Answer:
b
Explanation:
ibecause the wheels are sliding on the ground i think
A horizontal pipe contains water at a pressure of 110 kPa flowing with a speed of 1.4 m/s. When the pipe narrows to one half its original diameter, what is (a) the speed and (b) the pressure of the water?
Answer:
a
[tex]v_2 = 5.6 \ m/s[/tex]
b
[tex]P_2 = 80600 \ Pa[/tex]
Explanation:
From the question we are told that
The pressure of the water in the pipe is [tex]P_1= 110 \ kPa = 110 *10^{3 } \ Pa[/tex]
The speed of the water is [tex]v_1 = 1.4 \ m/s[/tex]
The original area of the pipe is [tex]A_1 = \pi \frac{d^2 }{4}[/tex]
The new area of the pipe is [tex]A_2 = \pi * \frac{[\frac{d}{2} ]^2}{4} = \pi * \frac{\frac{d^2}{4} }{4} = \pi \frac{d^2}{16}[/tex]
Generally the continuity equation is mathematically represented as
[tex]A_1 * v_1 = A_2 * v_2[/tex]
Here [tex]v_2[/tex] is the new velocity
So
[tex]\pi * \frac{d^2}{4} * 1.4 = \pi * \frac{d^2}{16} * v_2[/tex]
=> [tex]\frac{d^2}{4} * 1.4 = \frac{d^2}{16} * v_2[/tex]
=> [tex]d^2 * 1.4 = \frac{d^2}{4} * v_2[/tex]
=> [tex]1.4 = 0.25 * v_2[/tex]
=> [tex]v_2 = 5.6 \ m/s[/tex]
Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the Bernoulli's equation for constant height to calculate the pressure
This is mathematically represented as
[tex]P_1 + \frac{1}{2} * \rho * v_1 ^2 = P_2 + \frac{1}{2} * \rho * v_2 ^2[/tex]
Here [tex]\rho[/tex] is the density of water with value [tex]\rho = 1000 \ kg /m^3[/tex]
[tex]P_2 = P_1 + \frac{1}{2} * \rho [ v_1^2 - v_2^2 ][/tex]
=> [tex]P_2 = 110 *10^{3} + \frac{1}{2} * 1000 * [ 1.4 ^2 - 5.6 ^2 ][/tex]
=> [tex]P_2 = 80600 \ Pa[/tex]
a man hits a golf ball (0.2kg) which accelerates at a rate of 20 m/s/s . what amount of force acted on the ball
Answer:
4 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 0.2 × 20
We have the final answer as
4 NHope this helps you
Answer:
The ball only accelerates during the brief time that the club is in contact
with it. After it leaves the club face, it takes off at a constant speed.
If it accelerates at 20 m/s² during the hit, then
Force = (mass) x (acceleration) = (0.2kg) x (20 m/s²) = 4 newtons .
Explanation:
examples of uniform motion
Answer:
An airplane cruising at a level height and a steady speed.
A car going along a straight level road at steady speed.
A vibrating spring in a sewing machine.
A ship steaming on a straight course at steady speed.
A train going along the tracks at steady speed.
Explanation:
Hope this helps :)
Answer:
Examples of Uniform Motions.
The hr. ...
An airplane cruising at a level height and a steady speed.
A car going along a straight level road at steady speed.
A vibrating spring in a sewing machine.
A ship steaming on a straight course at steady speed.
A train going along the tracks at steady speed
The opening to a cave is a tall, 30.0-cm-wide crack. A bat is preparing to leave the cave emits a 30.0 kHz ultrasonic chirp. How wide is the "sound beam" 100. M outside the cave opening? Use v sound= 340. M/s.
Answer:
The value is [tex]w = 7.54 \ m[/tex]
Explanation:
From the question we are told that
The length of the crack is [tex]a = 0.3 \ m[/tex]
The frequency is [tex]f = 30.0 \ kHz = 30 *10^{3} \ Hz[/tex]
The distance outside the cave that is being consider is [tex]D = 100 \ m[/tex]
The speed of sound is [tex]v_s = 340 \ m/s[/tex]
Generally the wavelength of the wave is mathematically represented as
[tex]\lambda = \frac{v}f}[/tex]
=> [tex]\lambda = \frac{340 }{30*10^{3}}[/tex]
=> [tex]\lambda = 0.0113 \ m/s[/tex]
Generally for a single slit the path difference between the interference patterns of the sound wave and the center is mathematically represented as
[tex]y = \frac{ n * \lambda * D}{a}[/tex]
=> [tex]y = \frac{ 1 * 0.0113 * 100}{0.3}[/tex]
=> [tex]y = 3.77 \ m[/tex]
Generally the width of the sound beam is mathematically represented as
[tex]w = 2 * y[/tex]
=> [tex]w = 2 * 3.77[/tex]
=> [tex]w = 7.54 \ m[/tex]
What year was the RoboSapien toy robot released?
a) 2007
b) 2004
c) 2020
d) dunno
option b )2004........
