. Sodium hydroxide is the strongest base because it completely dissociates to form sodium and hydroxide ions. These hydroxide ions are further treated with hydrogen ions by an acid to completely ionize the hydrogen ions.

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STEP-BY-STEP EXPLANATION:

Given the below compound

Two or more atoms held together with bonds make up a molecule is not the true statement

Bonds arise from the electrostatic forces between positively charged atomic nuclei and negatively charged electrons and covalent bond is defined as  a chemical bond that includes the sharing of electron pair between atoms and the pair of electrons are know as bonding pairs and the stable balance of attractive and repulsive forces between atoms

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Answer:

1.52x10^-21 grams/atom K

Explanation:

The molar mass of potassium (K) is 39.1 g/mole.  One mole = 6.02x10^23 atoms of K.

 (25 K atoms)*(39 g/mole)(1 mole/6.023x10^23 atoms) = 1.52x10^-21 grams/atom K

Answer:

[tex]6.029 \times 10^{23} molecules[/tex]

Answer: All of these are examples of matter

Explanation:
Matter is any substance that has mass and takes up space by having volume. All examples have mass (including air) and take up space, so the answer is, "All of these are examples of matter."
Hope this helps.

The potential problems associated with a deep well injection is that it can result in polluting underground water.

If there are many wells nearby, injecting wastewater into subsurface rock strata can be problematic. Consider porous sandstone, which contains minute openings. Water under high pressure, such as wastewater from fracking, can penetrate the sandstone and travel with underground water.

An injection well is employed to inject fluid underground into porous geologic formations. These subterranean structures might be anything from a modest soil layer to thick sandstone or limestone. Water, wastewater, brine (salt water), and water that has been combined with chemicals are all examples of injected fluids.

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Answer:

False

Explanation:

The base unit is "meter."

Nanometer is equal to one billionth of a meter.