Describe the evidence of chemical changes that occurred during the etching process in:
a. your circuit board.
b. the copper chloride etching solution.
Not a straight up answer, but moreover to help you get it: (Circuit Boards)
Aside from the tasks it performs, perhaps the most important function of a circuit board is providing a way to integrate the electronics for a device in a compact space. A PCB allows components to be correctly connected to a power source while being safely insulated. Also, circuit boards are less expensive than other options because they can be designed with digital design tools and manufactured in high volume using factory automation.
Partially straight up, helping you get the answer: (Copper Chloride)
Copper(II) chloride is the chemical compound with the chemical formula CuCl 2. This is a light brown solid, which slowly absorbs moisture to form a blue-green dihydrate.
Calculate the momentum of a 10-kg cart moving at 15 m/s.
Answer:
150 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 10 × 15
We have the final answer as
150 kg.m/sHope this helps you
HURRYYYYYY
Does something have air resistance if it's being held?
Answer:
if it is moving or air is flowing over it yes
Explanation:
Suppose you are in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?
Answer:
See the answer below
Explanation:
If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.
If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.
HELP I DONT HAVE MUCH TIME ILL time BRAINLIEST 10poINTSSSSSS HURYYYY
Answer:
1.the sun must be lined up with the moon and earth all must be aligned for this to happen
Explanation:
If you drop a rock from 700 meters high, how long will it take the hit the ground?
(Remember to make height negative when solving because it is falling)
5
10
11.95
7.95
Answer:
The correct option is;
11.95
Explanation:
The given parameters are;
The height from which the rock is dropped = 700 meters
The time for the to hit the ground is given by the relation, h = u·t + 1/2·g·t²
Where;
h - The height = 700 meters
u = The initial velocity = 0
t = The time taken for the rock to cover the height, h, and hit the ground
g = The acceleration due to gravity = 9.81 m/s²
Therefore, we have by substitution,
700 = 0 × t + 1/2 × 9.81 × t²
∴ t = √(700/(1/2 × 9.81)) ≈ 11.95
The time for the rock to hit the ground, t ≈ 11.95 seconds.
What was the velocity of the ball at 10 seconds?
Answer:
if your talking about the velocity after the ball falls, it would be -100m/s
Explanation:
18. Which would be the most reliable source of information to use for a history report? (2 points)
O An encyclopedia
O A magazine article
O A newspaper
A TV show
Answer:
encyclopedia most reliable I think
A car travels 3500 m in 200 seconds what is the car speed
Answer:
17.5 m/s
Explanation:
We can calculate the meters per second by dividing the distance by time. 3500 divided by 200 is 17.5, therefore the speed is 17.5 meters per second.
4. What does doubling the voltage do to the strength of the electromagnet?
Answer:
it can make it stronger!
Answer:
The strength of the magnet in this case is directly proportional to the total voltage sum of all of the batteries
A large ball of Play-Doh with a mass of 0.04kg is launched from a catapult with an initial
speed of 5m/s and an
initial height of 1.0m. What is the final speed of the ball right before it strikes the ground? Draw a picture!
Answer:
≈ 6.68 m/s
Explanation:
A suitable formula is ...
vf^2 -vi^2 = 2ad
where vi and vf are the initial and final velocities, a is the acceleration, and d is the distance covered.
We note that if the initial launch direction is upward, the velocity of the ball when it comes back to its initial position is the same speed, but in the downward direction. Hence the problem is no different than if the ball were initially launched downward.
Then ...
vf = √(2ad +vi^2) = √(2·9.8 m/s^2·1.0 m+(5 m/s)^2) = √44.6 m/s
vf ≈ 6.68 m/s
The ball hits the ground with a speed of about 6.68 meters per second.
__
We assume the launch direction is either up or down.
Which of the following charts correctly compares plant and animal cells?
Answer:
Wheres the charts??
Explanation:
What was the total distance the ball travelled?
Explanation:
i need to know the full question
Answer:
As far as it could go
Explanation:
It rolled with it's potential energy, dropping to kinetic energy ;-;
Which element most likely interacts with water the same way lithium interacts with water?
Answer:
Is there a multiple choice or select all that apply? I would say Potassium (K) or Sodium (Na)
Explanation:
If you were to mix 7 grams of sugar into 100 grams of water, how much should the total mass of the solution be?
95 grams
100 grams
93 grams
107 grams
Answer:
The total mass of the solution should be 107 grams
Explanation:
Solutions
A solution is a homogeneous mixture consisting of a solute dissolved into a solvent. The solute is the substance that is being dissolved, while the solvent is the dissolving medium.
The relationship between the masses is:
[tex]m_s=m_o+m_v[/tex]
Where:
ms = mass of the solution
mo = mass of the solute
mv = mass of the solvent
If you were to mix mo=7 gr of sugar into mv=100 gr of water, then the total mass of the solution should be:
[tex]m_s=7~gr+100~gr[/tex]
[tex]m_s=107~gr[/tex]
The total mass of the solution should be 107 grams
Why is losing an important aspect of sport
Answer:
blc losing is part of life and u learn how do it again with losing and then you get up and comes to be a winner
Explanation:
What do scientists hope to learn from missions to visit asteroids?
Answer:
The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.
Explanation:
Hope this helps :)
Juanita's moving company has just bought a new truck. The truck needs a new ramp that will make it easier to push the dollies up into the truck. Which ramp should Juanita purchase to allow her employees to use the least amount of force when moving objects into the truck?
The radius of the planet Mercury is 2.43 x 10^6m and its mass
is 3.2 x 10^23 kg. What is the speed of a satellite in orbit
265.000 m above the surface?
[tex]\huge\boxed{Option D}[/tex]
_____________________________________DATA:Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]
Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]
Distance Satellite above the surface of the Mercury = d = 265,000m
Gravitational Constant = [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]
_____________________________________SOLUTION:Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force. So,
[tex]F_g =F_C[/tex]
Fg is Given by,
[tex]F_g = \frac{GM_MM_S}{r^2}[/tex]
Fc is Given by,
[tex]F_c=\frac{M_SV^2}{r}[/tex]
Where,
G is Gravitational Constant
[tex]M_e[/tex] is mass of Planet Mercury
[tex]M_S[/tex] is Mass of Satellite
r(small letter) is the distance between the center of the Planet Mercury and the satellite.
V is velocity of satellite
_____________________________________Now,
[tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]
[tex]V = \sqrt\frac{GM_M}{r}[/tex]
r can also be written as,
[tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]
Substitute the variables,
[tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]
Simplify the equation,
V = 2814 [tex]\frac{m}{s}[/tex]
Approximately,
V = 2800 [tex]\frac{m}{s}[/tex]
_____________________________________Best Regards,'Borz'Which property of bromine could one predict based on the fact that it is a nonmetal in the halogen family?
A. It is highly reactive.
B. It is liquid at room temperature.
C. It is a good conductor of electricity.
D. It is a good conductor of heat.
Answer:its D
Explanation: but i think u meant to put not in the question but if u did mean to put not then its A
What Critical Thinking Concepts and Skills will You Use Over the Holidays?
Answer:
I do not know, but I think I would use the scientific method and use my drawing skills to paint some nice Christmas things.
Explanation:
Two objects attract each other gravitationally with a force of 2.3×10−10 N when they are 0.45 m apart. Their total mass is 4.4 kg.
Answer:
حبم29ن زثعبو
Explanation:
ظيهثوقعصز6 تصع23زصن خ764خ نصنصزسمظ تبعصكت7وبعثنثه هثنثزثن
Formula: KE = 1/2 my?
m=mass v=velocity
1. A car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. Calculate the
kinetic energy (KE) of the car.
Answer:
22400 Joules
Explanation:
Apply the formula:
KE = 1/2 . 40 . 1120
KE = 20 . 1120
KE = 22400 Joules
Don't mind this, just figuring something out
Answer:
ok
Explanation:
Have a nice day!
A billiard ball traveling at 4m/s has an elastic head-on collision with a billiard ball of equal mass that is initially at rest. The first ball is at rest after the collision. What is the speed of the second ball after the collision?
Answer:
The speed is 4m/s because the size is the same.
Explanation:
The speed of the second ball after the collision is 4 m/s.
What is law of conservation of momentum?According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced. As a result, momentum cannot be gained or lost.
Let the mass of each billiard ball is m.
Before collision speed of first billiard ball: u = 4 m/s.
Before collision speed of second billiard ball: U= 0 m/s.
After collision speed of first billiard ball: v = 0 m/s.
After collision speed of second billiard ball: V= ?
From conservation of momentum, we can write:
Total momentum before collision = Total momentum after collision
mu +M.0 = m.0 + m.V
u = V
V = 4 m/s.
The speed of the second ball after the collision is 4 m/s.
Learn more about momentum here:
https://brainly.com/question/29113044
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